Get a newtype'd records underlying type in purescript
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I'm trying to see if there's an easy way to get the type of a newtype'd record to put in function signatures.
newtype T1 = T1 { foo:: Int}
derive instance newtypeT1 :: Newtype T1 _
... other classes that require me to newtype the record ...
I know I can access a records members with
_.property
and I can compose that with unwrap
unwrap >>> _.property
to get a function for that property, but I'd like to write a function similar to
testFoo :: forall a. (_ -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works but the wildcard symbol gives an warning, but I'm not sure how to get that record definition from T1. (This is a minimal example, I have a massive property object that is from an external source.
A workaround I've been using for now has been to declare my type like
type InnerT1 = { foo ::Int}
newtype T1 = T1 InnerT1
and exporting that InnerT1 so it can be used in my test file, but this seems a bit clunky and I am wondering if there is a better way?
purescript
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up vote
0
down vote
favorite
I'm trying to see if there's an easy way to get the type of a newtype'd record to put in function signatures.
newtype T1 = T1 { foo:: Int}
derive instance newtypeT1 :: Newtype T1 _
... other classes that require me to newtype the record ...
I know I can access a records members with
_.property
and I can compose that with unwrap
unwrap >>> _.property
to get a function for that property, but I'd like to write a function similar to
testFoo :: forall a. (_ -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works but the wildcard symbol gives an warning, but I'm not sure how to get that record definition from T1. (This is a minimal example, I have a massive property object that is from an external source.
A workaround I've been using for now has been to declare my type like
type InnerT1 = { foo ::Int}
newtype T1 = T1 InnerT1
and exporting that InnerT1 so it can be used in my test file, but this seems a bit clunky and I am wondering if there is a better way?
purescript
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm trying to see if there's an easy way to get the type of a newtype'd record to put in function signatures.
newtype T1 = T1 { foo:: Int}
derive instance newtypeT1 :: Newtype T1 _
... other classes that require me to newtype the record ...
I know I can access a records members with
_.property
and I can compose that with unwrap
unwrap >>> _.property
to get a function for that property, but I'd like to write a function similar to
testFoo :: forall a. (_ -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works but the wildcard symbol gives an warning, but I'm not sure how to get that record definition from T1. (This is a minimal example, I have a massive property object that is from an external source.
A workaround I've been using for now has been to declare my type like
type InnerT1 = { foo ::Int}
newtype T1 = T1 InnerT1
and exporting that InnerT1 so it can be used in my test file, but this seems a bit clunky and I am wondering if there is a better way?
purescript
I'm trying to see if there's an easy way to get the type of a newtype'd record to put in function signatures.
newtype T1 = T1 { foo:: Int}
derive instance newtypeT1 :: Newtype T1 _
... other classes that require me to newtype the record ...
I know I can access a records members with
_.property
and I can compose that with unwrap
unwrap >>> _.property
to get a function for that property, but I'd like to write a function similar to
testFoo :: forall a. (_ -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works but the wildcard symbol gives an warning, but I'm not sure how to get that record definition from T1. (This is a minimal example, I have a massive property object that is from an external source.
A workaround I've been using for now has been to declare my type like
type InnerT1 = { foo ::Int}
newtype T1 = T1 InnerT1
and exporting that InnerT1 so it can be used in my test file, but this seems a bit clunky and I am wondering if there is a better way?
purescript
purescript
asked Nov 10 at 7:17
Beau Trepp
84021224
84021224
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1 Answer
1
active
oldest
votes
up vote
1
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accepted
You can use the Newtype
class to get at the inner type:
testFoo :: forall a inner. Newtype T1 inner => (inner -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works without additional annotations, because the class has a functional dependency Newtype a b | a -> b
, which means that the inner type is uniquely determined by the outer type.
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You can use the Newtype
class to get at the inner type:
testFoo :: forall a inner. Newtype T1 inner => (inner -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works without additional annotations, because the class has a functional dependency Newtype a b | a -> b
, which means that the inner type is uniquely determined by the outer type.
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
add a comment |
up vote
1
down vote
accepted
You can use the Newtype
class to get at the inner type:
testFoo :: forall a inner. Newtype T1 inner => (inner -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works without additional annotations, because the class has a functional dependency Newtype a b | a -> b
, which means that the inner type is uniquely determined by the outer type.
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You can use the Newtype
class to get at the inner type:
testFoo :: forall a inner. Newtype T1 inner => (inner -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works without additional annotations, because the class has a functional dependency Newtype a b | a -> b
, which means that the inner type is uniquely determined by the outer type.
You can use the Newtype
class to get at the inner type:
testFoo :: forall a inner. Newtype T1 inner => (inner -> a) -> Effect a
testFoo accessor = (unwrap >>> accessor) <$> loadT1
This works without additional annotations, because the class has a functional dependency Newtype a b | a -> b
, which means that the inner type is uniquely determined by the outer type.
answered Nov 10 at 14:24
Fyodor Soikin
41.2k56295
41.2k56295
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
add a comment |
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
This works perfectly!, I knew there was something in there. Thanks!
– Beau Trepp
2 days ago
add a comment |
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