How to make subplots in donut pie chart in matplotlib pyhon
How to make subplots in donut pie chart in matplotlib pyhon?
Below is the code I wrote,
import matplotlib.pyplot as plt
labels = 'Frogs', 'Hogs', 'Dogs'
sizes = [15, 30, 45]
colors = ['yellowgreen', 'gold', 'lightskyblue']
explode = (0, 0, 0) # explode a slice if required
subgroup_names = ['A.1', 'A.2', 'A.3', 'B.1', 'B.2', 'C.1']
subgroup_size = [13, 3, 5, 6, 5, 10]
a, b, c = [plt.cm.Blues, plt.cm.Reds, plt.cm.Greens]
plt.pie(sizes, explode=explode, labels=labels, pctdistance=0.45, labeldistance=0.65, colors=colors, autopct='%.2f%%', shadow=True)
centre_circle = plt.Circle((0, 0), 0.175, color='black', fc='white', linewidth=1.25)
plt.pie(subgroup_size, labels=subgroup_names, pctdistance=0.85, labeldistance=1.25, colors=[a(0.5), a(0.4), a(0.3), b(0.5), b(0.4), c(0.6)], autopct='%.2f%%', shadow=True)
centre_circle2 = plt.Circle((0, 0), 0.275, color='red', fc='white', linewidth=1.25)
fig = plt.gcf()
fig.gca().add_artist(centre_circle)
fig.gca().add_artist(centre_circle2)
plt.axis('equal')
plt.show()
The result shows like below picture,
But I hope the result like below image (have to display the percentage value). This is the result I hope come out(with percentage value):
python matplotlib pie-chart
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
add a comment |
How to make subplots in donut pie chart in matplotlib pyhon?
Below is the code I wrote,
import matplotlib.pyplot as plt
labels = 'Frogs', 'Hogs', 'Dogs'
sizes = [15, 30, 45]
colors = ['yellowgreen', 'gold', 'lightskyblue']
explode = (0, 0, 0) # explode a slice if required
subgroup_names = ['A.1', 'A.2', 'A.3', 'B.1', 'B.2', 'C.1']
subgroup_size = [13, 3, 5, 6, 5, 10]
a, b, c = [plt.cm.Blues, plt.cm.Reds, plt.cm.Greens]
plt.pie(sizes, explode=explode, labels=labels, pctdistance=0.45, labeldistance=0.65, colors=colors, autopct='%.2f%%', shadow=True)
centre_circle = plt.Circle((0, 0), 0.175, color='black', fc='white', linewidth=1.25)
plt.pie(subgroup_size, labels=subgroup_names, pctdistance=0.85, labeldistance=1.25, colors=[a(0.5), a(0.4), a(0.3), b(0.5), b(0.4), c(0.6)], autopct='%.2f%%', shadow=True)
centre_circle2 = plt.Circle((0, 0), 0.275, color='red', fc='white', linewidth=1.25)
fig = plt.gcf()
fig.gca().add_artist(centre_circle)
fig.gca().add_artist(centre_circle2)
plt.axis('equal')
plt.show()
The result shows like below picture,
But I hope the result like below image (have to display the percentage value). This is the result I hope come out(with percentage value):
python matplotlib pie-chart
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10
add a comment |
How to make subplots in donut pie chart in matplotlib pyhon?
Below is the code I wrote,
import matplotlib.pyplot as plt
labels = 'Frogs', 'Hogs', 'Dogs'
sizes = [15, 30, 45]
colors = ['yellowgreen', 'gold', 'lightskyblue']
explode = (0, 0, 0) # explode a slice if required
subgroup_names = ['A.1', 'A.2', 'A.3', 'B.1', 'B.2', 'C.1']
subgroup_size = [13, 3, 5, 6, 5, 10]
a, b, c = [plt.cm.Blues, plt.cm.Reds, plt.cm.Greens]
plt.pie(sizes, explode=explode, labels=labels, pctdistance=0.45, labeldistance=0.65, colors=colors, autopct='%.2f%%', shadow=True)
centre_circle = plt.Circle((0, 0), 0.175, color='black', fc='white', linewidth=1.25)
plt.pie(subgroup_size, labels=subgroup_names, pctdistance=0.85, labeldistance=1.25, colors=[a(0.5), a(0.4), a(0.3), b(0.5), b(0.4), c(0.6)], autopct='%.2f%%', shadow=True)
centre_circle2 = plt.Circle((0, 0), 0.275, color='red', fc='white', linewidth=1.25)
fig = plt.gcf()
fig.gca().add_artist(centre_circle)
fig.gca().add_artist(centre_circle2)
plt.axis('equal')
plt.show()
The result shows like below picture,
But I hope the result like below image (have to display the percentage value). This is the result I hope come out(with percentage value):
python matplotlib pie-chart
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
How to make subplots in donut pie chart in matplotlib pyhon?
