how to print a list containing the separate sums of lists
I'm trying to gain the sum of a list of lists where the output would be [6,2,10] for the defined lists below.
data = [[1,2,3], [2], [1, 2, 3, 4]]
output =
total = 0
for row in data:
for val in row[0:len(row)]:
total += val
output.append(total)
print(output)
However, the results of this program is [6, 8, 18].
Any help would be appreciated.
python list loops iteration
edited Nov 12 at 15:11
Austin
9,3273828
asked Nov 12 at 15:04
hh_vv
81
add a comment |
I'm trying to gain the sum of a list of lists where the output would be [6,2,10] for the defined lists below.
data = [[1,2,3], [2], [1, 2, 3, 4]]
output =
total = 0
for row in data:
for val in row[0:len(row)]:
total += val
output.append(total)
print(output)
However, the results of this program is [6, 8, 18].
Any help would be appreciated.
python list loops iteration
edited Nov 12 at 15:11
Austin
9,3273828
asked Nov 12 at 15:04
hh_vv
81
add a comment |
I'm trying to gain the sum of a list of lists where the output would be [6,2,10] for the defined lists below.
data = [[1,2,3], [2], [1, 2, 3, 4]]
output =
total = 0
for row in data:
for val in row[0:len(row)]:
total += val
output.append(total)
print(output)
However, the results of this program is [6, 8, 18].
Any help would be appreciated.
python list loops iteration
edited Nov 12 at 15:11
Austin
9,3273828
asked Nov 12 at 15:04
hh_vv
81
I'm trying to gain the sum of a list of lists where the output would be [6,2,10] for the defined lists below.
data = [[1,2,3], [2], [1, 2, 3, 4]]
output =
total = 0
for row in data:
for val in row[0:len(row)]:
total += val
output.append(total)
print(output)
However, the results of this program is [6, 8, 18].
Any help would be appreciated.
python list loops iteration
python list loops iteration
edited Nov 12 at 15:11
Austin
9,3273828
asked Nov 12 at 15:04
hh_vv
81
edited Nov 12 at 15:11
Austin
9,3273828
asked Nov 12 at 15:04
hh_vv
81
edited Nov 12 at 15:11
Austin
9,3273828
edited Nov 12 at 15:11
Austin
9,3273828
edited Nov 12 at 15:11
Austin
9,3273828
9,3273828
asked Nov 12 at 15:04
hh_vv
81
asked Nov 12 at 15:04
hh_vv
81
asked Nov 12 at 15:04
hh_vv
81
81
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Use a list comprehension.
Each element in list is iterable, this fact makes sum the best option for this task.
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> [sum(d) for d in data]
[6, 2, 10]
Now, if you want to know what was your problem...
Place the accumulator after the data loop, and feed the list after every row loop:
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> output =
>>> for row in data:
... total = 0
... for val in row[0:len(row)]:
... total += val
... output.append(total)
...
>>> output
[6, 2, 10]
answered Nov 12 at 15:06
klashxx
10.1k12338
add a comment |
Use map():
data = [[1,2,3], [2], [1, 2, 3, 4]]
print(list(map(sum, data)))
# [6, 2, 10]
Or list-comprehension:
data = [[1,2,3], [2], [1, 2, 3, 4]]
print([sum(x) for x in data])
# [6, 2, 10]
answered Nov 12 at 15:09
Austin
9,3273828
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use a list comprehension.
Each element in list is iterable, this fact makes sum the best option for this task.
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> [sum(d) for d in data]
[6, 2, 10]
Now, if you want to know what was your problem...
Place the accumulator after the data loop, and feed the list after every row loop:
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> output =
>>> for row in data:
... total = 0
... for val in row[0:len(row)]:
... total += val
... output.append(total)
...
>>> output
[6, 2, 10]
answered Nov 12 at 15:06
klashxx
10.1k12338
add a comment |
Use a list comprehension.
Each element in list is iterable, this fact makes sum the best option for this task.
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> [sum(d) for d in data]
[6, 2, 10]
Now, if you want to know what was your problem...
Place the accumulator after the data loop, and feed the list after every row loop:
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> output =
>>> for row in data:
... total = 0
... for val in row[0:len(row)]:
... total += val
... output.append(total)
...
>>> output
[6, 2, 10]
answered Nov 12 at 15:06
klashxx
10.1k12338
add a comment |
Use a list comprehension.
Each element in list is iterable, this fact makes sum the best option for this task.
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> [sum(d) for d in data]
[6, 2, 10]
Now, if you want to know what was your problem...
Place the accumulator after the data loop, and feed the list after every row loop:
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> output =
>>> for row in data:
... total = 0
... for val in row[0:len(row)]:
... total += val
... output.append(total)
...
>>> output
[6, 2, 10]
answered Nov 12 at 15:06
klashxx
10.1k12338
Use a list comprehension.
Each element in list is iterable, this fact makes sum the best option for this task.
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> [sum(d) for d in data]
[6, 2, 10]
Now, if you want to know what was your problem...
Place the accumulator after the data loop, and feed the list after every row loop:
>>> data = [[1,2,3], [2], [1, 2, 3, 4]]
>>> output =
>>> for row in data:
... total = 0
... for val in row[0:len(row)]:
... total += val
... output.append(total)
...
>>> output
[6, 2, 10]
answered Nov 12 at 15:06
klashxx
10.1k12338
edited Nov 12 at 15:22
answered Nov 12 at 15:06
klashxx
10.1k12338
answered Nov 12 at 15:06
klashxx
10.1k12338
answered Nov 12 at 15:06
klashxx
10.1k12338
10.1k12338
add a comment |
add a comment |
Use map():
data = [[1,2,3], [2], [1, 2, 3, 4]]
print(list(map(sum, data)))
# [6, 2, 10]
Or list-comprehension:
data = [[1,2,3], [2], [1, 2, 3, 4]]
print([sum(x) for x in data])
# [6, 2, 10]
answered Nov 12 at 15:09
Austin
9,3273828
add a comment |
Use map():
data = [[1,2,3], [2], [1, 2, 3, 4]]
print(list(map(sum, data)))
# [6, 2, 10]
Or list-comprehension:
data = [[1,2,3], [2], [1, 2, 3, 4]]
print([sum(x) for x in data])
# [6, 2, 10]
answered Nov 12 at 15:09
Austin
9,3273828
add a comment |
Use map():
data = [[1,2,3], [2], [1, 2, 3, 4]]
print(list(map(sum, data)))
# [6, 2, 10]
Or list-comprehension:
data = [[1,2,3], [2], [1, 2, 3, 4]]
print([sum(x) for x in data])
# [6, 2, 10]
answered Nov 12 at 15:09
Austin
9,3273828
Use map():
data = [[1,2,3], [2], [1, 2, 3, 4]]
print(list(map(sum, data)))
# [6, 2, 10]
Or list-comprehension:
data = [[1,2,3], [2], [1, 2, 3, 4]]
print([sum(x) for x in data])
# [6, 2, 10]
answered Nov 12 at 15:09
Austin
9,3273828
answered Nov 12 at 15:09
Austin
9,3273828
answered Nov 12 at 15:09
Austin
9,3273828
answered Nov 12 at 15:09
Austin
9,3273828
9,3273828
add a comment |
add a comment |
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