Set child pid to 0 but output others












1















I read such a snippet of code from an instruction



#include "apue.h"

int globvar = 6; /* external variable in initialized data */
char buf = "a write to stdoutn";

int main(void)
{
int var;
pid_t pid; /* automatic variable on the stack */

var = 88; if (write(STDOUT_FILENO, buf, sizeof(buf) - 1) != sizeof(buf) - 1)
err_sys("write error");
printf("before forkn"); /* we don’t flush stdout */

if ((pid = fork()) < 0) {
err_sys("fork error");
} else if (pid == 0) { /* child */
globvar++; /* modify variables */
var++;
} else {
sleep(2); /* parent */
}

printf("pid = %ld, glob = %d, var = %d, bufsize = %lun", (long)getpid(), globvar, var, sizeof(buf));

exit(0);
}


Run it and get outputs



$ ./a.out
a write to stdout
before fork
pid = 7310, glob = 7, var = 89, bufsize = 19 #child’s variables were changed
pid = 7309, glob = 6, var = 88, bufsize = 19 #parent’s copy was not changed


I am confused about the child's pid



if ((pid = fork()) < 0)


the pid is set as 0, but in the output it's pid is 7310.



How could that happen?



does the pid here is just a number rather than a process?










share|improve this question



























    1















    I read such a snippet of code from an instruction



    #include "apue.h"

    int globvar = 6; /* external variable in initialized data */
    char buf = "a write to stdoutn";

    int main(void)
    {
    int var;
    pid_t pid; /* automatic variable on the stack */

    var = 88; if (write(STDOUT_FILENO, buf, sizeof(buf) - 1) != sizeof(buf) - 1)
    err_sys("write error");
    printf("before forkn"); /* we don’t flush stdout */

    if ((pid = fork()) < 0) {
    err_sys("fork error");
    } else if (pid == 0) { /* child */
    globvar++; /* modify variables */
    var++;
    } else {
    sleep(2); /* parent */
    }

    printf("pid = %ld, glob = %d, var = %d, bufsize = %lun", (long)getpid(), globvar, var, sizeof(buf));

    exit(0);
    }


    Run it and get outputs



    $ ./a.out
    a write to stdout
    before fork
    pid = 7310, glob = 7, var = 89, bufsize = 19 #child’s variables were changed
    pid = 7309, glob = 6, var = 88, bufsize = 19 #parent’s copy was not changed


    I am confused about the child's pid



    if ((pid = fork()) < 0)


    the pid is set as 0, but in the output it's pid is 7310.



    How could that happen?



    does the pid here is just a number rather than a process?










    share|improve this question

























      1












      1








      1








      I read such a snippet of code from an instruction



      #include "apue.h"

      int globvar = 6; /* external variable in initialized data */
      char buf = "a write to stdoutn";

      int main(void)
      {
      int var;
      pid_t pid; /* automatic variable on the stack */

      var = 88; if (write(STDOUT_FILENO, buf, sizeof(buf) - 1) != sizeof(buf) - 1)
      err_sys("write error");
      printf("before forkn"); /* we don’t flush stdout */

      if ((pid = fork()) < 0) {
      err_sys("fork error");
      } else if (pid == 0) { /* child */
      globvar++; /* modify variables */
      var++;
      } else {
      sleep(2); /* parent */
      }

      printf("pid = %ld, glob = %d, var = %d, bufsize = %lun", (long)getpid(), globvar, var, sizeof(buf));

      exit(0);
      }


      Run it and get outputs



      $ ./a.out
      a write to stdout
      before fork
      pid = 7310, glob = 7, var = 89, bufsize = 19 #child’s variables were changed
      pid = 7309, glob = 6, var = 88, bufsize = 19 #parent’s copy was not changed


      I am confused about the child's pid



      if ((pid = fork()) < 0)


      the pid is set as 0, but in the output it's pid is 7310.



      How could that happen?



      does the pid here is just a number rather than a process?










      share|improve this question














      I read such a snippet of code from an instruction



      #include "apue.h"

      int globvar = 6; /* external variable in initialized data */
      char buf = "a write to stdoutn";

      int main(void)
      {
      int var;
      pid_t pid; /* automatic variable on the stack */

      var = 88; if (write(STDOUT_FILENO, buf, sizeof(buf) - 1) != sizeof(buf) - 1)
      err_sys("write error");
      printf("before forkn"); /* we don’t flush stdout */

      if ((pid = fork()) < 0) {
      err_sys("fork error");
      } else if (pid == 0) { /* child */
      globvar++; /* modify variables */
      var++;
      } else {
      sleep(2); /* parent */
      }

      printf("pid = %ld, glob = %d, var = %d, bufsize = %lun", (long)getpid(), globvar, var, sizeof(buf));

      exit(0);
      }


      Run it and get outputs



      $ ./a.out
      a write to stdout
      before fork
      pid = 7310, glob = 7, var = 89, bufsize = 19 #child’s variables were changed
      pid = 7309, glob = 6, var = 88, bufsize = 19 #parent’s copy was not changed


      I am confused about the child's pid



      if ((pid = fork()) < 0)


      the pid is set as 0, but in the output it's pid is 7310.



      How could that happen?



      does the pid here is just a number rather than a process?







      c






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 3:44









      JawSawJawSaw

      4,57811837




      4,57811837
























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          fork() returns 0 in the child process, but in the printf statement you are printing the pid using getpid() which is the actual pid of the child process.



          If you had used pid in the printf statement instead of getpid() you will see that it prints 0.






          share|improve this answer























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            fork() returns 0 in the child process, but in the printf statement you are printing the pid using getpid() which is the actual pid of the child process.



            If you had used pid in the printf statement instead of getpid() you will see that it prints 0.






            share|improve this answer




























              1














              fork() returns 0 in the child process, but in the printf statement you are printing the pid using getpid() which is the actual pid of the child process.



              If you had used pid in the printf statement instead of getpid() you will see that it prints 0.






              share|improve this answer


























                1












                1








                1







                fork() returns 0 in the child process, but in the printf statement you are printing the pid using getpid() which is the actual pid of the child process.



                If you had used pid in the printf statement instead of getpid() you will see that it prints 0.






                share|improve this answer













                fork() returns 0 in the child process, but in the printf statement you are printing the pid using getpid() which is the actual pid of the child process.



                If you had used pid in the printf statement instead of getpid() you will see that it prints 0.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 15 '18 at 4:15









                P.WP.W

                15k31452




                15k31452
































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