Oracle SQL - Generate Unique sAMAccountName












1















I would like to use Oracle SQL to generate unique sAMAccountName for users. The logic to generate the unique name is the First letter of first name + entire Last Name.



If the combination already exists, append 1 at the end of the unique name.
If the second combination already exists, increment till uniqueness is achieved.



For example, 5 users named "Tom Kelly" and 3 users named "Tom Ke" will have the following unique names:




  1. TKelly

  2. TKelly1

  3. TKelly2

  4. TKelly3

  5. TKelly4

  6. TKe

  7. TKe1

  8. TKe2


I have written a procedure for this but it's not working completely. I think the logic needs to be updated in this query of the procedure:



SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter 
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);


The read-only table P_USERS contains all the users with a primary key as "user_id" and the unique name is stored in the attribute "Custom_Unique_Name"



After calculating the unique name, the attribute "PRIMARY_UNIQUE_NAME" in the master user table "T_MASTER_USERS" needs to be updated. This table's primary key is also "user_id" which holds the same value as in the read-only table "P_USERS"



   DECLARE
lastletter varchar2(10);
anyexists varchar2(10);
lastfive varchar2(10);
CURSOR c_length IS SELECT SUBSTR(first_name,1,1)||(last_name) as
tempid2,LENGTH(last_name) as lengthln, user_id, Custom_Unique_Name
FROM P_USERS;
status varchar2(10);
BEGIN
FOR item in c_length
LOOP
EXIT WHEN c_length%notfound;
lastletter:=0;
SELECT NVL(Custom_Unique_Name,0) INTO status FROM P_USERS
WHERE USER_ID=item.user_id;
IF status <> '0' THEN /* Checks if the person already has a
unique id */
NULL; /* If yes, then do nothing and exit the program */
ELSE
SELECT COUNT(*) INTO anyexists FROM (SELECT
Custom_Unique_Name FROM P_USERS
WHERE Custom_Unique_Name = item.tempid2 AND user_id <>
item.user_id);
IF anyexists=0 THEN /* Check if unique id exists for
the user. If not, then assign unique_id to the user */
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2 WHERE
user_id=item.user_id;
ELSE
SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);
IF LENGTH(TRIM(TRANSLATE(lastletter, '
+-.0123456789',' '))) > 0 THEN /* Checks if the count
of equivalent unique names if a number. If not, append
1*/
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||'1' WHERE
user_id=item.user_id;
ELSE
lastletter:=lastletter+1;
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||lastletter WHERE
user_id=item.user_id;
END IF;
END IF;
END IF;
END LOOP;
END;









share|improve this question























  • I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

    – Joel Coehoorn
    Nov 13 '18 at 19:57


















1















I would like to use Oracle SQL to generate unique sAMAccountName for users. The logic to generate the unique name is the First letter of first name + entire Last Name.



If the combination already exists, append 1 at the end of the unique name.
If the second combination already exists, increment till uniqueness is achieved.



For example, 5 users named "Tom Kelly" and 3 users named "Tom Ke" will have the following unique names:




  1. TKelly

  2. TKelly1

  3. TKelly2

  4. TKelly3

  5. TKelly4

  6. TKe

  7. TKe1

  8. TKe2


I have written a procedure for this but it's not working completely. I think the logic needs to be updated in this query of the procedure:



SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter 
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);


The read-only table P_USERS contains all the users with a primary key as "user_id" and the unique name is stored in the attribute "Custom_Unique_Name"



After calculating the unique name, the attribute "PRIMARY_UNIQUE_NAME" in the master user table "T_MASTER_USERS" needs to be updated. This table's primary key is also "user_id" which holds the same value as in the read-only table "P_USERS"



   DECLARE
lastletter varchar2(10);
anyexists varchar2(10);
lastfive varchar2(10);
CURSOR c_length IS SELECT SUBSTR(first_name,1,1)||(last_name) as
tempid2,LENGTH(last_name) as lengthln, user_id, Custom_Unique_Name
FROM P_USERS;
status varchar2(10);
BEGIN
FOR item in c_length
LOOP
EXIT WHEN c_length%notfound;
lastletter:=0;
SELECT NVL(Custom_Unique_Name,0) INTO status FROM P_USERS
WHERE USER_ID=item.user_id;
IF status <> '0' THEN /* Checks if the person already has a
unique id */
NULL; /* If yes, then do nothing and exit the program */
ELSE
SELECT COUNT(*) INTO anyexists FROM (SELECT
Custom_Unique_Name FROM P_USERS
WHERE Custom_Unique_Name = item.tempid2 AND user_id <>
item.user_id);
IF anyexists=0 THEN /* Check if unique id exists for
the user. If not, then assign unique_id to the user */
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2 WHERE
user_id=item.user_id;
ELSE
SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);
IF LENGTH(TRIM(TRANSLATE(lastletter, '
+-.0123456789',' '))) > 0 THEN /* Checks if the count
of equivalent unique names if a number. If not, append
1*/
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||'1' WHERE
user_id=item.user_id;
ELSE
lastletter:=lastletter+1;
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||lastletter WHERE
user_id=item.user_id;
END IF;
END IF;
END IF;
END LOOP;
END;









share|improve this question























  • I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

    – Joel Coehoorn
    Nov 13 '18 at 19:57
















1












1








1








I would like to use Oracle SQL to generate unique sAMAccountName for users. The logic to generate the unique name is the First letter of first name + entire Last Name.



If the combination already exists, append 1 at the end of the unique name.
If the second combination already exists, increment till uniqueness is achieved.



