how to print every fifth row in a file
I have a file with numbers
20
18
21
16
14
30
40
24
and I need to output four files with rows printed with intervals of 4
So we have rows 1,5,9...
20
14
Then rows 2,6,10...
18
30
Then 3,7,11...
21
40
and then 4,8,12...
16
24
I did try the code below but it does not give me the control over the starting row
awk 'NR % 4 == 0'
bash awk sed
edited Nov 14 '18 at 17:34
kvantour
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
add a comment |
I have a file with numbers
20
18
21
16
14
30
40
24
and I need to output four files with rows printed with intervals of 4
So we have rows 1,5,9...
20
14
Then rows 2,6,10...
18
30
Then 3,7,11...
21
40
and then 4,8,12...
16
24
I did try the code below but it does not give me the control over the starting row
awk 'NR % 4 == 0'
bash awk sed
edited Nov 14 '18 at 17:34
kvantour
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
add a comment |
I have a file with numbers
20
18
21
16
14
30
40
24
and I need to output four files with rows printed with intervals of 4
So we have rows 1,5,9...
20
14
Then rows 2,6,10...
18
30
Then 3,7,11...
21
40
and then 4,8,12...
16
24
I did try the code below but it does not give me the control over the starting row
awk 'NR % 4 == 0'
bash awk sed
edited Nov 14 '18 at 17:34
kvantour
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
I have a file with numbers
20
18
21
16
14
30
40
24
and I need to output four files with rows printed with intervals of 4
So we have rows 1,5,9...
20
14
Then rows 2,6,10...
18
30
Then 3,7,11...
21
40
and then 4,8,12...
16
24
I did try the code below but it does not give me the control over the starting row
awk 'NR % 4 == 0'
bash awk sed
bash awk sed
edited Nov 14 '18 at 17:34
kvantour
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
edited Nov 14 '18 at 17:34
kvantour
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
edited Nov 14 '18 at 17:34
kvantour
9,66831731
edited Nov 14 '18 at 17:34
kvantour
9,66831731
edited Nov 14 '18 at 17:34
kvantour
9,66831731
9,66831731
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
asked Nov 14 '18 at 17:05
vkaul11vkaul11
1,40343053
1,40343053
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
In a single awk you can do:
awk '{print > ("file" (NR%4))}' inputfile
This will send the output to files file0, file1, file2 and file3
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
add a comment |
You may use these awk commands:
awk -v n=1 'NR%4 == n%4' file
20
14
awk -v n=2 'NR%4 == n%4' file
18
30
awk -v n=3 'NR%4 == n%4' file
21
40
awk -v n=4 'NR%4 == n%4' file
16
24
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
add a comment |
IMHO awk is the best solution. You can use sed:
Inputfile generated with seq 12:
for ((i=1;i<5; i++)); do
sed -n $i~4w$i.out <(seq 12)
done
Here w$i.out writes to file $i.out.
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
add a comment |
This might work for you (GNU sed):
sed -ne '1~4w file1' -e '2~4w file2' -e '3~4w file3' -e '4~4w file4' file
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
In a single awk you can do:
awk '{print > ("file" (NR%4))}' inputfile
This will send the output to files file0, file1, file2 and file3
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
add a comment |
In a single awk you can do:
awk '{print > ("file" (NR%4))}' inputfile
This will send the output to files file0, file1, file2 and file3
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
add a comment |
In a single awk you can do:
awk '{print > ("file" (NR%4))}' inputfile
This will send the output to files file0, file1, file2 and file3
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
In a single awk you can do:
awk '{print > ("file" (NR%4))}' inputfile
This will send the output to files file0, file1, file2 and file3
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
answered Nov 14 '18 at 17:29
kvantourkvantour
9,66831731
9,66831731
add a comment |
add a comment |
You may use these awk commands:
awk -v n=1 'NR%4 == n%4' file
20
14
awk -v n=2 'NR%4 == n%4' file
18
30
awk -v n=3 'NR%4 == n%4' file
21
40
awk -v n=4 'NR%4 == n%4' file
16
24
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
add a comment |
You may use these awk commands:
awk -v n=1 'NR%4 == n%4' file
20
14
awk -v n=2 'NR%4 == n%4' file
18
30
awk -v n=3 'NR%4 == n%4' file
21
40
awk -v n=4 'NR%4 == n%4' file
16
24
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
add a comment |
You may use these awk commands:
awk -v n=1 'NR%4 == n%4' file
20
14
awk -v n=2 'NR%4 == n%4' file
18
30
awk -v n=3 'NR%4 == n%4' file
21
40
awk -v n=4 'NR%4 == n%4' file
16
24
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
You may use these awk commands:
awk -v n=1 'NR%4 == n%4' file
20
14
awk -v n=2 'NR%4 == n%4' file
18
30
awk -v n=3 'NR%4 == n%4' file
21
40
awk -v n=4 'NR%4 == n%4' file
16
24
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
answered Nov 14 '18 at 17:11
anubhavaanubhava
532k47331408
532k47331408
add a comment |
add a comment |
IMHO awk is the best solution. You can use sed:
Inputfile generated with seq 12:
for ((i=1;i<5; i++)); do
sed -n $i~4w$i.out <(seq 12)
done
Here w$i.out writes to file $i.out.
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
add a comment |
IMHO awk is the best solution. You can use sed:
Inputfile generated with seq 12:
for ((i=1;i<5; i++)); do
sed -n $i~4w$i.out <(seq 12)
done
Here w$i.out writes to file $i.out.
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
add a comment |
IMHO awk is the best solution. You can use sed:
Inputfile generated with seq 12:
for ((i=1;i<5; i++)); do
sed -n $i~4w$i.out <(seq 12)
done
Here w$i.out writes to file $i.out.
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
IMHO awk is the best solution. You can use sed:
Inputfile generated with seq 12:
for ((i=1;i<5; i++)); do
sed -n $i~4w$i.out <(seq 12)
done
Here w$i.out writes to file $i.out.
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
answered Nov 14 '18 at 20:50
Walter AWalter A
11k21132
11k21132
add a comment |
add a comment |
This might work for you (GNU sed):
sed -ne '1~4w file1' -e '2~4w file2' -e '3~4w file3' -e '4~4w file4' file
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
add a comment |
This might work for you (GNU sed):
sed -ne '1~4w file1' -e '2~4w file2' -e '3~4w file3' -e '4~4w file4' file
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
add a comment |
This might work for you (GNU sed):
sed -ne '1~4w file1' -e '2~4w file2' -e '3~4w file3' -e '4~4w file4' file
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
This might work for you (GNU sed):
sed -ne '1~4w file1' -e '2~4w file2' -e '3~4w file3' -e '4~4w file4' file
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
answered Nov 16 '18 at 1:48
potongpotong
36.2k43062
36.2k43062
add a comment |
add a comment |
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