Make the outer layout aware of the current route in react static
My app has a structure like this:
const App = () => (
<Router>
<Layout>
<Routes />
</Layout>
</Router>
)
However, I would like to make the layout depend on the type of page that is loaded.
I know that there is a this.props.location inside the rendered routes, but I cannot access it from the outside.
I read about lifting state up, but I don't know whether that's possible with the <Routes /> component.
How can I get the current route in my Layout component?
reactjs react-router react-static react-static-router
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
add a comment |
My app has a structure like this:
const App = () => (
<Router>
<Layout>
<Routes />
</Layout>
</Router>
)
However, I would like to make the layout depend on the type of page that is loaded.
I know that there is a this.props.location inside the rendered routes, but I cannot access it from the outside.
I read about lifting state up, but I don't know whether that's possible with the <Routes /> component.
How can I get the current route in my Layout component?
reactjs react-router react-static react-static-router
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53
add a comment |
My app has a structure like this:
const App = () => (
<Router>
<Layout>
<Routes />
</Layout>
</Router>
)
However, I would like to make the layout depend on the type of page that is loaded.
I know that there is a this.props.location inside the rendered routes, but I cannot access it from the outside.
I read about lifting state up, but I don't know whether that's possible with the <Routes /> component.
How can I get the current route in my Layout component?
reactjs react-router react-static react-static-router
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
My app has a structure like this:
const App = () => (
<Router>
<Layout>
<Routes />
</Layout>
</Router>
)
However, I would like to make the layout depend on the type of page that is loaded.
I know that there is a this.props.location inside the rendered routes, but I cannot access it from the outside.
I read about lifting state up, but I don't know whether that's possible with the <Routes /> component.
How can I get the current route in my Layout component?
reactjs react-router react-static react-static-router
reactjs react-router react-static react-static-router
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
edited Nov 13 '18 at 15:39
Sung Kim
17.4k33111161
17.4k33111161
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
asked Nov 13 '18 at 15:22
XiphiasXiphias
1,61011227
1,61011227
Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53
add a comment |
Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53
Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53
Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53
add a comment |
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Hi, have you tried using Routes with children render prop like this stackoverflow.com/questions/54055652/…?
– Evgeny Timoshenko
Jan 5 at 19:53