For example, 5 users named "Tom Kelly" and 3 users named "Tom Ke" will have the following unique names:




  1. TKelly

  2. TKelly1

  3. TKelly2

  4. TKelly3

  5. TKelly4

  6. TKe

  7. TKe1

  8. TKe2


I have written a procedure for this but it's not working completely. I think the logic needs to be updated in this query of the procedure:



SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter 
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);


The read-only table P_USERS contains all the users with a primary key as "user_id" and the unique name is stored in the attribute "Custom_Unique_Name"



After calculating the unique name, the attribute "PRIMARY_UNIQUE_NAME" in the master user table "T_MASTER_USERS" needs to be updated. This table's primary key is also "user_id" which holds the same value as in the read-only table "P_USERS"



   DECLARE
lastletter varchar2(10);
anyexists varchar2(10);
lastfive varchar2(10);
CURSOR c_length IS SELECT SUBSTR(first_name,1,1)||(last_name) as
tempid2,LENGTH(last_name) as lengthln, user_id, Custom_Unique_Name
FROM P_USERS;
status varchar2(10);
BEGIN
FOR item in c_length
LOOP
EXIT WHEN c_length%notfound;
lastletter:=0;
SELECT NVL(Custom_Unique_Name,0) INTO status FROM P_USERS
WHERE USER_ID=item.user_id;
IF status <> '0' THEN /* Checks if the person already has a
unique id */
NULL; /* If yes, then do nothing and exit the program */
ELSE
SELECT COUNT(*) INTO anyexists FROM (SELECT
Custom_Unique_Name FROM P_USERS
WHERE Custom_Unique_Name = item.tempid2 AND user_id <>
item.user_id);
IF anyexists=0 THEN /* Check if unique id exists for
the user. If not, then assign unique_id to the user */
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2 WHERE
user_id=item.user_id;
ELSE
SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);
IF LENGTH(TRIM(TRANSLATE(lastletter, '
+-.0123456789',' '))) > 0 THEN /* Checks if the count
of equivalent unique names if a number. If not, append
1*/
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||'1' WHERE
user_id=item.user_id;
ELSE
lastletter:=lastletter+1;
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||lastletter WHERE
user_id=item.user_id;
END IF;
END IF;
END IF;
END LOOP;
END;









share|improve this question














I would like to use Oracle SQL to generate unique sAMAccountName for users. The logic to generate the unique name is the First letter of first name + entire Last Name.



If the combination already exists, append 1 at the end of the unique name.
If the second combination already exists, increment till uniqueness is achieved.



For example, 5 users named "Tom Kelly" and 3 users named "Tom Ke" will have the following unique names:




  1. TKelly

  2. TKelly1

  3. TKelly2

  4. TKelly3

  5. TKelly4

  6. TKe

  7. TKe1

  8. TKe2


I have written a procedure for this but it's not working completely. I think the logic needs to be updated in this query of the procedure:



SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter 
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);


The read-only table P_USERS contains all the users with a primary key as "user_id" and the unique name is stored in the attribute "Custom_Unique_Name"



After calculating the unique name, the attribute "PRIMARY_UNIQUE_NAME" in the master user table "T_MASTER_USERS" needs to be updated. This table's primary key is also "user_id" which holds the same value as in the read-only table "P_USERS"



   DECLARE
lastletter varchar2(10);
anyexists varchar2(10);
lastfive varchar2(10);
CURSOR c_length IS SELECT SUBSTR(first_name,1,1)||(last_name) as
tempid2,LENGTH(last_name) as lengthln, user_id, Custom_Unique_Name
FROM P_USERS;
status varchar2(10);
BEGIN
FOR item in c_length
LOOP
EXIT WHEN c_length%notfound;
lastletter:=0;
SELECT NVL(Custom_Unique_Name,0) INTO status FROM P_USERS
WHERE USER_ID=item.user_id;
IF status <> '0' THEN /* Checks if the person already has a
unique id */
NULL; /* If yes, then do nothing and exit the program */
ELSE
SELECT COUNT(*) INTO anyexists FROM (SELECT
Custom_Unique_Name FROM P_USERS
WHERE Custom_Unique_Name = item.tempid2 AND user_id <>
item.user_id);
IF anyexists=0 THEN /* Check if unique id exists for
the user. If not, then assign unique_id to the user */
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2 WHERE
user_id=item.user_id;
ELSE
SELECT SUBSTR(Custom_Unique_Name,-1,1) INTO lastletter
FROM (SELECT * FROM (SELECT Custom_Unique_Name FROM
P_USERS WHERE Custom_Unique_Name= item.tempid2 AND
user_id <> item.user_id ORDER BY Custom_Unique_Name
DESC) WHERE ROWNUM<=1);
IF LENGTH(TRIM(TRANSLATE(lastletter, '
+-.0123456789',' '))) > 0 THEN /* Checks if the count
of equivalent unique names if a number. If not, append
1*/
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||'1' WHERE
user_id=item.user_id;
ELSE
lastletter:=lastletter+1;
UPDATE T_MASTER_USERS SET
PRIMARY_UNIQUE_NAME=item.tempid2||lastletter WHERE
user_id=item.user_id;
END IF;
END IF;
END IF;
END LOOP;
END;






sql oracle






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asked Nov 13 '18 at 19:04









Gaurav KabraGaurav Kabra

5419




5419













  • I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

    – Joel Coehoorn
    Nov 13 '18 at 19:57





















  • I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

    – Joel Coehoorn
    Nov 13 '18 at 19:57



















I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

– Joel Coehoorn
Nov 13 '18 at 19:57







I built a system like this once before, I found it much easier to handle this in client code for whatever app I was building... generate a string there, and try an insert against a column with a UNIQUE constraint, and keep iterating on failure until it succeeds. More recently, I've wanted system to be sure there is either a manual human review, a choice is offered, or the username is a valid e-mail address from an outside system before creating the name.

