how to change the regularization parameter in keras layer without rebuild a new model in R











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I want to fine tuning my L2 parameter in my last keras layer using a for loop approach. My target is build a Extreme Machine Learning model. Now, I'm using the code below:



#possible values for L2... 
k = 2^(seq(-20,-1,1))

#vectors with metrics
acc_vector = vector('numeric',length(k))
loss_vector = vector('numeric',length(k))

for(i in seq_along(k)){

model0 = keras_model_sequential() %>%
layer_dense(units = 500,activation = 'relu',input_shape = c(784),
trainable = F,name = 'dense1') %>%
layer_dense(units = 10, activation = 'softmax',
kernel_regularizer = regularizer_l2(k[i]),name='dense2') %>%
compile(loss = 'categorical_crossentropy',optimizer = optimizer_rmsprop(),
metrics = c('accuracy'))

model0 %>% fit(
x_train, y_train,
epochs = 5, batch_size = 512,
validation_split = 0.2,verbose=0)

eval = model0 %>% evaluate(x_test, y_test)

acc_vector[i] = eval$acc
loss_vector[i] = eval$loss

#I don't know why, but without the next 2 lines, my memory usage increase 2 times
rm(model0,eval)
gc()
}


So, here is my problem. With this aproach (run fast, at least), my weights start by random in each loop and the value of L2 doesn't make any sense. I tried other approachs like include weights = "weights" in the first layer and worked fine, except by the process time... it increased a lot! After this, I tried to pop the last layer and add a new layer with the new L2 as follow:



model0 = keras_model_sequential() %>% 
layer_dense(units = 500,activation = 'relu',input_shape = c(784),
trainable = F,name = 'dense1') %>%
layer_dense(units = 10, activation = 'softmax',
kernel_regularizer = regularizer_l2('any value'),name='dense2')

for(i in seq_along(k)){
model0 %>% pop_layer() %>%
layer_dense(units = 10, activation = 'softmax',
kernel_regularizer = regularizer_l2(k[i]),name='dense2')
}


But doesn't work. The behavior of the last approach makes the models have just the first layer. I just want change the value of L2 to retrain the last layer of my model. How can I do that in a simple way?










share|improve this question


























    up vote
    0
    down vote

    favorite












    I want to fine tuning my L2 parameter in my last keras layer using a for loop approach. My target is build a Extreme Machine Learning model. Now, I'm using the code below:



    #possible values for L2... 
    k = 2^(seq(-20,-1,1))

    #vectors with metrics
    acc_vector = vector('numeric',length(k))
    loss_vector = vector('numeric',length(k))

    for(i in seq_along(k)){

    model0 = keras_model_sequential() %>%
    layer_dense(units = 500,activation = 'relu',input_shape = c(784),
    trainable = F,name = 'dense1') %>%
    layer_dense(units = 10, activation = 'softmax',
    kernel_regularizer = regularizer_l2(k[i]),name='dense2') %>%
    compile(loss = 'categorical_crossentropy',optimizer = optimizer_rmsprop(),
    metrics = c('accuracy'))

    model0 %>% fit(
    x_train, y_train,
    epochs = 5, batch_size = 512,
    validation_split = 0.2,verbose=0)

    eval = model0 %>% evaluate(x_test, y_test)

    acc_vector[i] = eval$acc
    loss_vector[i] = eval$loss

    #I don't know why, but without the next 2 lines, my memory usage increase 2 times
    rm(model0,eval)
    gc()
    }


    So, here is my problem. With this aproach (run fast, at least), my weights start by random in each loop and the value of L2 doesn't make any sense. I tried other approachs like include weights = "weights" in the first layer and worked fine, except by the process time... it increased a lot! After this, I tried to pop the last layer and add a new layer with the new L2 as follow:



    model0 = keras_model_sequential() %>% 
    layer_dense(units = 500,activation = 'relu',input_shape = c(784),
    trainable = F,name = 'dense1') %>%
    layer_dense(units = 10, activation = 'softmax',
    kernel_regularizer = regularizer_l2('any value'),name='dense2')

    for(i in seq_along(k)){
    model0 %>% pop_layer() %>%
    layer_dense(units = 10, activation = 'softmax',
    kernel_regularizer = regularizer_l2(k[i]),name='dense2')
    }


    But doesn't work. The behavior of the last approach makes the models have just the first layer. I just want change the value of L2 to retrain the last layer of my model. How can I do that in a simple way?










