Vfrdtyky

How can I code, in OCaml, something like this (main() in C)

for (i=0; i<y; i++)

    if (x==5)

    {

        y=i;

        return true;

    }

It would return the boolean True and y would be equal to the corresponding i value.

Basically, in OCaml, I was wondering if you could have a if like:

for i=0 to y-1 do

        if x=5 then

        begin 

            y=i

            true

        end

        else ()

done;;

I know the lines between begin-end aren't correctly implemented. I don't even know if what I want to do is possible in OCaml. If you are someone who has knowledge on this kindly share it with me. Thanks!

If your question is about early return from a for loop, this is how you'd it:

exception Break of int



let n =

  try

    for i = 0 to 5 do

      if i mod 2 = 0 then

        raise (Break i)

    done;

    0

  with

    Break i -> i

You could also assign to a ref cell instead of passing the value in the exception, if that fits your use case better. But this isn't the kind of code you should typically be writing in OCaml. Trying to emulate C in OCaml is almost always a bad idea.