IL code to call method with out parameter
I want to IL generate a dynamic method
delegate ArraySegment<byte> X(MyClass mc);
that calls a method of the signature on mc and returns its out parameter.
MethodInfo methInf = aClass.GetMethod("Y",
BindingFlags.Public | BindingFlags.Instance,
null, new { typeof(ArraySegment<byte>).MakeByRefType() }, null);
but I don't know how to handle the out parameter. Here's the code I have so far.
DynamicMethod dm = new DynamicMethod("X", typeof(ArraySegment<byte>),
new { typeof(MyClass) });
ILGenerator il = dm.GetILGenerator();
il.Emit(OpCodes.Ldarg_0);
il.EmitCall(OpCodes.Callvirt, methInf, null);
What's needed to make the out param work?
c# cil emit out-parameters ilgenerator
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
add a comment |
I want to IL generate a dynamic method
delegate ArraySegment<byte> X(MyClass mc);
that calls a method of the signature on mc and returns its out parameter.
MethodInfo methInf = aClass.GetMethod("Y",
BindingFlags.Public | BindingFlags.Instance,
null, new { typeof(ArraySegment<byte>).MakeByRefType() }, null);
but I don't know how to handle the out parameter. Here's the code I have so far.
DynamicMethod dm = new DynamicMethod("X", typeof(ArraySegment<byte>),
new { typeof(MyClass) });
ILGenerator il = dm.GetILGenerator();
il.Emit(OpCodes.Ldarg_0);
il.EmitCall(OpCodes.Callvirt, methInf, null);
What's needed to make the out param work?
c# cil emit out-parameters ilgenerator
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
Just to clarify, your question is about how to emit a call to a method featuring anoutparameter?
– elgonzo
Nov 12 '18 at 23:55
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
refandoutare actually identical to the CLR. They only differ by how the compiler enforces that code sets anoutbefore the method returns.
– Crowcoder
Nov 13 '18 at 0:39
add a comment |
I want to IL generate a dynamic method
delegate ArraySegment<byte> X(MyClass mc);
that calls a method of the signature on mc and returns its out parameter.
MethodInfo methInf = aClass.GetMethod("Y",
BindingFlags.Public | BindingFlags.Instance,
null, new { typeof(ArraySegment<byte>).MakeByRefType() }, null);
but I don't know how to handle the out parameter. Here's the code I have so far.
DynamicMethod dm = new DynamicMethod("X", typeof(ArraySegment<byte>),
new { typeof(MyClass) });
ILGenerator il = dm.GetILGenerator();
il.Emit(OpCodes.Ldarg_0);
il.EmitCall(OpCodes.Callvirt, methInf, null);
What's needed to make the out param work?
c# cil emit out-parameters ilgenerator
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
I want to IL generate a dynamic method
delegate ArraySegment<byte> X(MyClass mc);
that calls a method of the signature on mc and returns its out parameter.
MethodInfo methInf = aClass.GetMethod("Y",
BindingFlags.Public | BindingFlags.Instance,
null, new { typeof(ArraySegment<byte>).MakeByRefType() }, null);
but I don't know how to handle the out parameter. Here's the code I have so far.
DynamicMethod dm = new DynamicMethod("X", typeof(ArraySegment<byte>),
new { typeof(MyClass) });
ILGenerator il = dm.GetILGenerator();
il.Emit(OpCodes.Ldarg_0);
il.EmitCall(OpCodes.Callvirt, methInf, null);
What's needed to make the out param work?
c# cil emit out-parameters ilgenerator
c# cil emit out-parameters ilgenerator
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
edited Nov 13 '18 at 0:56
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
asked Nov 12 '18 at 23:48
Eugene Beresovsky
10.8k660110
10.8k660110
Just to clarify, your question is about how to emit a call to a method featuring anoutparameter?
– elgonzo
Nov 12 '18 at 23:55
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
refandoutare actually identical to the CLR. They only differ by how the compiler enforces that code sets anoutbefore the method returns.
– Crowcoder
Nov 13 '18 at 0:39
add a comment |
Just to clarify, your question is about how to emit a call to a method featuring anoutparameter?
– elgonzo
Nov 12 '18 at 23:55
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
refandoutare actually identical to the CLR. They only differ by how the compiler enforces that code sets anoutbefore the method returns.
– Crowcoder
Nov 13 '18 at 0:39
Just to clarify, your question is about how to emit a call to a method featuring an
out parameter?– elgonzo
Nov 12 '18 at 23:55
Just to clarify, your question is about how to emit a call to a method featuring an
out parameter?– elgonzo
Nov 12 '18 at 23:55
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
ref and out are actually identical to the CLR. They only differ by how the compiler enforces that code sets an out before the method returns.– Crowcoder
Nov 13 '18 at 0:39
ref and out are actually identical to the CLR. They only differ by how the compiler enforces that code sets an out before the method returns.– Crowcoder
Nov 13 '18 at 0:39
add a comment |
1 Answer
1
active
oldest
votes
Thanks @MarcGravell (also for your deleted answer, which was of great help, as it spells out what you hint at in your comment to my question) and ILSpy, which helped me by compiling c# code to CIL, so I could just peek at that.