– Joel Coehoorn
Nov 13 '18 at 19:57














3 Answers
3






active

oldest

votes


















1














How about something like this?



SQL> create table users
2 (username varchar2(20) primary key);

Table created.

SQL> create or replace procedure p_un (par_first_name in varchar2,
2 par_last_name in varchar2)
3 is
4 l_username users.username%type;
5 l_letter users.username%type;
6 l_digit users.username%type;
7 retval users.username%type;
8 begin
9 l_username := upper(substr(par_first_name, 1, 1) || par_last_name);
10
11 select max(regexp_substr(u.username, '^w+')) l_letter,
12 max(regexp_substr(u.username, 'd+$')) l_digit
13 into l_letter,
14 l_digit
15 from users u
16 where u.username like l_username ||'%'
17 and ( substr(u.username, length(l_username) + 1, 1) between '1' and '9'
18 or ( regexp_substr(u.username, 'd$') is null
19 and substr(u.username, length(l_username) + 1, 1) is null
20 )
21 )
22 and ( to_number(regexp_substr(username, 'd$')) =
23 (select max(to_number(regexp_substr(u1.username, 'd$')))
24 from users u1
25 where u1.username like l_username ||'%'
26 and ( substr(u1.username, length(l_username) + 1, 1) between '1' and '9'
27 or ( regexp_substr(u1.username, 'd$') is null
28 and substr(u1.username, length(l_username) + 1, 1) is null
29 )
30 )
31 )
32 or regexp_substr(u.username, 'd$') is null
33 );
34
35 if l_letter is null then
36 retval := upper(l_username);
37 else
38 retval := upper(l_username || to_char(to_number(nvl(l_digit, 0)) + 1));
39 end if;
40
41 dbms_output.put_line('l_username = ' || l_username||', letter = '|| l_letter||
42 ', digit = '||l_digit ||', new username = ' || retval);
43 insert into users (username) values (retval);
44 end;
45 /

Procedure created.


What does it do?



SELECT (at line 11) searches for existing usernames that




  • look like a new username (which is composed of the first letter of the first name and the whole last name) (line 16)

  • contains a number at the end (line 17)

  • or there's no number at all (lines 18, 19)

  • but, if there is a number there, select MAX number (line 23)

  • if such a username doesn't exist, return its default value (line 36)

  • if it exists, add 1 to the MAX number and attach it to the default username value (line 38)


Testing:



SQL> exec p_un('Tom', 'Kelly');
l_username = TKELLY, letter = , digit = , new username = TKELLY

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Kelly');
l_username = TKELLY, letter = TKELLY, digit = , new username = TKELLY1

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Kelly');
l_username = TKELLY, letter = TKELLY1, digit = 1, new username = TKELLY2

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Ke');
l_username = TKE, letter = , digit = , new username = TKE

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Ke');
l_username = TKE, letter = TKE, digit = , new username = TKE1

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Kelly');
l_username = TKELLY, letter = TKELLY2, digit = 2, new username = TKELLY3

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Ke');
l_username = TKE, letter = TKE1, digit = 1, new username = TKE2

PL/SQL procedure successfully completed.

SQL> exec p_un('Tom', 'Ke');
l_username = TKE, letter = TKE2, digit = 2, new username = TKE3

PL/SQL procedure successfully completed.


Result:



SQL> select * From users;

USERNAME
--------------------
TKE
TKE1
TKE2
TKE3
TKELLY
TKELLY1
TKELLY2
TKELLY3

8 rows selected.





share|improve this answer

































    0














    Try below Anonymous block for your scenario:



      create table P_USERS
    (first_name varchar2(20),
    last_name varchar2(20),
    user_id number);

    insert into P_USERS values ('Tom','Kelly',1);
    insert into P_USERS values ('Tom','Kelly',2);
    insert into P_USERS values ('Tom','Kelly',3);
    insert into P_USERS values ('Tom','Kelly',4);
    insert into P_USERS values ('Tom','Kelly',5);
    insert into P_USERS values ('Tom','Ke',6);
    insert into P_USERS values ('Tom','Ke',7);
    insert into P_USERS values ('Tom','Ke',8);
    commit;

    create table T_MASTER_USERS
    ( user_id number,
    PRIMARY_UNIQUE_NAME varchar2(20));

    insert into T_MASTER_USERS values (1,NULL);
    insert into T_MASTER_USERS values (2,NULL);
    insert into T_MASTER_USERS values (3,NULL);
    insert into T_MASTER_USERS values (4,NULL);
    insert into T_MASTER_USERS values (5,NULL);
    insert into T_MASTER_USERS values (6,NULL);
    insert into T_MASTER_USERS values (7,NULL);
    insert into T_MASTER_USERS values (8,NULL);
    commit;


    DECLARE
    cursor uniq_grp is SELECT SUBSTR(first_name,1,1)||(last_name) as
    tempid2 ,count(*) as CNT
    FROM P_USERS
    group by SUBSTR(first_name,1,1)||(last_name);

    cursor concat_names is SELECT SUBSTR(first_name,1,1)||(last_name) as
    tempid2, user_id
    FROM P_USERS;

    V_CNT number;