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I want to fine tuning my L2 parameter in my last keras layer using a for loop approach. My target is build a Extreme Machine Learning model. Now, I'm using the code below:



      #possible values for L2... 
      k = 2^(seq(-20,-1,1))

      #vectors with metrics
      acc_vector = vector('numeric',length(k))
      loss_vector = vector('numeric',length(k))

      for(i in seq_along(k)){

      model0 = keras_model_sequential() %>%
      layer_dense(units = 500,activation = 'relu',input_shape = c(784),
      trainable = F,name = 'dense1') %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2(k[i]),name='dense2') %>%
      compile(loss = 'categorical_crossentropy',optimizer = optimizer_rmsprop(),
      metrics = c('accuracy'))

      model0 %>% fit(
      x_train, y_train,
      epochs = 5, batch_size = 512,
      validation_split = 0.2,verbose=0)

      eval = model0 %>% evaluate(x_test, y_test)

      acc_vector[i] = eval$acc
      loss_vector[i] = eval$loss

      #I don't know why, but without the next 2 lines, my memory usage increase 2 times
      rm(model0,eval)
      gc()
      }


      So, here is my problem. With this aproach (run fast, at least), my weights start by random in each loop and the value of L2 doesn't make any sense. I tried other approachs like include weights = "weights" in the first layer and worked fine, except by the process time... it increased a lot! After this, I tried to pop the last layer and add a new layer with the new L2 as follow:



      model0 = keras_model_sequential() %>% 
      layer_dense(units = 500,activation = 'relu',input_shape = c(784),
      trainable = F,name = 'dense1') %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2('any value'),name='dense2')

      for(i in seq_along(k)){
      model0 %>% pop_layer() %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2(k[i]),name='dense2')
      }


      But doesn't work. The behavior of the last approach makes the models have just the first layer. I just want change the value of L2 to retrain the last layer of my model. How can I do that in a simple way?










      share|improve this question













      I want to fine tuning my L2 parameter in my last keras layer using a for loop approach. My target is build a Extreme Machine Learning model. Now, I'm using the code below:



      #possible values for L2... 
      k = 2^(seq(-20,-1,1))

      #vectors with metrics
      acc_vector = vector('numeric',length(k))
      loss_vector = vector('numeric',length(k))

      for(i in seq_along(k)){

      model0 = keras_model_sequential() %>%
      layer_dense(units = 500,activation = 'relu',input_shape = c(784),
      trainable = F,name = 'dense1') %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2(k[i]),name='dense2') %>%
      compile(loss = 'categorical_crossentropy',optimizer = optimizer_rmsprop(),
      metrics = c('accuracy'))

      model0 %>% fit(
      x_train, y_train,
      epochs = 5, batch_size = 512,
      validation_split = 0.2,verbose=0)

      eval = model0 %>% evaluate(x_test, y_test)

      acc_vector[i] = eval$acc
      loss_vector[i] = eval$loss

      #I don't know why, but without the next 2 lines, my memory usage increase 2 times
      rm(model0,eval)
      gc()
      }


      So, here is my problem. With this aproach (run fast, at least), my weights start by random in each loop and the value of L2 doesn't make any sense. I tried other approachs like include weights = "weights" in the first layer and worked fine, except by the process time... it increased a lot! After this, I tried to pop the last layer and add a new layer with the new L2 as follow:



      model0 = keras_model_sequential() %>% 
      layer_dense(units = 500,activation = 'relu',input_shape = c(784),
      trainable = F,name = 'dense1') %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2('any value'),name='dense2')

      for(i in seq_along(k)){
      model0 %>% pop_layer() %>%
      layer_dense(units = 10, activation = 'softmax',
      kernel_regularizer = regularizer_l2(k[i]),name='dense2')
      }


      But doesn't work. The behavior of the last approach makes the models have just the first layer. I just want change the value of L2 to retrain the last layer of my model. How can I do that in a simple way?







      r keras






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      asked Nov 11 at 18:10









      brunoroquette

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