standard deviation calculation can't figure out what a variable is

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Hey guys i was given the code to calculate a standard deviation in java netbeans. However I don't really understand how standard deviation works. What does the s represent in the code.

public static <T extends Number> double calculateStandardDeviation(ArrayList<T> numberList) {

        if (numberList.size() <= 1) {

            throw new IllegalArgumentException("Size of array must be greater than 1");

        }



        int numberListSize = numberList.size();

        double s = 0;

        double listAverage = calculateAverage(numberList,true);



        for (int i = 0; i < numberListSize; i++) {

            double numberDouble = numberList.get(i).doubleValue();

            s += Math.pow(numberDouble - listAverage,2);

        }

        double standardDeviation = Math.sqrt(s / (numberListSize-1));

        return standardDeviation;

    }

Sorry if this problem is to simple for stack overflow.

asked Nov 10 at 19:12

Caleb

215

s is variance, sd = sqrt( s/ size - 1)
– The Scientific Method
Nov 10 at 19:16

thanks. I appreciate it
– Caleb
Nov 10 at 19:18

add a comment |

up vote
-3
down vote

favorite

Hey guys i was given the code to calculate a standard deviation in java netbeans. However I don't really understand how standard deviation works. What does the s represent in the code.

public static <T extends Number> double calculateStandardDeviation(ArrayList<T> numberList) {

        if (numberList.size() <= 1) {

            throw new IllegalArgumentException("Size of array must be greater than 1");

        }



        int numberListSize = numberList.size();

        double s = 0;

        double listAverage = calculateAverage(numberList,true);



        for (int i = 0; i < numberListSize; i++) {

            double numberDouble = numberList.get(i).doubleValue();

            s += Math.pow(numberDouble - listAverage,2);

        }

        double standardDeviation = Math.sqrt(s / (numberListSize-1));

        return standardDeviation;

    }

Sorry if this problem is to simple for stack overflow.

asked Nov 10 at 19:12

Caleb

215

s is variance, sd = sqrt( s/ size - 1)
– The Scientific Method
Nov 10 at 19:16

thanks. I appreciate it
– Caleb
Nov 10 at 19:18

add a comment |

up vote
-3
down vote

favorite

Hey guys i was given the code to calculate a standard deviation in java netbeans. However I don't really understand how standard deviation works. What does the s represent in the code.

public static <T extends Number> double calculateStandardDeviation(ArrayList<T> numberList) {

        if (numberList.size() <= 1) {

            throw new IllegalArgumentException("Size of array must be greater than 1");

        }



        int numberListSize = numberList.size();

        double s = 0;

        double listAverage = calculateAverage(numberList,true);



        for (int i = 0; i < numberListSize; i++) {

            double numberDouble = numberList.get(i).doubleValue();

            s += Math.pow(numberDouble - listAverage,2);

        }

        double standardDeviation = Math.sqrt(s / (numberListSize-1));

        return standardDeviation;

    }

Sorry if this problem is to simple for stack overflow.

asked Nov 10 at 19:12

Caleb

215

Hey guys i was given the code to calculate a standard deviation in java netbeans. However I don't really understand how standard deviation works. What does the s represent in the code.

public static <T extends Number> double calculateStandardDeviation(ArrayList<T> numberList) {

        if (numberList.size() <= 1) {

            throw new IllegalArgumentException("Size of array must be greater than 1");

        }



        int numberListSize = numberList.size();

        double s = 0;

        double listAverage = calculateAverage(numberList,true);



        for (int i = 0; i < numberListSize; i++) {

            double numberDouble = numberList.get(i).doubleValue();

            s += Math.pow(numberDouble - listAverage,2);

        }

        double standardDeviation = Math.sqrt(s / (numberListSize-1));

        return standardDeviation;

    }

Sorry if this problem is to simple for stack overflow.

java netbeans standard-deviation

asked Nov 10 at 19:12

Caleb

215

asked Nov 10 at 19:12

Caleb

215

asked Nov 10 at 19:12

Caleb

215

asked Nov 10 at 19:12

Caleb

215

asked Nov 10 at 19:12

Caleb

215

s is variance, sd = sqrt( s/ size - 1)
– The Scientific Method
Nov 10 at 19:16

thanks. I appreciate it
– Caleb
Nov 10 at 19:18

add a comment |

s is variance, sd = sqrt( s/ size - 1)
– The Scientific Method
Nov 10 at 19:16

thanks. I appreciate it
– Caleb
Nov 10 at 19:18

s is variance, sd = sqrt( s/ size - 1)
– The Scientific Method
Nov 10 at 19:16

thanks. I appreciate it
– Caleb
Nov 10 at 19:18

add a comment |

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