So here's the final, working code:
LocalBuilder local = il.DeclareLocal(typeof(ArraySegment<byte>));
il.Emit(OpCodes.Ldarg_0);
il.Emit(OpCodes.Ldloca, local);
il.EmitCall(OpCodes.Callvirt, methInf, null);
il.Emit(OpCodes.Pop);
il.Emit(OpCodes.Ldloc, local.LocalIndex);
il.Emit(OpCodes.Ret);
Invoking this is 10 times faster than doing methodInfo.Invoke(...) (on a methodInfo object that was created only once, of course).
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks @MarcGravell (also for your deleted answer, which was of great help, as it spells out what you hint at in your comment to my question) and ILSpy, which helped me by compiling c# code to CIL, so I could just peek at that.
So here's the final, working code:
LocalBuilder local = il.DeclareLocal(typeof(ArraySegment<byte>));
il.Emit(OpCodes.Ldarg_0);
il.Emit(OpCodes.Ldloca, local);
il.EmitCall(OpCodes.Callvirt, methInf, null);
il.Emit(OpCodes.Pop);
il.Emit(OpCodes.Ldloc, local.LocalIndex);
il.Emit(OpCodes.Ret);
Invoking this is 10 times faster than doing methodInfo.Invoke(...) (on a methodInfo object that was created only once, of course).
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
add a comment |
Thanks @MarcGravell (also for your deleted answer, which was of great help, as it spells out what you hint at in your comment to my question) and ILSpy, which helped me by compiling c# code to CIL, so I could just peek at that.
So here's the final, working code:
LocalBuilder local = il.DeclareLocal(typeof(ArraySegment<byte>));
il.Emit(OpCodes.Ldarg_0);
il.Emit(OpCodes.Ldloca, local);
il.EmitCall(OpCodes.Callvirt, methInf, null);
il.Emit(OpCodes.Pop);
il.Emit(OpCodes.Ldloc, local.LocalIndex);
il.Emit(OpCodes.Ret);
Invoking this is 10 times faster than doing methodInfo.Invoke(...) (on a methodInfo object that was created only once, of course).
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
add a comment |
Thanks @MarcGravell (also for your deleted answer, which was of great help, as it spells out what you hint at in your comment to my question) and ILSpy, which helped me by compiling c# code to CIL, so I could just peek at that.
So here's the final, working code:
LocalBuilder local = il.DeclareLocal(typeof(ArraySegment<byte>));
il.Emit(OpCodes.Ldarg_0);
il.Emit(OpCodes.Ldloca, local);
il.EmitCall(OpCodes.Callvirt, methInf, null);
il.Emit(OpCodes.Pop);
il.Emit(OpCodes.Ldloc, local.LocalIndex);
il.Emit(OpCodes.Ret);
Invoking this is 10 times faster than doing methodInfo.Invoke(...) (on a methodInfo object that was created only once, of course).
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
Thanks @MarcGravell (also for your deleted answer, which was of great help, as it spells out what you hint at in your comment to my question) and ILSpy, which helped me by compiling c# code to CIL, so I could just peek at that.
So here's the final, working code:
LocalBuilder local = il.DeclareLocal(typeof(ArraySegment<byte>));
il.Emit(OpCodes.Ldarg_0);
il.Emit(OpCodes.Ldloca, local);
il.EmitCall(OpCodes.Callvirt, methInf, null);
il.Emit(OpCodes.Pop);
il.Emit(OpCodes.Ldloc, local.LocalIndex);
il.Emit(OpCodes.Ret);
Invoking this is 10 times faster than doing methodInfo.Invoke(...) (on a methodInfo object that was created only once, of course).
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
edited Nov 13 '18 at 1:06
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
answered Nov 13 '18 at 0:56
Eugene Beresovsky
10.8k660110
10.8k660110
add a comment |
add a comment |
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Just to clarify, your question is about how to emit a call to a method featuring an
outparameter?– elgonzo
Nov 12 '18 at 23:55
Since the parameter is already a ref type, you should just have to load the parameter (which is a reference) - whether that is arg0 or arg1 depends on instance vs static
– Marc Gravell♦
Nov 13 '18 at 0:05
refandoutare actually identical to the CLR. They only differ by how the compiler enforces that code sets anoutbefore the method returns.– Crowcoder
Nov 13 '18 at 0:39