Program only prints out second last letter. want the whole word backwards instead












0















import java.util.Scanner;
public class Project2 {

public static void main(String args) {
Scanner in = new Scanner(System.in);
String word;
String c;
int x, count, count1;
System.out.println("Please enter a word:");
word=in.nextLine();
x=word.length();
for(count=0;count<x;count++) {
count1=x;
count1--;
c=word.substring((count1)-1,count1);
System.out.println(c);
}
}
}


All this program does is print out the second to last character of the word that the user enters. I'm confused as to why it is doing this and want to know how to print out the whole word backwards. Someone help please.










share|improve this question

























  • When you need to traverse backward than traverse it backward.

    – jack jay
    Nov 14 '18 at 6:04











  • FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 14 '18 at 6:06
















0















import java.util.Scanner;
public class Project2 {

public static void main(String args) {
Scanner in = new Scanner(System.in);
String word;
String c;
int x, count, count1;
System.out.println("Please enter a word:");
word=in.nextLine();
x=word.length();
for(count=0;count<x;count++) {
count1=x;
count1--;
c=word.substring((count1)-1,count1);
System.out.println(c);
}
}
}


All this program does is print out the second to last character of the word that the user enters. I'm confused as to why it is doing this and want to know how to print out the whole word backwards. Someone help please.










share|improve this question

























  • When you need to traverse backward than traverse it backward.

    – jack jay
    Nov 14 '18 at 6:04











  • FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 14 '18 at 6:06














0












0








0


1






import java.util.Scanner;
public class Project2 {

public static void main(String args) {
Scanner in = new Scanner(System.in);
String word;
String c;
int x, count, count1;
System.out.println("Please enter a word:");
word=in.nextLine();
x=word.length();
for(count=0;count<x;count++) {
count1=x;
count1--;
c=word.substring((count1)-1,count1);
System.out.println(c);
}
}
}


All this program does is print out the second to last character of the word that the user enters. I'm confused as to why it is doing this and want to know how to print out the whole word backwards. Someone help please.










share|improve this question
















import java.util.Scanner;
public class Project2 {

public static void main(String args) {
Scanner in = new Scanner(System.in);
String word;
String c;
int x, count, count1;
System.out.println("Please enter a word:");
word=in.nextLine();
x=word.length();
for(count=0;count<x;count++) {
count1=x;
count1--;
c=word.substring((count1)-1,count1);
System.out.println(c);
}
}
}


All this program does is print out the second to last character of the word that the user enters. I'm confused as to why it is doing this and want to know how to print out the whole word backwards. Someone help please.







java substring






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 7:12









Andreas

1,89421018




1,89421018










asked Nov 14 '18 at 6:01









Shrey VarmaShrey Varma

1




1













  • When you need to traverse backward than traverse it backward.

    – jack jay
    Nov 14 '18 at 6:04











  • FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 14 '18 at 6:06



















  • When you need to traverse backward than traverse it backward.

    – jack jay
    Nov 14 '18 at 6:04











  • FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 14 '18 at 6:06

















When you need to traverse backward than traverse it backward.

– jack jay
Nov 14 '18 at 6:04





When you need to traverse backward than traverse it backward.

– jack jay
Nov 14 '18 at 6:04













FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 14 '18 at 6:06





FWIW - ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 14 '18 at 6:06












6 Answers
6






active

oldest

votes


















2














You don't need a loop to reverse a string.



Ref - StringBuilder#reverse



Scanner in = new Scanner(System.in);
System.out.println(new StringBuilder(in.nextLine()).reverse());


If you want to print characters in reverse, then forget the substring-ing.



String word = in.nextLine();
int x = word.length();
for(count = x - 1; count >= 0; count--) {
System.out.println(word.charAt(count));
}





share|improve this answer





















  • 1





    this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

    – Kartik
    Nov 14 '18 at 6:10











  • Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

    – cricket_007
    Nov 14 '18 at 6:11



















1














Take count1=x; assignment out of the loop. Also make count--; after printing the letter.






share|improve this answer
























  • But then what do i make the starting value for count1?