Below is the code I wrote,
import matplotlib.pyplot as plt
labels = 'Frogs', 'Hogs', 'Dogs'
sizes = [15, 30, 45]
colors = ['yellowgreen', 'gold', 'lightskyblue']
explode = (0, 0, 0) # explode a slice if required
subgroup_names = ['A.1', 'A.2', 'A.3', 'B.1', 'B.2', 'C.1']
subgroup_size = [13, 3, 5, 6, 5, 10]
a, b, c = [plt.cm.Blues, plt.cm.Reds, plt.cm.Greens]
plt.pie(sizes, explode=explode, labels=labels, pctdistance=0.45, labeldistance=0.65, colors=colors, autopct='%.2f%%', shadow=True)
centre_circle = plt.Circle((0, 0), 0.175, color='black', fc='white', linewidth=1.25)
plt.pie(subgroup_size, labels=subgroup_names, pctdistance=0.85, labeldistance=1.25, colors=[a(0.5), a(0.4), a(0.3), b(0.5), b(0.4), c(0.6)], autopct='%.2f%%', shadow=True)
centre_circle2 = plt.Circle((0, 0), 0.275, color='red', fc='white', linewidth=1.25)
fig = plt.gcf()
fig.gca().add_artist(centre_circle)
fig.gca().add_artist(centre_circle2)
plt.axis('equal')
plt.show()
The result shows like below picture,
But I hope the result like below image (have to display the percentage value). This is the result I hope come out(with percentage value):
python matplotlib pie-chart
python matplotlib pie-chart
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
edited Nov 14 '18 at 10:02
ImportanceOfBeingErnest
129k13138215
129k13138215
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
asked Nov 14 '18 at 4:53
newLearnernewLearner
133
133
There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10
add a comment |
There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10
There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10
There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10
add a comment |
1 Answer
1
active
oldest
votes
Matplotlib documentation has very nice examples for almost everything you can dream of. Please see here for a nested pie chart.
Following the comment on link-only answers, the keyword radius is what you are looking for in your call to pie(). It takes in a float which determines the absolute radius of your pie. Drawing nested pies thereby requires multiple calls to pie(), each with a different value of radius. Please see an example below
import matplotlib.pyplot as plt
plt.pie([1, 2, 3], radius=1,
colors=['xkcd:cerulean', 'xkcd:bright red', 'xkcd:grass green'],
labels=['Group A', 'Group B', 'Group C'], autopct='%.2f%%',
pctdistance=0.85, shadow=True,
wedgeprops=dict(width=0.3, edgecolor='white'))
plt.pie([0.3, 0.7, 0.4, 1.5, 0.1, 3], radius=0.7,
colors=['xkcd:sky blue', 'xkcd:light blue', 'xkcd:reddish pink',
'xkcd:salmon pink', 'xkcd:baby pink', 'xkcd:apple green'],
wedgeprops=dict(width=0.3, edgecolor='white'),
labels=['A.1', 'A.2', 'B.1', 'B.2', 'B.3', 'C.1'], autopct='%.2f%%',
pctdistance=0.8, labeldistance=0.4, shadow=True)
plt.axis('equal')
plt.show()
which returns the following plot
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
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Matplotlib documentation has very nice examples for almost everything you can dream of. Please see here for a nested pie chart.
Following the comment on link-only answers, the keyword radius is what you are looking for in your call to pie(). It takes in a float which determines the absolute radius of your pie. Drawing nested pies thereby requires multiple calls to pie(), each with a different value of radius. Please see an example below
import matplotlib.pyplot as plt
plt.pie([1, 2, 3], radius=1,
colors=['xkcd:cerulean', 'xkcd:bright red', 'xkcd:grass green'],
labels=['Group A', 'Group B', 'Group C'], autopct='%.2f%%',
pctdistance=0.85, shadow=True,
wedgeprops=dict(width=0.3, edgecolor='white'))
plt.pie([0.3, 0.7, 0.4, 1.5, 0.1, 3], radius=0.7,
colors=['xkcd:sky blue', 'xkcd:light blue', 'xkcd:reddish pink',
'xkcd:salmon pink', 'xkcd:baby pink', 'xkcd:apple green'],
wedgeprops=dict(width=0.3, edgecolor='white'),
labels=['A.1', 'A.2', 'B.1', 'B.2', 'B.3', 'C.1'], autopct='%.2f%%',
pctdistance=0.8, labeldistance=0.4, shadow=True)
plt.axis('equal')
plt.show()
which returns the following plot
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
add a comment |
Matplotlib documentation has very nice examples for almost everything you can dream of. Please see here for a nested pie chart.