    BEGIN

    FOR C1 in uniq_grp

    LOOP

    FOR C2 IN concat_names
    LOOP
    IF C2.tempid2=C1.tempid2 THEN
    V_CNT := c1.CNT -1;
    UPDATE T_MASTER_USERS SET
    PRIMARY_UNIQUE_NAME=c2.tempid2||V_CNT WHERE
    user_id=C2.user_id;
    c1.cnt := V_CNT;
    END IF;
    END LOOP;

    COMMIT;

    END LOOP;

    END;





    share|improve this answer































      0














      create or replace procedure generate_unique(par_first_name in varchar2,par_last_name in varchar2)
      (par_first_name in varchar2,par_last_name in varchar2)

      is

      l_username users.username%type;

      l_letter users.username%type;



      begin



       l_username := upper(substr(par_first_name, 1, 1) || par_last_name); 

      dbms_output.put_line('l_username = ' || l_username );


      SELECT CASE WHEN MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', '')) IS NULL



                  THEN l_username 

      ELSE l_username

      ||

      (MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', ''))+1)

      END into l_letter FROM USERS WHERE REGEXP_LIKE(UPPER(USERNAME),l_username||'[0-9]*$');


      dbms_output.put_line('unique userid is ' || l_letter);

      end;






      share|improve this answer
























      • Please include an explanation of your code, and fix your code block formatting.

        – mypetlion
        Nov 20 '18 at 17:44











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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      How about something like this?



      SQL> create table users
      2 (username varchar2(20) primary key);

      Table created.

      SQL> create or replace procedure p_un (par_first_name in varchar2,
      2 par_last_name in varchar2)
      3 is
      4 l_username users.username%type;
      5 l_letter users.username%type;
      6 l_digit users.username%type;
      7 retval users.username%type;
      8 begin
      9 l_username := upper(substr(par_first_name, 1, 1) || par_last_name);
      10
      11 select max(regexp_substr(u.username, '^w+')) l_letter,
      12 max(regexp_substr(u.username, 'd+$')) l_digit
      13 into l_letter,
      14 l_digit
      15 from users u
      16 where u.username like l_username ||'%'
      17 and ( substr(u.username, length(l_username) + 1, 1) between '1' and '9'
      18 or ( regexp_substr(u.username, 'd$') is null
      19 and substr(u.username, length(l_username) + 1, 1) is null
      20 )
      21 )
      22 and ( to_number(regexp_substr(username, 'd$')) =
      23 (select max(to_number(regexp_substr(u1.username, 'd$')))
      24 from users u1
      25 where u1.username like l_username ||'%'
      26 and ( substr(u1.username, length(l_username) + 1, 1) between '1' and '9'
      27 or ( regexp_substr(u1.username, 'd$') is null
      28 and substr(u1.username, length(l_username) + 1, 1) is null
      29 )
      30 )
      31 )
      32 or regexp_substr(u.username, 'd$') is null
      33 );
      34
      35 if l_letter is null then
      36 retval := upper(l_username);
      37 else
      38 retval := upper(l_username || to_char(to_number(nvl(l_digit, 0)) + 1));
      39 end if;
      40
      41 dbms_output.put_line('l_username = ' || l_username||', letter = '|| l_letter||
      42 ', digit = '||l_digit ||', new username = ' || retval);
      43 insert into users (username) values (retval);
      44 end;
      45 /

      Procedure created.


      What does it do?



      SELECT (at line 11) searches for existing usernames that




      • look like a new username (which is composed of the first letter of the first name and the whole last name) (line 16)

      • contains a number at the end (line 17)

      • or there's no number at all (lines 18, 19)

      • but, if there is a number there, select MAX number (line 23)

      • if such a username doesn't exist, return its default value (line 36)

      • if it exists, add 1 to the MAX number and attach it to the default username value (line 38)


      Testing:



      SQL> exec p_un('Tom', 'Kelly');
      l_username = TKELLY, letter = , digit = , new username = TKELLY

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Kelly');
      l_username = TKELLY, letter = TKELLY, digit = , new username = TKELLY1

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Kelly');
      l_username = TKELLY, letter = TKELLY1, digit = 1, new username = TKELLY2

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Ke');
      l_username = TKE, letter = , digit = , new username = TKE

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Ke');
      l_username = TKE, letter = TKE, digit = , new username = TKE1

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Kelly');
      l_username = TKELLY, letter = TKELLY2, digit = 2, new username = TKELLY3

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Ke');
      l_username = TKE, letter = TKE1, digit = 1, new username = TKE2

      PL/SQL procedure successfully completed.

      SQL> exec p_un('Tom', 'Ke');
      l_username = TKE, letter = TKE2, digit = 2, new username = TKE3

      PL/SQL procedure successfully completed.


      Result:



      SQL> select * From users;

      USERNAME
      --------------------
      TKE
      TKE1
      TKE2
      TKE3
      TKELLY
      TKELLY1
      TKELLY2
      TKELLY3

      8 rows selected.





      share|improve this answer






























        1














        How about something like this?



        SQL> create table users
        2 (username varchar2(20) primary key);

        Table created.