    – Shrey Varma
    Nov 14 '18 at 6:04











  • I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

    – cricket_007
    Nov 14 '18 at 6:08











  • It will print each letter of string in new line.

    – Jignesh M. Khatri
    Nov 14 '18 at 6:17



















1














You are correct up until x = word.length(). It is printing the second from last character because you keep setting the value of count1 to length of word and you substract it by 1. Therefore, it keeps referring to the second last character. To fix that, do the following instead:



count1=x;
for(count=0;count<x;count++) {
c=word.substring((count1)-1,count1);
System.out.println(c);
count1--;
}





share|improve this answer
























  • Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

    – Andreas
    Nov 14 '18 at 6:11



















1














Every time the loop is running, you are resetting the count1 value to x (count1=x). So c will always be the same value.
To make this work, try taking count1 = x out of the loop so that every time the loop is running, count1 value will be reduced as expected providing the required sub-string.






share|improve this answer































    1














    Into the loop for(count=0;count<x;count++)
    Every loop you did the same thing



    count1=x;
    count1--;
    c=word.substring((count1)-1,count1);
    System.out.println(c);


    This block has no relation with the loop!



    Thats why you are getting the second last character!



    To fix this:



    Solution 1: (Just reverse the String)



    word=in.nextLine();
    System.out.println(new StringBuilder(word).reverse());


    or Solution 2: (Using loop using your code)



    x=word.length();
    for(count= x-1; count >= 0; count--) {
    c = word.substring((count)-1, count);
    System.out.print(c);
    }





    share|improve this answer

































      1














      If at all you want to do it the hard way by traversing, do the following changes.



      for(count=x;count>=0;count--) {
      System.out.println(word.substring(count - 1,count));
      }


      Update: You can use charAt#String to easily get the character at some position.



      for(count=x-1;count>=0;count--) {
      System.out.println(word.charAt(count));
      }





      share|improve this answer


























      • substring(count - 1,count) is the same effect as charAt(count)

        – cricket_007
        Nov 14 '18 at 6:14











      • @cricket_007 yeah. Thanks for mentioning it.

        – jack jay
        Nov 14 '18 at 6:20











      Your Answer






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      6 Answers
      6






      active

      oldest

      votes








      6 Answers
      6






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      You don't need a loop to reverse a string.



      Ref - StringBuilder#reverse



      Scanner in = new Scanner(System.in);
      System.out.println(new StringBuilder(in.nextLine()).reverse());


      If you want to print characters in reverse, then forget the substring-ing.



      String word = in.nextLine();
      int x = word.length();
      for(count = x - 1; count >= 0; count--) {
      System.out.println(word.charAt(count));
      }





      share|improve this answer





















      • 1





        this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

        – Kartik
        Nov 14 '18 at 6:10











      • Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

        – cricket_007
        Nov 14 '18 at 6:11
















      2














      You don't need a loop to reverse a string.



      Ref - StringBuilder#reverse



      Scanner in = new Scanner(System.in);
      System.out.println(new StringBuilder(in.nextLine()).reverse());


      If you want to print characters in reverse, then forget the substring-ing.



      String word = in.nextLine();
      int x = word.length();
      for(count = x - 1; count >= 0; count--) {
      System.out.println(word.charAt(count));
      }





      share|improve this answer





















      • 1





        this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

        – Kartik
        Nov 14 '18 at 6:10











      • Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

        – cricket_007
        Nov 14 '18 at 6:11














      2












      2








      2







      You don't need a loop to reverse a string.



      Ref - StringBuilder#reverse



      Scanner in = new Scanner(System.in);
      System.out.println(new StringBuilder(in.nextLine()).reverse());


      If you want to print characters in reverse, then forget the substring-ing.



      String word = in.nextLine();
      int x = word.length();
      for(count = x - 1; count >= 0; count--) {
      System.out.println(word.charAt(count));
      }





      share|improve this answer















      You don't need a loop to reverse a string.



      Ref - StringBuilder#reverse



      Scanner in = new Scanner(System.in);
      System.out.println(new StringBuilder(in.nextLine()).reverse());


      If you want to print characters in reverse, then forget the substring-ing.



