Hibernate escaping “:” character

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I've found some posts here and some answers. I've tried every each of them with bad results. I don't want to use stored procedures.
I'm using Hibernate in Java, with MySQL. Some of my query string is:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit := ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank := @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
Some people said a solution is using /*'*/:=/*'*/
inside the query (post), but it doesn't work for me:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit /*'*/:=/*'*/ ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank /*'*/:=/*'*/ @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
I'm despereted!
Any idea, please? I'd be so grateful!
Thanks!
mysql hibernate
add a comment |
up vote
0
down vote
favorite
I've found some posts here and some answers. I've tried every each of them with bad results. I don't want to use stored procedures.
I'm using Hibernate in Java, with MySQL. Some of my query string is:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit := ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank := @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
Some people said a solution is using /*'*/:=/*'*/
inside the query (post), but it doesn't work for me:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit /*'*/:=/*'*/ ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank /*'*/:=/*'*/ @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
I'm despereted!
Any idea, please? I'd be so grateful!
Thanks!
mysql hibernate
What is the logic behind your query?
– Tim Biegeleisen
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've found some posts here and some answers. I've tried every each of them with bad results. I don't want to use stored procedures.
I'm using Hibernate in Java, with MySQL. Some of my query string is:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit := ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank := @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
Some people said a solution is using /*'*/:=/*'*/
inside the query (post), but it doesn't work for me:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit /*'*/:=/*'*/ ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank /*'*/:=/*'*/ @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
I'm despereted!
Any idea, please? I'd be so grateful!
Thanks!
mysql hibernate
I've found some posts here and some answers. I've tried every each of them with bad results. I don't want to use stored procedures.
I'm using Hibernate in Java, with MySQL. Some of my query string is:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit := ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank := @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
Some people said a solution is using /*'*/:=/*'*/
inside the query (post), but it doesn't work for me:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit /*'*/:=/*'*/ ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank /*'*/:=/*'*/ @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
I'm despereted!
Any idea, please? I'd be so grateful!
Thanks!
mysql hibernate
mysql hibernate
edited yesterday
asked 2 days ago


Ommadawn
165115
165115
What is the logic behind your query?
– Tim Biegeleisen
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago
add a comment |
What is the logic behind your query?
– Tim Biegeleisen
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago
What is the logic behind your query?
– Tim Biegeleisen
2 days ago
What is the logic behind your query?
– Tim Biegeleisen
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
Finally I could fix it using double backslash inside the Java query code:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit \:= ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank \:= @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Finally I could fix it using double backslash inside the Java query code:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit \:= ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank \:= @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
add a comment |
up vote
0
down vote
accepted
Finally I could fix it using double backslash inside the Java query code:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit \:= ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank \:= @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Finally I could fix it using double backslash inside the Java query code:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit \:= ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank \:= @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
Finally I could fix it using double backslash inside the Java query code:
SET @rank = 0;
SET @limit = 0.1;
SELECT (@limit \:= ROUND(COUNT(id) * @limit)) FROM Pics;
SELECT Q1.popularity FROM Pics AS p INNER JOIN (
SELECT IF((@rank \:= @rank + 1) <= @limit, true, false) AS 'popularity', p.id
FROM Pics AS p
ORDER BY p.points DESC
) AS Q1 ON Q1.id = p.id WHERE p.id = 7;
answered yesterday


Ommadawn
165115
165115
add a comment |
add a comment |
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What is the logic behind your query?
– Tim Biegeleisen
2 days ago
Don't think about that, is just a example. It's not the full query, only pieces of code with the ":=" characters.
– Ommadawn
2 days ago
Well I'm thinking about it. In particular, I'm thinking you should avoid using session variables with Hibernate, and maybe I can give you a workaround.
– Tim Biegeleisen
2 days ago
Ok, I'll edit the query and put the original example.
– Ommadawn
2 days ago