Following the comment on link-only answers, the keyword radius is what you are looking for in your call to pie(). It takes in a float which determines the absolute radius of your pie. Drawing nested pies thereby requires multiple calls to pie(), each with a different value of radius. Please see an example below
import matplotlib.pyplot as plt
plt.pie([1, 2, 3], radius=1,
colors=['xkcd:cerulean', 'xkcd:bright red', 'xkcd:grass green'],
labels=['Group A', 'Group B', 'Group C'], autopct='%.2f%%',
pctdistance=0.85, shadow=True,
wedgeprops=dict(width=0.3, edgecolor='white'))
plt.pie([0.3, 0.7, 0.4, 1.5, 0.1, 3], radius=0.7,
colors=['xkcd:sky blue', 'xkcd:light blue', 'xkcd:reddish pink',
'xkcd:salmon pink', 'xkcd:baby pink', 'xkcd:apple green'],
wedgeprops=dict(width=0.3, edgecolor='white'),
labels=['A.1', 'A.2', 'B.1', 'B.2', 'B.3', 'C.1'], autopct='%.2f%%',
pctdistance=0.8, labeldistance=0.4, shadow=True)
plt.axis('equal')
plt.show()
which returns the following plot
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
add a comment |
Matplotlib documentation has very nice examples for almost everything you can dream of. Please see here for a nested pie chart.
Following the comment on link-only answers, the keyword radius is what you are looking for in your call to pie(). It takes in a float which determines the absolute radius of your pie. Drawing nested pies thereby requires multiple calls to pie(), each with a different value of radius. Please see an example below
import matplotlib.pyplot as plt
plt.pie([1, 2, 3], radius=1,
colors=['xkcd:cerulean', 'xkcd:bright red', 'xkcd:grass green'],
labels=['Group A', 'Group B', 'Group C'], autopct='%.2f%%',
pctdistance=0.85, shadow=True,
wedgeprops=dict(width=0.3, edgecolor='white'))
plt.pie([0.3, 0.7, 0.4, 1.5, 0.1, 3], radius=0.7,
colors=['xkcd:sky blue', 'xkcd:light blue', 'xkcd:reddish pink',
'xkcd:salmon pink', 'xkcd:baby pink', 'xkcd:apple green'],
wedgeprops=dict(width=0.3, edgecolor='white'),
labels=['A.1', 'A.2', 'B.1', 'B.2', 'B.3', 'C.1'], autopct='%.2f%%',
pctdistance=0.8, labeldistance=0.4, shadow=True)
plt.axis('equal')
plt.show()
which returns the following plot
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
Matplotlib documentation has very nice examples for almost everything you can dream of. Please see here for a nested pie chart.
Following the comment on link-only answers, the keyword radius is what you are looking for in your call to pie(). It takes in a float which determines the absolute radius of your pie. Drawing nested pies thereby requires multiple calls to pie(), each with a different value of radius. Please see an example below
import matplotlib.pyplot as plt
plt.pie([1, 2, 3], radius=1,
colors=['xkcd:cerulean', 'xkcd:bright red', 'xkcd:grass green'],
labels=['Group A', 'Group B', 'Group C'], autopct='%.2f%%',
pctdistance=0.85, shadow=True,
wedgeprops=dict(width=0.3, edgecolor='white'))
plt.pie([0.3, 0.7, 0.4, 1.5, 0.1, 3], radius=0.7,
colors=['xkcd:sky blue', 'xkcd:light blue', 'xkcd:reddish pink',
'xkcd:salmon pink', 'xkcd:baby pink', 'xkcd:apple green'],
wedgeprops=dict(width=0.3, edgecolor='white'),
labels=['A.1', 'A.2', 'B.1', 'B.2', 'B.3', 'C.1'], autopct='%.2f%%',
pctdistance=0.8, labeldistance=0.4, shadow=True)
plt.axis('equal')
plt.show()
which returns the following plot
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
edited Nov 15 '18 at 10:11
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
answered Nov 14 '18 at 5:03
Patol75Patol75
6236
6236
add a comment |
add a comment |
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There is an example for nested charts in the documentation. Can you apply it here and then ask for the remaining problem?
– ImportanceOfBeingErnest
Nov 14 '18 at 10:10