      String word = in.nextLine();
      int x = word.length();
      for(count = x - 1; count >= 0; count--) {
      System.out.println(word.charAt(count));
      }






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 14 '18 at 6:10

























      answered Nov 14 '18 at 6:04









      cricket_007cricket_007

      81.2k1142111




      81.2k1142111








      • 1





        this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

        – Kartik
        Nov 14 '18 at 6:10











      • Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

        – cricket_007
        Nov 14 '18 at 6:11














      • 1





        this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

        – Kartik
        Nov 14 '18 at 6:10











      • Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

        – cricket_007
        Nov 14 '18 at 6:11








      1




      1





      this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

      – Kartik
      Nov 14 '18 at 6:10





      this is not an answer to the question.. if an alternative was to be provided, we could direct the OP to Reverse a string in Java

      – Kartik
      Nov 14 '18 at 6:10













      Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

      – cricket_007
      Nov 14 '18 at 6:11





      Perhaps, but they did ask ultimately say want to know how to print out the whole word backwards, so your choice...

      – cricket_007
      Nov 14 '18 at 6:11













      1














      Take count1=x; assignment out of the loop. Also make count--; after printing the letter.






      share|improve this answer
























      • But then what do i make the starting value for count1?

        – Shrey Varma
        Nov 14 '18 at 6:04











      • I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

        – cricket_007
        Nov 14 '18 at 6:08











      • It will print each letter of string in new line.

        – Jignesh M. Khatri
        Nov 14 '18 at 6:17
















      1














      Take count1=x; assignment out of the loop. Also make count--; after printing the letter.






      share|improve this answer
























      • But then what do i make the starting value for count1?

        – Shrey Varma
        Nov 14 '18 at 6:04











      • I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

        – cricket_007
        Nov 14 '18 at 6:08











      • It will print each letter of string in new line.

        – Jignesh M. Khatri
        Nov 14 '18 at 6:17














      1












      1








      1







      Take count1=x; assignment out of the loop. Also make count--; after printing the letter.






      share|improve this answer













      Take count1=x; assignment out of the loop. Also make count--; after printing the letter.







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 14 '18 at 6:02









      Jignesh M. KhatriJignesh M. Khatri

      501411




      501411













      • But then what do i make the starting value for count1?

        – Shrey Varma
        Nov 14 '18 at 6:04











      • I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

        – cricket_007
        Nov 14 '18 at 6:08











      • It will print each letter of string in new line.

        – Jignesh M. Khatri
        Nov 14 '18 at 6:17



















      • But then what do i make the starting value for count1?

        – Shrey Varma
        Nov 14 '18 at 6:04











      • I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

        – cricket_007
        Nov 14 '18 at 6:08











      • It will print each letter of string in new line.

        – Jignesh M. Khatri
        Nov 14 '18 at 6:17

















      But then what do i make the starting value for count1?

      – Shrey Varma
      Nov 14 '18 at 6:04





      But then what do i make the starting value for count1?

      – Shrey Varma
      Nov 14 '18 at 6:04













      I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

      – cricket_007
      Nov 14 '18 at 6:08





      I doubt this is the only fix because c is getting reassigned within the loop over and over again, never making a reversed string

      – cricket_007
      Nov 14 '18 at 6:08













      It will print each letter of string in new line.

      – Jignesh M. Khatri
      Nov 14 '18 at 6:17





      It will print each letter of string in new line.

      – Jignesh M. Khatri
      Nov 14 '18 at 6:17











      1














      You are correct up until x = word.length(). It is printing the second from last character because you keep setting the value of count1 to length of word and you substract it by 1. Therefore, it keeps referring to the second last character. To fix that, do the following instead:



      count1=x;
      for(count=0;count<x;count++) {
      c=word.substring((count1)-1,count1);
      System.out.println(c);
      count1--;
      }





      share|improve this answer
























      • Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

        – Andreas
        Nov 14 '18 at 6:11
















      1














      You are correct up until x = word.length(). It is printing the second from last character because you keep setting the value of count1 to length of word and you substract it by 1. Therefore, it keeps referring to the second last character. To fix that, do the following instead:



      count1=x;
      for(count=0;count<x;count++) {
      c=word.substring((count1)-1,count1);
      System.out.println(c);
      count1--;
      }





