Regex: Matching any character (a-z and 0-9), but not $ in order to upgrade to PHP 7.2 [duplicate]











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  • Fix unquoted PHP array keys

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  • How to fix associative array keys that lack single quotation marks in multiple files

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Upgrading some really old PHP code and need to find all occurrences of array access without quotation mars (" and '). Should match [abc] but not ["abc"] or ['abc']. My regex works, but it also matches the $ character(like [$abc]), which i don't want.



Here is my full regex: [[^"'][A-Za-z0-9]+][^"'] https://regex101.com/r/uJM6DQ/1



How can I make it stop matching the $ character? Why does it match the $ character even if I never ask regex to match it?










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Nov 11 at 13:15


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.











  • 1




    Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
    – The fourth bird
    Nov 11 at 12:28










  • Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
    – Jan Greger Hemb
    Nov 11 at 12:32








  • 2




    "even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
    – trincot
    Nov 11 at 12:32








  • 1




    Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
    – The fourth bird
    Nov 11 at 12:34








  • 1




    Ah, now I understand it. Thanks for the help!
    – Jan Greger Hemb
    Nov 11 at 12:36















up vote
-1
down vote

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This question already has an answer here:




  • Fix unquoted PHP array keys

    1 answer



  • How to fix associative array keys that lack single quotation marks in multiple files

    4 answers




Upgrading some really old PHP code and need to find all occurrences of array access without quotation mars (" and '). Should match [abc] but not ["abc"] or ['abc']. My regex works, but it also matches the $ character(like [$abc]), which i don't want.



Here is my full regex: [[^"'][A-Za-z0-9]+][^"'] https://regex101.com/r/uJM6DQ/1



How can I make it stop matching the $ character? Why does it match the $ character even if I never ask regex to match it?










share|improve this question













marked as duplicate by mario php
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Nov 11 at 13:15


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.











  • 1




    Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
    – The fourth bird
    Nov 11 at 12:28










  • Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
    – Jan Greger Hemb
    Nov 11 at 12:32








  • 2




    "even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
    – trincot
    Nov 11 at 12:32








  • 1




    Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
    – The fourth bird
    Nov 11 at 12:34








  • 1




    Ah, now I understand it. Thanks for the help!
    – Jan Greger Hemb
    Nov 11 at 12:36













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite












This question already has an answer here:




  • Fix unquoted PHP array keys

    1 answer



  • How to fix associative array keys that lack single quotation marks in multiple files

    4 answers




Upgrading some really old PHP code and need to find all occurrences of array access without quotation mars (" and '). Should match [abc] but not ["abc"] or ['abc']. My regex works, but it also matches the $ character(like [$abc]), which i don't want.



Here is my full regex: [[^"'][A-Za-z0-9]+][^"'] https://regex101.com/r/uJM6DQ/1



How can I make it stop matching the $ character? Why does it match the $ character even if I never ask regex to match it?










share|improve this question














This question already has an answer here:




  • Fix unquoted PHP array keys

    1 answer



  • How to fix associative array keys that lack single quotation marks in multiple files

    4 answers




Upgrading some really old PHP code and need to find all occurrences of array access without quotation mars (" and '). Should match [abc] but not ["abc"] or ['abc']. My regex works, but it also matches the $ character(like [$abc]), which i don't want.



Here is my full regex: [[^"'][A-Za-z0-9]+][^"'] https://regex101.com/r/uJM6DQ/1



How can I make it stop matching the $ character? Why does it match the $ character even if I never ask regex to match it?





This question already has an answer here:




  • Fix unquoted PHP array keys

    1 answer



  • How to fix associative array keys that lack single quotation marks in multiple files

    4 answers








php regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 11 at 12:27









Jan Greger Hemb

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156




marked as duplicate by mario php
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Nov 11 at 13:15


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by mario php
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Nov 11 at 13:15


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.










  • 1




    Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
    – The fourth bird
    Nov 11 at 12:28










  • Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
    – Jan Greger Hemb
    Nov 11 at 12:32








  • 2




    "even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
    – trincot
    Nov 11 at 12:32








  • 1




    Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
    – The fourth bird
    Nov 11 at 12:34








  • 1




    Ah, now I understand it. Thanks for the help!
    – Jan Greger Hemb
    Nov 11 at 12:36














  • 1




    Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
    – The fourth bird
    Nov 11 at 12:28










  • Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
    – Jan Greger Hemb
    Nov 11 at 12:32








  • 2




    "even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
    – trincot
    Nov 11 at 12:32








  • 1




    Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
    – The fourth bird
    Nov 11 at 12:34








  • 1




    Ah, now I understand it. Thanks for the help!
    – Jan Greger Hemb
    Nov 11 at 12:36








1




1




Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
– The fourth bird
Nov 11 at 12:28




Perhaps add it to the first negated character class [[^$"'][A-Za-z0-9]+][^"']
– The fourth bird
Nov 11 at 12:28












Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
– Jan Greger Hemb
Nov 11 at 12:32






Haha, good point, that solves the problem. Thanks! But do you know why it matches the $ in the first place?
– Jan Greger Hemb
Nov 11 at 12:32






2




2




"even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
– trincot
Nov 11 at 12:32






"even if I never ask regex to match it": You do ask to match it with the negative class: [^"']. You'll agree that $ complies with that (among many other characters)
– trincot
Nov 11 at 12:32






1




1




Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
– The fourth bird
Nov 11 at 12:34






Because you use a negated character class [^"']. The negated character class matches any character that is not in the character class.
– The fourth bird
Nov 11 at 12:34






1




1




Ah, now I understand it. Thanks for the help!
– Jan Greger Hemb
Nov 11 at 12:36




Ah, now I understand it. Thanks for the help!
– Jan Greger Hemb
Nov 11 at 12:36

















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