bad_lexical_cast Exception handling in c++
i am using lexical cast in a function for three different variables. Now if a bad_lexical_cast exception occurs i have to set default values respective to each variable. now how to find from which statement the exception is thrown?
c++11
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
add a comment |
i am using lexical cast in a function for three different variables. Now if a bad_lexical_cast exception occurs i have to set default values respective to each variable. now how to find from which statement the exception is thrown?
c++11
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
1
Look at 6.2 example from. Do the same, put each call of lexical_cast intotry-catchblock.
– rafix07
Nov 14 '18 at 9:18
add a comment |
i am using lexical cast in a function for three different variables. Now if a bad_lexical_cast exception occurs i have to set default values respective to each variable. now how to find from which statement the exception is thrown?
c++11
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
i am using lexical cast in a function for three different variables. Now if a bad_lexical_cast exception occurs i have to set default values respective to each variable. now how to find from which statement the exception is thrown?
c++11
c++11
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
edited Nov 14 '18 at 10:54
Mike Kinghan
30.7k764113
30.7k764113
asked Nov 14 '18 at 9:13
vijiviji
1
asked Nov 14 '18 at 9:13
vijiviji
1
asked Nov 14 '18 at 9:13
vijiviji
1
1
1
Look at 6.2 example from. Do the same, put each call of lexical_cast intotry-catchblock.
– rafix07
Nov 14 '18 at 9:18
add a comment |
1
Look at 6.2 example from. Do the same, put each call of lexical_cast intotry-catchblock.
– rafix07
Nov 14 '18 at 9:18
1
1
Look at 6.2 example from. Do the same, put each call of lexical_cast into
try-catch block.– rafix07
Nov 14 '18 at 9:18
Look at 6.2 example from. Do the same, put each call of lexical_cast into
try-catch block.– rafix07
Nov 14 '18 at 9:18
add a comment |
1 Answer
1
active
oldest
votes
You can assign the default values first and then wrap each boost::lexical_cast into a try-catch block.
Or, better, extract a function that does it for you:
#include <boost/lexical_cast.hpp>
#include <iostream>
template<class T, class S>
T lexical_cast_or_default(S s, T default_value) noexcept {
T value;
return boost::conversion::try_lexical_convert(s, value)
? value
: default_value
;
}
int main() {
double a = lexical_cast_or_default("abc", 3.14);
double b = lexical_cast_or_default("123", 3.14);
int c = lexical_cast_or_default<int>("456", 3.14);
std::cout << a << 'n';
std::cout << b << 'n';
std::cout << c << 'n';
}
Outputs:
3.14
123
456
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53296573%2fbad-lexical-cast-exception-handling-in-c%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can assign the default values first and then wrap each boost::lexical_cast into a try-catch block.
Or, better, extract a function that does it for you:
#include <boost/lexical_cast.hpp>
#include <iostream>
template<class T, class S>
T lexical_cast_or_default(S s, T default_value) noexcept {
T value;
return boost::conversion::try_lexical_convert(s, value)
? value
: default_value
;
}
int main() {
double a = lexical_cast_or_default("abc", 3.14);
double b = lexical_cast_or_default("123", 3.14);
int c = lexical_cast_or_default<int>("456", 3.14);
std::cout << a << 'n';
std::cout << b << 'n';
std::cout << c << 'n';
}
Outputs:
3.14
123
456
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
add a comment |
You can assign the default values first and then wrap each boost::lexical_cast into a try-catch block.
Or, better, extract a function that does it for you:
#include <boost/lexical_cast.hpp>
#include <iostream>
template<class T, class S>
T lexical_cast_or_default(S s, T default_value) noexcept {
T value;
return boost::conversion::try_lexical_convert(s, value)
? value
: default_value
;
}
int main() {
double a = lexical_cast_or_default("abc", 3.14);
double b = lexical_cast_or_default("123", 3.14);
int c = lexical_cast_or_default<int>("456", 3.14);
std::cout << a << 'n';
std::cout << b << 'n';
std::cout << c << 'n';
}
Outputs:
3.14
123
456
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
add a comment |
You can assign the default values first and then wrap each boost::lexical_cast into a try-catch block.
Or, better, extract a function that does it for you:
#include <boost/lexical_cast.hpp>
#include <iostream>
template<class T, class S>
T lexical_cast_or_default(S s, T default_value) noexcept {
T value;
return boost::conversion::try_lexical_convert(s, value)
? value
: default_value
;
}
int main() {
double a = lexical_cast_or_default("abc", 3.14);
double b = lexical_cast_or_default("123", 3.14);
int c = lexical_cast_or_default<int>("456", 3.14);
std::cout << a << 'n';
std::cout << b << 'n';
std::cout << c << 'n';
}
Outputs:
3.14
123
456
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
You can assign the default values first and then wrap each boost::lexical_cast into a try-catch block.
Or, better, extract a function that does it for you:
#include <boost/lexical_cast.hpp>
#include <iostream>
template<class T, class S>
T lexical_cast_or_default(S s, T default_value) noexcept {
T value;
return boost::conversion::try_lexical_convert(s, value)
? value
: default_value
;
}
int main() {
double a = lexical_cast_or_default("abc", 3.14);
double b = lexical_cast_or_default("123", 3.14);
int c = lexical_cast_or_default<int>("456", 3.14);
std::cout << a << 'n';
std::cout << b << 'n';
std::cout << c << 'n';
}
Outputs:
3.14
123
456
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
edited Nov 14 '18 at 11:35
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
answered Nov 14 '18 at 11:23
Maxim EgorushkinMaxim Egorushkin
87.2k11102185
87.2k11102185
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53296573%2fbad-lexical-cast-exception-handling-in-c%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Look at 6.2 example from. Do the same, put each call of lexical_cast into
try-catchblock.– rafix07
Nov 14 '18 at 9:18