      share|improve this answer
























      • Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

        – Andreas
        Nov 14 '18 at 6:11














      1












      1








      1







      You are correct up until x = word.length(). It is printing the second from last character because you keep setting the value of count1 to length of word and you substract it by 1. Therefore, it keeps referring to the second last character. To fix that, do the following instead:



      count1=x;
      for(count=0;count<x;count++) {
      c=word.substring((count1)-1,count1);
      System.out.println(c);
      count1--;
      }





      share|improve this answer













      You are correct up until x = word.length(). It is printing the second from last character because you keep setting the value of count1 to length of word and you substract it by 1. Therefore, it keeps referring to the second last character. To fix that, do the following instead:



      count1=x;
      for(count=0;count<x;count++) {
      c=word.substring((count1)-1,count1);
      System.out.println(c);
      count1--;
      }






      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 14 '18 at 6:06









      AndreasAndreas

      1,89421018




      1,89421018













      • Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

        – Andreas
        Nov 14 '18 at 6:11



















      • Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

        – Andreas
        Nov 14 '18 at 6:11

















      Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

      – Andreas
      Nov 14 '18 at 6:11





      Please remember to accept the answer that suits your question the most, so StackOverflow can archive it properly.

      – Andreas
      Nov 14 '18 at 6:11











      1














      Every time the loop is running, you are resetting the count1 value to x (count1=x). So c will always be the same value.
      To make this work, try taking count1 = x out of the loop so that every time the loop is running, count1 value will be reduced as expected providing the required sub-string.






      share|improve this answer




























        1














        Every time the loop is running, you are resetting the count1 value to x (count1=x). So c will always be the same value.
        To make this work, try taking count1 = x out of the loop so that every time the loop is running, count1 value will be reduced as expected providing the required sub-string.






        share|improve this answer


























          1












          1








          1







          Every time the loop is running, you are resetting the count1 value to x (count1=x). So c will always be the same value.
          To make this work, try taking count1 = x out of the loop so that every time the loop is running, count1 value will be reduced as expected providing the required sub-string.






          share|improve this answer













          Every time the loop is running, you are resetting the count1 value to x (count1=x). So c will always be the same value.
          To make this work, try taking count1 = x out of the loop so that every time the loop is running, count1 value will be reduced as expected providing the required sub-string.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 6:08









          RakihthaRRRakihthaRR

          185111




          185111























              1














              Into the loop for(count=0;count<x;count++)
              Every loop you did the same thing



              count1=x;
              count1--;
              c=word.substring((count1)-1,count1);
              System.out.println(c);


              This block has no relation with the loop!



              Thats why you are getting the second last character!



              To fix this:



              Solution 1: (Just reverse the String)



              word=in.nextLine();
              System.out.println(new StringBuilder(word).reverse());


              or Solution 2: (Using loop using your code)



              x=word.length();
              for(count= x-1; count >= 0; count--) {
              c = word.substring((count)-1, count);
              System.out.print(c);
              }





              share|improve this answer






























                1














                Into the loop for(count=0;count<x;count++)
                Every loop you did the same thing



                count1=x;
                count1--;
                c=word.substring((count1)-1,count1);
                System.out.println(c);


                This block has no relation with the loop!



                Thats why you are getting the second last character!



                To fix this:



                Solution 1: (Just reverse the String)



                word=in.nextLine();
                System.out.println(new StringBuilder(word).reverse());


                or Solution 2: (Using loop using your code)



                x=word.length();
                for(count= x-1; count >= 0; count--) {
                c = word.substring((count)-1, count);
                System.out.print(c);
                }





                share|improve this answer




























                  1












                  1








                  1







                  Into the loop for(count=0;count<x;count++)
                  Every loop you did the same thing



                  count1=x;
                  count1--;
                  c=word.substring((count1)-1,count1);
                  System.out.println(c);


                  This block has no relation with the loop!



                  Thats why you are getting the second last character!



