mysql query when you have coma seperated string both sides











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-3
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hello I have this problem where I have a list of ids like



ID= 1,2,3,4,5


and the field in the database has values like



3,4,56,34,1,2,3 // field name can be users


and now I want to select all the tables in the database which has any of the values in ID



I tried this with



 FIND_IN_SET


but it's not working properly



    FIND_IN_SET (users, $ID)


can anyone help me with this, please??










share|improve this question
























  • Redesign you DB
    – Jens
    Nov 12 at 7:57










  • Please your query here which you tried?
    – Gufran Hasan
    Nov 12 at 8:00










  • Do you want to select Tables or Rows??
    – Mᴏʀᴀᴅɴᴇᴊᴀᴅ
    Nov 12 at 8:00










  • You might want to use the IN operator.
    – Jean-Marc Zimmer
    Nov 12 at 8:01






  • 1




    Possible duplicate of MySql: FIND_IN_SET does not work properly
    – Gufran Hasan
    Nov 12 at 8:02















up vote
-3
down vote

favorite












hello I have this problem where I have a list of ids like



ID= 1,2,3,4,5


and the field in the database has values like



3,4,56,34,1,2,3 // field name can be users


and now I want to select all the tables in the database which has any of the values in ID



I tried this with



 FIND_IN_SET


but it's not working properly



    FIND_IN_SET (users, $ID)


can anyone help me with this, please??










share|improve this question
























  • Redesign you DB
    – Jens
    Nov 12 at 7:57










  • Please your query here which you tried?
    – Gufran Hasan
    Nov 12 at 8:00










  • Do you want to select Tables or Rows??
    – Mᴏʀᴀᴅɴᴇᴊᴀᴅ
    Nov 12 at 8:00










  • You might want to use the IN operator.
    – Jean-Marc Zimmer
    Nov 12 at 8:01






  • 1




    Possible duplicate of MySql: FIND_IN_SET does not work properly
    – Gufran Hasan
    Nov 12 at 8:02













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











hello I have this problem where I have a list of ids like



ID= 1,2,3,4,5


and the field in the database has values like



3,4,56,34,1,2,3 // field name can be users


and now I want to select all the tables in the database which has any of the values in ID



I tried this with



 FIND_IN_SET


but it's not working properly



    FIND_IN_SET (users, $ID)


can anyone help me with this, please??










share|improve this question















hello I have this problem where I have a list of ids like



ID= 1,2,3,4,5


and the field in the database has values like



3,4,56,34,1,2,3 // field name can be users


and now I want to select all the tables in the database which has any of the values in ID



I tried this with



 FIND_IN_SET


but it's not working properly



    FIND_IN_SET (users, $ID)


can anyone help me with this, please??







php mysql mysqli






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 7:58









Gufran Hasan

3,41641326




3,41641326










asked Nov 12 at 7:55









Amani

279




279












  • Redesign you DB
    – Jens
    Nov 12 at 7:57










  • Please your query here which you tried?
    – Gufran Hasan
    Nov 12 at 8:00










  • Do you want to select Tables or Rows??
    – Mᴏʀᴀᴅɴᴇᴊᴀᴅ
    Nov 12 at 8:00










  • You might want to use the IN operator.
    – Jean-Marc Zimmer
    Nov 12 at 8:01






  • 1




    Possible duplicate of MySql: FIND_IN_SET does not work properly
    – Gufran Hasan
    Nov 12 at 8:02


















  • Redesign you DB
    – Jens
    Nov 12 at 7:57










  • Please your query here which you tried?
    – Gufran Hasan
    Nov 12 at 8:00










  • Do you want to select Tables or Rows??
    – Mᴏʀᴀᴅɴᴇᴊᴀᴅ
    Nov 12 at 8:00










  • You might want to use the IN operator.
    – Jean-Marc Zimmer
    Nov 12 at 8:01






  • 1




    Possible duplicate of MySql: FIND_IN_SET does not work properly
    – Gufran Hasan
    Nov 12 at 8:02
