        SQL> create or replace procedure p_un (par_first_name in varchar2,
        2 par_last_name in varchar2)
        3 is
        4 l_username users.username%type;
        5 l_letter users.username%type;
        6 l_digit users.username%type;
        7 retval users.username%type;
        8 begin
        9 l_username := upper(substr(par_first_name, 1, 1) || par_last_name);
        10
        11 select max(regexp_substr(u.username, '^w+')) l_letter,
        12 max(regexp_substr(u.username, 'd+$')) l_digit
        13 into l_letter,
        14 l_digit
        15 from users u
        16 where u.username like l_username ||'%'
        17 and ( substr(u.username, length(l_username) + 1, 1) between '1' and '9'
        18 or ( regexp_substr(u.username, 'd$') is null
        19 and substr(u.username, length(l_username) + 1, 1) is null
        20 )
        21 )
        22 and ( to_number(regexp_substr(username, 'd$')) =
        23 (select max(to_number(regexp_substr(u1.username, 'd$')))
        24 from users u1
        25 where u1.username like l_username ||'%'
        26 and ( substr(u1.username, length(l_username) + 1, 1) between '1' and '9'
        27 or ( regexp_substr(u1.username, 'd$') is null
        28 and substr(u1.username, length(l_username) + 1, 1) is null
        29 )
        30 )
        31 )
        32 or regexp_substr(u.username, 'd$') is null
        33 );
        34
        35 if l_letter is null then
        36 retval := upper(l_username);
        37 else
        38 retval := upper(l_username || to_char(to_number(nvl(l_digit, 0)) + 1));
        39 end if;
        40
        41 dbms_output.put_line('l_username = ' || l_username||', letter = '|| l_letter||
        42 ', digit = '||l_digit ||', new username = ' || retval);
        43 insert into users (username) values (retval);
        44 end;
        45 /

        Procedure created.


        What does it do?



        SELECT (at line 11) searches for existing usernames that




        • look like a new username (which is composed of the first letter of the first name and the whole last name) (line 16)

        • contains a number at the end (line 17)

        • or there's no number at all (lines 18, 19)

        • but, if there is a number there, select MAX number (line 23)

        • if such a username doesn't exist, return its default value (line 36)

        • if it exists, add 1 to the MAX number and attach it to the default username value (line 38)


        Testing:



        SQL> exec p_un('Tom', 'Kelly');
        l_username = TKELLY, letter = , digit = , new username = TKELLY

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Kelly');
        l_username = TKELLY, letter = TKELLY, digit = , new username = TKELLY1

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Kelly');
        l_username = TKELLY, letter = TKELLY1, digit = 1, new username = TKELLY2

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Ke');
        l_username = TKE, letter = , digit = , new username = TKE

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Ke');
        l_username = TKE, letter = TKE, digit = , new username = TKE1

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Kelly');
        l_username = TKELLY, letter = TKELLY2, digit = 2, new username = TKELLY3

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Ke');
        l_username = TKE, letter = TKE1, digit = 1, new username = TKE2

        PL/SQL procedure successfully completed.

        SQL> exec p_un('Tom', 'Ke');
        l_username = TKE, letter = TKE2, digit = 2, new username = TKE3

        PL/SQL procedure successfully completed.


        Result:



        SQL> select * From users;

        USERNAME
        --------------------
        TKE
        TKE1
        TKE2
        TKE3
        TKELLY
        TKELLY1
        TKELLY2
        TKELLY3

        8 rows selected.





        share|improve this answer




























          1












          1








          1







          How about something like this?



          SQL> create table users
          2 (username varchar2(20) primary key);

          Table created.

          SQL> create or replace procedure p_un (par_first_name in varchar2,
          2 par_last_name in varchar2)
          3 is
          4 l_username users.username%type;
          5 l_letter users.username%type;
          6 l_digit users.username%type;
          7 retval users.username%type;
          8 begin
          9 l_username := upper(substr(par_first_name, 1, 1) || par_last_name);
          10
          11 select max(regexp_substr(u.username, '^w+')) l_letter,
          12 max(regexp_substr(u.username, 'd+$')) l_digit
          13 into l_letter,
          14 l_digit
          15 from users u
          16 where u.username like l_username ||'%'
          17 and ( substr(u.username, length(l_username) + 1, 1) between '1' and '9'
          18 or ( regexp_substr(u.username, 'd$') is null
          19 and substr(u.username, length(l_username) + 1, 1) is null
          20 )
          21 )
          22 and ( to_number(regexp_substr(username, 'd$')) =
          23 (select max(to_number(regexp_substr(u1.username, 'd$')))
          24 from users u1
          25 where u1.username like l_username ||'%'
          26 and ( substr(u1.username, length(l_username) + 1, 1) between '1' and '9'
          27 or ( regexp_substr(u1.username, 'd$') is null
          28 and substr(u1.username, length(l_username) + 1, 1) is null
          29 )
          30 )
          31 )
          32 or regexp_substr(u.username, 'd$') is null
          33 );
          34
          35 if l_letter is null then
          36 retval := upper(l_username);
          37 else
          38 retval := upper(l_username || to_char(to_number(nvl(l_digit, 0)) + 1));
          39 end if;
          40
          41 dbms_output.put_line('l_username = ' || l_username||', letter = '|| l_letter||
          42 ', digit = '||l_digit ||', new username = ' || retval);
          43 insert into users (username) values (retval);
          44 end;
          45 /

          Procedure created.


          What does it do?



          SELECT (at line 11) searches for existing usernames that




          • look like a new username (which is composed of the first letter of the first name and the whole last name) (line 16)

          • contains a number at the end (line 17)

          • or there's no number at all (lines 18, 19)

          • but, if there is a number there, select MAX number (line 23)

          • if such a username doesn't exist, return its default value (line 36)

          • if it exists, add 1 to the MAX number and attach it to the default username value (line 38)


          Testing:



          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = , digit = , new username = TKELLY

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY, digit = , new username = TKELLY1

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY1, digit = 1, new username = TKELLY2

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = , digit = , new username = TKE

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE, digit = , new username = TKE1

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY2, digit = 2, new username = TKELLY3

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE1, digit = 1, new username = TKE2

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE2, digit = 2, new username = TKE3

          PL/SQL procedure successfully completed.


