Java: passing variable one time but different values
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I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
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up vote
0
down vote
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I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
Your question does not make sense. We don't know whatobjis. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate themassignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
java
edited Nov 10 at 20:34
Pushpesh Kumar Rajwanshi
2,3601720
2,3601720
asked Nov 10 at 20:30
Akk
35
35
Your question does not make sense. We don't know whatobjis. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate themassignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
add a comment |
Your question does not make sense. We don't know whatobjis. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate themassignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
Your question does not make sense. We don't know what
obj is. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
Your question does not make sense. We don't know what
obj is. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
m assignment everytime you change the value of x– dubes
Nov 10 at 20:37
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
m assignment everytime you change the value of x– dubes
Nov 10 at 20:37
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
add a comment |
up vote
0
down vote
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
add a comment |
up vote
1
down vote
accepted
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
edited Nov 10 at 22:40
answered Nov 10 at 20:52
Sahil Makhijani
538
538
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
add a comment |
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
1
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
add a comment |
up vote
0
down vote
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
up vote
0
down vote
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
up vote
0
down vote
up vote
0
down vote
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
answered Nov 10 at 20:52
Sand
4398
4398
add a comment |
add a comment |
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Your question does not make sense. We don't know what
objis. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
massignment everytime you change the value ofx– dubes
Nov 10 at 20:37