C allocating char array causing bad access runtime exception












0















I seem to be having trouble correctly allocating memory for my array. The method is returning as expected, but a runtime exception is killing the program.



I got this exception while using my debugger.



EXC_BAD_ACCESS (code=1, address=0x0)


This is the method causing the issue:



char *progScanner(char *line){

char originalLine[100];
strcpy(originalLine, line);
char *correctLine[100];
char *segment;
int i = 0;

segment = strtok(originalLine," ,()");
while (segment != NULL){
printf (" %s",segment);
correctLine[i++] = segment;
segment = strtok (NULL, " ,()");
}

char *newLine;
newLine = malloc(100 * sizeof(char));
int j = 1;
strcpy (newLine, correctLine[0]);
while(j<=i){
strcat(newLine, correctLine[j]);
j++;
}

return newLine;
}









share|improve this question























  • Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

    – Barmar
    Nov 13 '18 at 22:14











  • The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

    – Barmar
    Nov 13 '18 at 22:15






  • 2





    while(j<=i) should be while(j<i).

    – Barmar
    Nov 13 '18 at 22:17






  • 1





    Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

    – Christian Gibbons
    Nov 13 '18 at 22:36













  • @Barmar you're right, please leave an answer. Can't believe I missed that for so long.

    – Voxorin
    Nov 13 '18 at 23:38
















0















I seem to be having trouble correctly allocating memory for my array. The method is returning as expected, but a runtime exception is killing the program.



I got this exception while using my debugger.



EXC_BAD_ACCESS (code=1, address=0x0)


This is the method causing the issue:



char *progScanner(char *line){

char originalLine[100];
strcpy(originalLine, line);
char *correctLine[100];
char *segment;
int i = 0;

segment = strtok(originalLine," ,()");
while (segment != NULL){
printf (" %s",segment);
correctLine[i++] = segment;
segment = strtok (NULL, " ,()");
}

char *newLine;
newLine = malloc(100 * sizeof(char));
int j = 1;
strcpy (newLine, correctLine[0]);
while(j<=i){
strcat(newLine, correctLine[j]);
j++;
}

return newLine;
}









share|improve this question























  • Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

    – Barmar
    Nov 13 '18 at 22:14











  • The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

    – Barmar
    Nov 13 '18 at 22:15






  • 2





    while(j<=i) should be while(j<i).

    – Barmar
    Nov 13 '18 at 22:17






  • 1





    Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

    – Christian Gibbons
    Nov 13 '18 at 22:36













  • @Barmar you're right, please leave an answer. Can't believe I missed that for so long.

    – Voxorin
    Nov 13 '18 at 23:38














0












0








0








I seem to be having trouble correctly allocating memory for my array. The method is returning as expected, but a runtime exception is killing the program.



I got this exception while using my debugger.



EXC_BAD_ACCESS (code=1, address=0x0)


This is the method causing the issue:



char *progScanner(char *line){

char originalLine[100];
strcpy(originalLine, line);
char *correctLine[100];
char *segment;
int i = 0;

segment = strtok(originalLine," ,()");
while (segment != NULL){
printf (" %s",segment);
correctLine[i++] = segment;
segment = strtok (NULL, " ,()");
}

char *newLine;
newLine = malloc(100 * sizeof(char));
int j = 1;
strcpy (newLine, correctLine[0]);
while(j<=i){
strcat(newLine, correctLine[j]);
j++;
}

return newLine;
}









share|improve this question














I seem to be having trouble correctly allocating memory for my array. The method is returning as expected, but a runtime exception is killing the program.



I got this exception while using my debugger.



EXC_BAD_ACCESS (code=1, address=0x0)


This is the method causing the issue:



char *progScanner(char *line){

char originalLine[100];
strcpy(originalLine, line);
char *correctLine[100];
char *segment;
int i = 0;

segment = strtok(originalLine," ,()");
while (segment != NULL){
printf (" %s",segment);
correctLine[i++] = segment;
segment = strtok (NULL, " ,()");
}

char *newLine;
newLine = malloc(100 * sizeof(char));
int j = 1;
strcpy (newLine, correctLine[0]);
while(j<=i){
strcat(newLine, correctLine[j]);
j++;
}

return newLine;
}






c memory-management runtime






share|improve this question













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asked Nov 13 '18 at 22:08









VoxorinVoxorin

177




177













  • Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

    – Barmar
    Nov 13 '18 at 22:14











  • The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

    – Barmar
    Nov 13 '18 at 22:15






  • 2





    while(j<=i) should be while(j<i).

    – Barmar
    Nov 13 '18 at 22:17






  • 1





    Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

    – Christian Gibbons
    Nov 13 '18 at 22:36













  • @Barmar you're right, please leave an answer. Can't believe I missed that for so long.

    – Voxorin
    Nov 13 '18 at 23:38



















  • Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

    – Barmar
    Nov 13 '18 at 22:14











  • The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

    – Barmar
    Nov 13 '18 at 22:15






  • 2





    while(j<=i) should be while(j<i).

    – Barmar
    Nov 13 '18 at 22:17






  • 1





    Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

    – Christian Gibbons
    Nov 13 '18 at 22:36













  • @Barmar you're right, please leave an answer. Can't believe I missed that for so long.

    – Voxorin
    Nov 13 '18 at 23:38

















Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

– Barmar
Nov 13 '18 at 22:14





Are you sure the original line is less than 100 characters long? If it's longer, you'll cause undefined behavior.

– Barmar
Nov 13 '18 at 22:14













The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

– Barmar
Nov 13 '18 at 22:15





The error indicates that you're trying to dereference a null pointer. Step through the code with a debugger to see where this is happening.

– Barmar
Nov 13 '18 at 22:15




2




2





while(j<=i) should be while(j<i).

– Barmar
Nov 13 '18 at 22:17





while(j<=i) should be while(j<i).

– Barmar
Nov 13 '18 at 22:17




1




1





Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

– Christian Gibbons
Nov 13 '18 at 22:36







Unrelated, but the use of strcat in a loop like this is a textbook case of Schlemiel The Painter. joelonsoftware.com/2001/12/11/back-to-basics

– Christian Gibbons
Nov 13 '18 at 22:36















@Barmar you're right, please leave an answer. Can't believe I missed that for so long.

– Voxorin
Nov 13 '18 at 23:38





@Barmar you're right, please leave an answer. Can't believe I missed that for so long.

– Voxorin
Nov 13 '18 at 23:38












1 Answer
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You're accessing outside the correctLine array when you get to j == i, because the last valid index in correctLine is j-1. Change



while(j<=i){


to



while(j<i){





share|improve this answer























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    active

    oldest

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    0














    You're accessing outside the correctLine array when you get to j == i, because the last valid index in correctLine is j-1. Change



    while(j<=i){


    to



    while(j<i){





    share|improve this answer




























      0














      You're accessing outside the correctLine array when you get to j == i, because the last valid index in correctLine is j-1. Change



      while(j<=i){


      to



      while(j<i){





      share|improve this answer


























        0












        0








        0







        You're accessing outside the correctLine array when you get to j == i, because the last valid index in correctLine is j-1. Change



        while(j<=i){


        to



        while(j<i){





        share|improve this answer













        You're accessing outside the correctLine array when you get to j == i, because the last valid index in correctLine is j-1. Change



        while(j<=i){


        to



        while(j<i){






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 14 '18 at 6:10









        BarmarBarmar

        423k35248348




        423k35248348






























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