          Result:



          SQL> select * From users;

          USERNAME
          --------------------
          TKE
          TKE1
          TKE2
          TKE3
          TKELLY
          TKELLY1
          TKELLY2
          TKELLY3

          8 rows selected.





          share|improve this answer















          How about something like this?



          SQL> create table users
          2 (username varchar2(20) primary key);

          Table created.

          SQL> create or replace procedure p_un (par_first_name in varchar2,
          2 par_last_name in varchar2)
          3 is
          4 l_username users.username%type;
          5 l_letter users.username%type;
          6 l_digit users.username%type;
          7 retval users.username%type;
          8 begin
          9 l_username := upper(substr(par_first_name, 1, 1) || par_last_name);
          10
          11 select max(regexp_substr(u.username, '^w+')) l_letter,
          12 max(regexp_substr(u.username, 'd+$')) l_digit
          13 into l_letter,
          14 l_digit
          15 from users u
          16 where u.username like l_username ||'%'
          17 and ( substr(u.username, length(l_username) + 1, 1) between '1' and '9'
          18 or ( regexp_substr(u.username, 'd$') is null
          19 and substr(u.username, length(l_username) + 1, 1) is null
          20 )
          21 )
          22 and ( to_number(regexp_substr(username, 'd$')) =
          23 (select max(to_number(regexp_substr(u1.username, 'd$')))
          24 from users u1
          25 where u1.username like l_username ||'%'
          26 and ( substr(u1.username, length(l_username) + 1, 1) between '1' and '9'
          27 or ( regexp_substr(u1.username, 'd$') is null
          28 and substr(u1.username, length(l_username) + 1, 1) is null
          29 )
          30 )
          31 )
          32 or regexp_substr(u.username, 'd$') is null
          33 );
          34
          35 if l_letter is null then
          36 retval := upper(l_username);
          37 else
          38 retval := upper(l_username || to_char(to_number(nvl(l_digit, 0)) + 1));
          39 end if;
          40
          41 dbms_output.put_line('l_username = ' || l_username||', letter = '|| l_letter||
          42 ', digit = '||l_digit ||', new username = ' || retval);
          43 insert into users (username) values (retval);
          44 end;
          45 /

          Procedure created.


          What does it do?



          SELECT (at line 11) searches for existing usernames that




          • look like a new username (which is composed of the first letter of the first name and the whole last name) (line 16)

          • contains a number at the end (line 17)

          • or there's no number at all (lines 18, 19)

          • but, if there is a number there, select MAX number (line 23)

          • if such a username doesn't exist, return its default value (line 36)

          • if it exists, add 1 to the MAX number and attach it to the default username value (line 38)


          Testing:



          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = , digit = , new username = TKELLY

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY, digit = , new username = TKELLY1

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY1, digit = 1, new username = TKELLY2

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = , digit = , new username = TKE

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE, digit = , new username = TKE1

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Kelly');
          l_username = TKELLY, letter = TKELLY2, digit = 2, new username = TKELLY3

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE1, digit = 1, new username = TKE2

          PL/SQL procedure successfully completed.

          SQL> exec p_un('Tom', 'Ke');
          l_username = TKE, letter = TKE2, digit = 2, new username = TKE3

          PL/SQL procedure successfully completed.


          Result:



          SQL> select * From users;

          USERNAME
          --------------------
          TKE
          TKE1
          TKE2
          TKE3
          TKELLY
          TKELLY1
          TKELLY2
          TKELLY3

          8 rows selected.






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 13 '18 at 20:14

























          answered Nov 13 '18 at 20:08









          LittlefootLittlefoot

          21.1k71433




          21.1k71433

























              0














              Try below Anonymous block for your scenario:



                create table P_USERS
              (first_name varchar2(20),
              last_name varchar2(20),
              user_id number);

              insert into P_USERS values ('Tom','Kelly',1);
              insert into P_USERS values ('Tom','Kelly',2);
              insert into P_USERS values ('Tom','Kelly',3);
              insert into P_USERS values ('Tom','Kelly',4);
              insert into P_USERS values ('Tom','Kelly',5);
              insert into P_USERS values ('Tom','Ke',6);
              insert into P_USERS values ('Tom','Ke',7);
              insert into P_USERS values ('Tom','Ke',8);
              commit;

              create table T_MASTER_USERS
              ( user_id number,
              PRIMARY_UNIQUE_NAME varchar2(20));

              insert into T_MASTER_USERS values (1,NULL);
              insert into T_MASTER_USERS values (2,NULL);
              insert into T_MASTER_USERS values (3,NULL);
              insert into T_MASTER_USERS values (4,NULL);
              insert into T_MASTER_USERS values (5,NULL);
              insert into T_MASTER_USERS values (6,NULL);
              insert into T_MASTER_USERS values (7,NULL);
              insert into T_MASTER_USERS values (8,NULL);
              commit;


              DECLARE
              cursor uniq_grp is SELECT SUBSTR(first_name,1,1)||(last_name) as
              tempid2 ,count(*) as CNT
              FROM P_USERS
              group by SUBSTR(first_name,1,1)||(last_name);

              cursor concat_names is SELECT SUBSTR(first_name,1,1)||(last_name) as
              tempid2, user_id
              FROM P_USERS;

              V_CNT number;

              BEGIN

              FOR C1 in uniq_grp

              LOOP

              FOR C2 IN concat_names
              LOOP
              IF C2.tempid2=C1.tempid2 THEN
              V_CNT := c1.CNT -1;
              UPDATE T_MASTER_USERS SET
              PRIMARY_UNIQUE_NAME=c2.tempid2||V_CNT WHERE
              user_id=C2.user_id;
              c1.cnt := V_CNT;
              END IF;
              END LOOP;