Redesign you DB
– Jens
Nov 12 at 7:57




Redesign you DB
– Jens
Nov 12 at 7:57












Please your query here which you tried?
– Gufran Hasan
Nov 12 at 8:00




Please your query here which you tried?
– Gufran Hasan
Nov 12 at 8:00












Do you want to select Tables or Rows??
– Mᴏʀᴀᴅɴᴇᴊᴀᴅ
Nov 12 at 8:00




Do you want to select Tables or Rows??
– Mᴏʀᴀᴅɴᴇᴊᴀᴅ
Nov 12 at 8:00












You might want to use the IN operator.
– Jean-Marc Zimmer
Nov 12 at 8:01




You might want to use the IN operator.
– Jean-Marc Zimmer
Nov 12 at 8:01




1




1




Possible duplicate of MySql: FIND_IN_SET does not work properly
– Gufran Hasan
Nov 12 at 8:02




Possible duplicate of MySql: FIND_IN_SET does not work properly
– Gufran Hasan
Nov 12 at 8:02












2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










like this?



SELECT * FROM `tableName` WHERE CONCAT(",", `users`, ",") REGEXP ",(1|2|3|4|5),"





share|improve this answer





















  • This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
    – Amani
    Nov 12 at 9:35










  • you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
    – suresh bambhaniya
    Nov 12 at 9:56




















up vote
1
down vote













This should work :



$ID = "(1, 2, 3, 4, 5)";
$q = "SELECT * FROM `users` WHERE `ID` IN " . $ID;
//Execute $q here





share|improve this answer





















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    like this?



    SELECT * FROM `tableName` WHERE CONCAT(",", `users`, ",") REGEXP ",(1|2|3|4|5),"





    share|improve this answer





















    • This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
      – Amani
      Nov 12 at 9:35










    • you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
      – suresh bambhaniya
      Nov 12 at 9:56

















    up vote
    1
    down vote



    accepted










    like this?



    SELECT * FROM `tableName` WHERE CONCAT(",", `users`, ",") REGEXP ",(1|2|3|4|5),"





    share|improve this answer





















    • This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
      – Amani
      Nov 12 at 9:35










    • you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
      – suresh bambhaniya
      Nov 12 at 9:56















    up vote
    1
    down vote



    accepted







    up vote
    1
    down vote



    accepted






    like this?



    SELECT * FROM `tableName` WHERE CONCAT(",", `users`, ",") REGEXP ",(1|2|3|4|5),"





    share|improve this answer












    like this?



    SELECT * FROM `tableName` WHERE CONCAT(",", `users`, ",") REGEXP ",(1|2|3|4|5),"






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 12 at 8:10









    suresh bambhaniya

    865113




    865113












    • This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
      – Amani
      Nov 12 at 9:35










    • you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
      – suresh bambhaniya
      Nov 12 at 9:56




















    • This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
      – Amani
      Nov 12 at 9:35










    • you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
      – suresh bambhaniya
      Nov 12 at 9:56


















    This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
    – Amani
    Nov 12 at 9:35




    This is actually working, but i want to get results only if all the values of ID matches with users . i tried using & insted of | but dosent works
    – Amani
    Nov 12 at 9:35












    you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
    – suresh bambhaniya
    Nov 12 at 9:56






    you can store users in ascending order(1,2,3,4,34,56) and then use SELECT * FROM tableName WHERE users REGEXP "1,2,3,4,5"
    – suresh bambhaniya
    Nov 12 at 9:56














    up vote
    1
    down vote













    This should work :



    $ID = "(1, 2, 3, 4, 5)";
    $q = "SELECT * FROM `users` WHERE `ID` IN " . $ID;
    //Execute $q here





    share|improve this answer

























      up vote
      1
      down vote













      This should work :



      $ID = "(1, 2, 3, 4, 5)";
      $q = "SELECT * FROM `users` WHERE `ID` IN " . $ID;
      //Execute $q here





      share|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        This should work :



        $ID = "(1, 2, 3, 4, 5)";
        $q = "SELECT * FROM `users` WHERE `ID` IN " . $ID;
        //Execute $q here





        share|improve this answer












        This should work :



        $ID = "(1, 2, 3, 4, 5)";
        $q = "SELECT * FROM `users` WHERE `ID` IN " . $ID;
        //Execute $q here






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 8:05









        Jean-Marc Zimmer

        36914




        36914






























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