                  To fix this:



                  Solution 1: (Just reverse the String)



                  word=in.nextLine();
                  System.out.println(new StringBuilder(word).reverse());


                  or Solution 2: (Using loop using your code)



                  x=word.length();
                  for(count= x-1; count >= 0; count--) {
                  c = word.substring((count)-1, count);
                  System.out.print(c);
                  }





                  share|improve this answer















                  Into the loop for(count=0;count<x;count++)
                  Every loop you did the same thing



                  count1=x;
                  count1--;
                  c=word.substring((count1)-1,count1);
                  System.out.println(c);


                  This block has no relation with the loop!



                  Thats why you are getting the second last character!



                  To fix this:



                  Solution 1: (Just reverse the String)



                  word=in.nextLine();
                  System.out.println(new StringBuilder(word).reverse());


                  or Solution 2: (Using loop using your code)



                  x=word.length();
                  for(count= x-1; count >= 0; count--) {
                  c = word.substring((count)-1, count);
                  System.out.print(c);
                  }






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 14 '18 at 6:18

























                  answered Nov 14 '18 at 6:12









                  ZicoZico

                  1,74411620




                  1,74411620























                      1














                      If at all you want to do it the hard way by traversing, do the following changes.



                      for(count=x;count>=0;count--) {
                      System.out.println(word.substring(count - 1,count));
                      }


                      Update: You can use charAt#String to easily get the character at some position.



                      for(count=x-1;count>=0;count--) {
                      System.out.println(word.charAt(count));
                      }





                      share|improve this answer


























                      • substring(count - 1,count) is the same effect as charAt(count)

                        – cricket_007
                        Nov 14 '18 at 6:14











                      • @cricket_007 yeah. Thanks for mentioning it.

                        – jack jay
                        Nov 14 '18 at 6:20
















                      1














                      If at all you want to do it the hard way by traversing, do the following changes.



                      for(count=x;count>=0;count--) {
                      System.out.println(word.substring(count - 1,count));
                      }


                      Update: You can use charAt#String to easily get the character at some position.



                      for(count=x-1;count>=0;count--) {
                      System.out.println(word.charAt(count));
                      }





                      share|improve this answer


























                      • substring(count - 1,count) is the same effect as charAt(count)

                        – cricket_007
                        Nov 14 '18 at 6:14











                      • @cricket_007 yeah. Thanks for mentioning it.

                        – jack jay
                        Nov 14 '18 at 6:20














                      1












                      1








                      1







                      If at all you want to do it the hard way by traversing, do the following changes.



                      for(count=x;count>=0;count--) {
                      System.out.println(word.substring(count - 1,count));
                      }


                      Update: You can use charAt#String to easily get the character at some position.



                      for(count=x-1;count>=0;count--) {
                      System.out.println(word.charAt(count));
                      }





                      share|improve this answer















                      If at all you want to do it the hard way by traversing, do the following changes.



                      for(count=x;count>=0;count--) {
                      System.out.println(word.substring(count - 1,count));
                      }


                      Update: You can use charAt#String to easily get the character at some position.



                      for(count=x-1;count>=0;count--) {
                      System.out.println(word.charAt(count));
                      }






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Nov 14 '18 at 6:21

























                      answered Nov 14 '18 at 6:06









                      jack jayjack jay

                      2,2121824




                      2,2121824













                      • substring(count - 1,count) is the same effect as charAt(count)

                        – cricket_007
                        Nov 14 '18 at 6:14











                      • @cricket_007 yeah. Thanks for mentioning it.

                        – jack jay
                        Nov 14 '18 at 6:20



















                      • substring(count - 1,count) is the same effect as charAt(count)

                        – cricket_007
                        Nov 14 '18 at 6:14











                      • @cricket_007 yeah. Thanks for mentioning it.

                        – jack jay
                        Nov 14 '18 at 6:20

















                      substring(count - 1,count) is the same effect as charAt(count)

                      – cricket_007
                      Nov 14 '18 at 6:14





                      substring(count - 1,count) is the same effect as charAt(count)

                      – cricket_007
                      Nov 14 '18 at 6:14













                      @cricket_007 yeah. Thanks for mentioning it.

                      – jack jay
                      Nov 14 '18 at 6:20





                      @cricket_007 yeah. Thanks for mentioning it.

                      – jack jay
                      Nov 14 '18 at 6:20


















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