              COMMIT;

              END LOOP;

              END;





              share|improve this answer




























                0














                Try below Anonymous block for your scenario:



                  create table P_USERS
                (first_name varchar2(20),
                last_name varchar2(20),
                user_id number);

                insert into P_USERS values ('Tom','Kelly',1);
                insert into P_USERS values ('Tom','Kelly',2);
                insert into P_USERS values ('Tom','Kelly',3);
                insert into P_USERS values ('Tom','Kelly',4);
                insert into P_USERS values ('Tom','Kelly',5);
                insert into P_USERS values ('Tom','Ke',6);
                insert into P_USERS values ('Tom','Ke',7);
                insert into P_USERS values ('Tom','Ke',8);
                commit;

                create table T_MASTER_USERS
                ( user_id number,
                PRIMARY_UNIQUE_NAME varchar2(20));

                insert into T_MASTER_USERS values (1,NULL);
                insert into T_MASTER_USERS values (2,NULL);
                insert into T_MASTER_USERS values (3,NULL);
                insert into T_MASTER_USERS values (4,NULL);
                insert into T_MASTER_USERS values (5,NULL);
                insert into T_MASTER_USERS values (6,NULL);
                insert into T_MASTER_USERS values (7,NULL);
                insert into T_MASTER_USERS values (8,NULL);
                commit;


                DECLARE
                cursor uniq_grp is SELECT SUBSTR(first_name,1,1)||(last_name) as
                tempid2 ,count(*) as CNT
                FROM P_USERS
                group by SUBSTR(first_name,1,1)||(last_name);

                cursor concat_names is SELECT SUBSTR(first_name,1,1)||(last_name) as
                tempid2, user_id
                FROM P_USERS;

                V_CNT number;

                BEGIN

                FOR C1 in uniq_grp

                LOOP

                FOR C2 IN concat_names
                LOOP
                IF C2.tempid2=C1.tempid2 THEN
                V_CNT := c1.CNT -1;
                UPDATE T_MASTER_USERS SET
                PRIMARY_UNIQUE_NAME=c2.tempid2||V_CNT WHERE
                user_id=C2.user_id;
                c1.cnt := V_CNT;
                END IF;
                END LOOP;

                COMMIT;

                END LOOP;

                END;





                share|improve this answer


























                  0












                  0








                  0







                  Try below Anonymous block for your scenario:



                    create table P_USERS
                  (first_name varchar2(20),
                  last_name varchar2(20),
                  user_id number);

                  insert into P_USERS values ('Tom','Kelly',1);
                  insert into P_USERS values ('Tom','Kelly',2);
                  insert into P_USERS values ('Tom','Kelly',3);
                  insert into P_USERS values ('Tom','Kelly',4);
                  insert into P_USERS values ('Tom','Kelly',5);
                  insert into P_USERS values ('Tom','Ke',6);
                  insert into P_USERS values ('Tom','Ke',7);
                  insert into P_USERS values ('Tom','Ke',8);
                  commit;

                  create table T_MASTER_USERS
                  ( user_id number,
                  PRIMARY_UNIQUE_NAME varchar2(20));

                  insert into T_MASTER_USERS values (1,NULL);
                  insert into T_MASTER_USERS values (2,NULL);
                  insert into T_MASTER_USERS values (3,NULL);
                  insert into T_MASTER_USERS values (4,NULL);
                  insert into T_MASTER_USERS values (5,NULL);
                  insert into T_MASTER_USERS values (6,NULL);
                  insert into T_MASTER_USERS values (7,NULL);
                  insert into T_MASTER_USERS values (8,NULL);
                  commit;


                  DECLARE
                  cursor uniq_grp is SELECT SUBSTR(first_name,1,1)||(last_name) as
                  tempid2 ,count(*) as CNT
                  FROM P_USERS
                  group by SUBSTR(first_name,1,1)||(last_name);

                  cursor concat_names is SELECT SUBSTR(first_name,1,1)||(last_name) as
                  tempid2, user_id
                  FROM P_USERS;

                  V_CNT number;

                  BEGIN

                  FOR C1 in uniq_grp

                  LOOP

                  FOR C2 IN concat_names
                  LOOP
                  IF C2.tempid2=C1.tempid2 THEN
                  V_CNT := c1.CNT -1;
                  UPDATE T_MASTER_USERS SET
                  PRIMARY_UNIQUE_NAME=c2.tempid2||V_CNT WHERE
                  user_id=C2.user_id;
                  c1.cnt := V_CNT;
                  END IF;
                  END LOOP;

                  COMMIT;

                  END LOOP;

                  END;





                  share|improve this answer













                  Try below Anonymous block for your scenario:



                    create table P_USERS
                  (first_name varchar2(20),
                  last_name varchar2(20),
                  user_id number);

                  insert into P_USERS values ('Tom','Kelly',1);
                  insert into P_USERS values ('Tom','Kelly',2);
                  insert into P_USERS values ('Tom','Kelly',3);
                  insert into P_USERS values ('Tom','Kelly',4);
                  insert into P_USERS values ('Tom','Kelly',5);
                  insert into P_USERS values ('Tom','Ke',6);
                  insert into P_USERS values ('Tom','Ke',7);
                  insert into P_USERS values ('Tom','Ke',8);
                  commit;

                  create table T_MASTER_USERS
                  ( user_id number,
                  PRIMARY_UNIQUE_NAME varchar2(20));

                  insert into T_MASTER_USERS values (1,NULL);
                  insert into T_MASTER_USERS values (2,NULL);
                  insert into T_MASTER_USERS values (3,NULL);
                  insert into T_MASTER_USERS values (4,NULL);
                  insert into T_MASTER_USERS values (5,NULL);
                  insert into T_MASTER_USERS values (6,NULL);
                  insert into T_MASTER_USERS values (7,NULL);
                  insert into T_MASTER_USERS values (8,NULL);
                  commit;


                  DECLARE
                  cursor uniq_grp is SELECT SUBSTR(first_name,1,1)||(last_name) as
                  tempid2 ,count(*) as CNT
                  FROM P_USERS
                  group by SUBSTR(first_name,1,1)||(last_name);

                  cursor concat_names is SELECT SUBSTR(first_name,1,1)||(last_name) as
                  tempid2, user_id
                  FROM P_USERS;

                  V_CNT number;

                  BEGIN

                  FOR C1 in uniq_grp

                  LOOP

                  FOR C2 IN concat_names
                  LOOP
                  IF C2.tempid2=C1.tempid2 THEN
                  V_CNT := c1.CNT -1;
                  UPDATE T_MASTER_USERS SET
                  PRIMARY_UNIQUE_NAME=c2.tempid2||V_CNT WHERE
                  user_id=C2.user_id;
                  c1.cnt := V_CNT;
                  END IF;
                  END LOOP;

                  COMMIT;

                  END LOOP;

                  END;






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 21:08









                  kanagarajkanagaraj

                  31917




                  31917























                      0














                      create or replace procedure generate_unique(par_first_name in varchar2,par_last_name in varchar2)
                      (par_first_name in varchar2,par_last_name in varchar2)

                      is

                      l_username users.username%type;

                      l_letter users.username%type;



                      begin



                       l_username := upper(substr(par_first_name, 1, 1) || par_last_name); 

                      dbms_output.put_line('l_username = ' || l_username );


                      SELECT CASE WHEN MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', '')) IS NULL



                                  THEN l_username 

                      ELSE l_username

                      ||

                      (MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', ''))+1)

                      END into l_letter FROM USERS WHERE REGEXP_LIKE(UPPER(USERNAME),l_username||'[0-9]*$');


                      dbms_output.put_line('unique userid is ' || l_letter);

                      end;






                      share|improve this answer
























                      • Please include an explanation of your code, and fix your code block formatting.

                        – mypetlion
                        Nov 20 '18 at 17:44
















                      0














                      create or replace procedure generate_unique(par_first_name in varchar2,par_last_name in varchar2)
                      (par_first_name in varchar2,par_last_name in varchar2)

                      is

                      l_username users.username%type;

                      l_letter users.username%type;



                      begin



                       l_username := upper(substr(par_first_name, 1, 1) || par_last_name); 

                      dbms_output.put_line('l_username = ' || l_username );


                      SELECT CASE WHEN MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', '')) IS NULL



                                  THEN l_username 

                      ELSE l_username

                      ||

                      (MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', ''))+1)

                      END into l_letter FROM USERS WHERE REGEXP_LIKE(UPPER(USERNAME),l_username||'[0-9]*$');


                      dbms_output.put_line('unique userid is ' || l_letter);

                      end;






                      share|improve this answer
























                      • Please include an explanation of your code, and fix your code block formatting.

                        – mypetlion
                        Nov 20 '18 at 17:44














                      0












                      0








                      0







                      create or replace procedure generate_unique(par_first_name in varchar2,par_last_name in varchar2)
                      (par_first_name in varchar2,par_last_name in varchar2)

                      is

                      l_username users.username%type;

                      l_letter users.username%type;



                      begin



                       l_username := upper(substr(par_first_name, 1, 1) || par_last_name); 

                      dbms_output.put_line('l_username = ' || l_username );


                      SELECT CASE WHEN MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', '')) IS NULL



                                  THEN l_username 

                      ELSE l_username

                      ||

                      (MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', ''))+1)

                      END into l_letter FROM USERS WHERE REGEXP_LIKE(UPPER(USERNAME),l_username||'[0-9]*$');


                      dbms_output.put_line('unique userid is ' || l_letter);

                      end;






                      share|improve this answer













                      create or replace procedure generate_unique(par_first_name in varchar2,par_last_name in varchar2)
                      (par_first_name in varchar2,par_last_name in varchar2)

                      is

                      l_username users.username%type;

                      l_letter users.username%type;



                      begin



                       l_username := upper(substr(par_first_name, 1, 1) || par_last_name); 

                      dbms_output.put_line('l_username = ' || l_username );


                      SELECT CASE WHEN MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', '')) IS NULL



                                  THEN l_username 

                      ELSE l_username

                      ||

                      (MAX(REGEXP_REPLACE(UPPER(USERNAME),'[^0-9]', ''))+1)

                      END into l_letter FROM USERS WHERE REGEXP_LIKE(UPPER(USERNAME),l_username||'[0-9]*$');


                      dbms_output.put_line('unique userid is ' || l_letter);

                      end;







                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Nov 20 '18 at 17:20









                      user10681585user10681585

                      1




                      1













                      • Please include an explanation of your code, and fix your code block formatting.

                        – mypetlion
                        Nov 20 '18 at 17:44



















                      • Please include an explanation of your code, and fix your code block formatting.

                        – mypetlion
                        Nov 20 '18 at 17:44

















                      Please include an explanation of your code, and fix your code block formatting.

                      – mypetlion
                      Nov 20 '18 at 17:44





                      Please include an explanation of your code, and fix your code block formatting.

                      – mypetlion
                      Nov 20 '18 at 17:44


















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