Get the Count of Concatenating Column in sql











up vote
1
down vote

favorite
2












i have Concatenating the multiple Columns and i want the count of how many columns are Concatenated



the query output and expected output are



for Concatenation



select  ConcateColumn = STUFF(
COALESCE('* ' + RTRIM(col1),'')
+COALESCE('* ' + RTRIM(col2),'')
+COALESCE('* ' + RTRIM(col4),'')
+COALESCE('* ' + RTRIM(col3),'')
, 1, 2, '')


table



===================================
| col1 | col2 | col3 | col4 |
===================================
| 1 | 2 | NULL | NULL |
| NULL | NULL | NULL | NULL |
| 1 | NULL | NULL | NULL |
| NULL | 2 | 3 | 4 |
| | NULL | NULL | NULL |
==================================


the resulted output



 ==============
|ConcateColumn|
==============
|1*2 |
|NULL |
|1 |
|2*3*4 |
| |
===============


Expected Output



------------------------
| Count | ConcateColumn |
-------------------------
| 2 | 1*2 |
| 0 | NULL |
| 1 | 1 |
| 3 | 2*3*4 |
| 0 | |
-------------------------


if i get the count that is more than enough










share|improve this question






















  • Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
    – Martin Parkin
    Nov 11 at 10:59










  • please note that the no of columns are dynamic
    – Ramapriyan C
    Nov 11 at 10:59















up vote
1
down vote

favorite
2












i have Concatenating the multiple Columns and i want the count of how many columns are Concatenated



the query output and expected output are



for Concatenation



select  ConcateColumn = STUFF(
COALESCE('* ' + RTRIM(col1),'')
+COALESCE('* ' + RTRIM(col2),'')
+COALESCE('* ' + RTRIM(col4),'')
+COALESCE('* ' + RTRIM(col3),'')
, 1, 2, '')


table



===================================
| col1 | col2 | col3 | col4 |
===================================
| 1 | 2 | NULL | NULL |
| NULL | NULL | NULL | NULL |
| 1 | NULL | NULL | NULL |
| NULL | 2 | 3 | 4 |
| | NULL | NULL | NULL |
==================================


the resulted output



 ==============
|ConcateColumn|
==============
|1*2 |
|NULL |
|1 |
|2*3*4 |
| |
===============


Expected Output



------------------------
| Count | ConcateColumn |
-------------------------
| 2 | 1*2 |
| 0 | NULL |
| 1 | 1 |
| 3 | 2*3*4 |
| 0 | |
-------------------------


if i get the count that is more than enough










share|improve this question






















  • Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
    – Martin Parkin
    Nov 11 at 10:59










  • please note that the no of columns are dynamic
    – Ramapriyan C
    Nov 11 at 10:59













up vote
1
down vote

favorite
2









up vote
1
down vote

favorite
2






2





i have Concatenating the multiple Columns and i want the count of how many columns are Concatenated



the query output and expected output are



for Concatenation



select  ConcateColumn = STUFF(
COALESCE('* ' + RTRIM(col1),'')
+COALESCE('* ' + RTRIM(col2),'')
+COALESCE('* ' + RTRIM(col4),'')
+COALESCE('* ' + RTRIM(col3),'')
, 1, 2, '')


table



===================================
| col1 | col2 | col3 | col4 |
===================================
| 1 | 2 | NULL | NULL |
| NULL | NULL | NULL | NULL |
| 1 | NULL | NULL | NULL |
| NULL | 2 | 3 | 4 |
| | NULL | NULL | NULL |
==================================


the resulted output



 ==============
|ConcateColumn|
==============
|1*2 |
|NULL |
|1 |
|2*3*4 |
| |
===============


Expected Output



------------------------
| Count | ConcateColumn |
-------------------------
| 2 | 1*2 |
| 0 | NULL |
| 1 | 1 |
| 3 | 2*3*4 |
| 0 | |
-------------------------


if i get the count that is more than enough










share|improve this question













i have Concatenating the multiple Columns and i want the count of how many columns are Concatenated



the query output and expected output are



for Concatenation



select  ConcateColumn = STUFF(
COALESCE('* ' + RTRIM(col1),'')
+COALESCE('* ' + RTRIM(col2),'')
+COALESCE('* ' + RTRIM(col4),'')
+COALESCE('* ' + RTRIM(col3),'')
, 1, 2, '')


table



===================================
| col1 | col2 | col3 | col4 |
===================================
| 1 | 2 | NULL | NULL |
| NULL | NULL | NULL | NULL |
| 1 | NULL | NULL | NULL |
| NULL | 2 | 3 | 4 |
| | NULL | NULL | NULL |
==================================


the resulted output



 ==============
|ConcateColumn|
==============
|1*2 |
|NULL |
|1 |
|2*3*4 |
| |
===============


Expected Output



------------------------
| Count | ConcateColumn |
-------------------------
| 2 | 1*2 |
| 0 | NULL |
| 1 | 1 |
| 3 | 2*3*4 |
| 0 | |
-------------------------


if i get the count that is more than enough







c# sql .net sql-server model-view-controller






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share|improve this question










asked Nov 11 at 10:53









Ramapriyan C

206




206












  • Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
    – Martin Parkin
    Nov 11 at 10:59










  • please note that the no of columns are dynamic
    – Ramapriyan C
    Nov 11 at 10:59


















  • Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
    – Martin Parkin
    Nov 11 at 10:59










  • please note that the no of columns are dynamic
    – Ramapriyan C
    Nov 11 at 10:59
















Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
– Martin Parkin
Nov 11 at 10:59




Off the top of my head, you could do something using CASE statements and a subquery to achieve this. What have you already tried to calculate this?
– Martin Parkin
Nov 11 at 10:59












please note that the no of columns are dynamic
– Ramapriyan C
Nov 11 at 10:59




please note that the no of columns are dynamic
– Ramapriyan C
Nov 11 at 10:59












4 Answers
4






active

oldest

votes

















up vote
1
down vote



accepted










You can count the number of * in the concatenated string:



with cte as 
(
select
ConcateColumn = STUFF( COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
, 1, 2, '')
FROM T
)
select ConcateColumn,
-- how many '*' have been removed?
coalesce(len(ConcateColumn) - len(replace(ConcateColumn, '*', '')) + 1, 0)
from cte
;


Of course, this will return wrong numbers if your data contains *






share|improve this answer























  • if the column is empty i need count as 0 , but im getting as 1
    – Ramapriyan C
    Nov 11 at 11:18










  • What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
    – dnoeth
    Nov 11 at 11:22










  • yes '' will return count as 1
    – Ramapriyan C
    Nov 11 at 11:23










  • check it in fiddle in last insert column
    – Ramapriyan C
    Nov 11 at 11:23






  • 1




    Well, an empty string is not the same as a NULL, of course it's counted.
    – dnoeth
    Nov 11 at 11:24


















up vote
2
down vote













You can try this.



select  (SELECT count(NULLIF(val,''))
FROM (VALUES(col1),(col2),(col3), (col4)) v (val)) 'COUNT',
ConcateColumn = STUFF(
COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
+COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
, 1, 2, '')
FROM T


If you want to count without NULL and '' you can try to use NULLIF function.



sqlfiddle






share|improve this answer



















  • 1




    count instead of sum, but you beat me to it... +1 :-)
    – Zohar Peled
    Nov 11 at 11:01












  • @ZoharPeled Yes Thanks
    – D-Shih
    Nov 11 at 11:02










  • please note that the columns may a string, just for understanding i gave it as numbers
    – Ramapriyan C
    Nov 11 at 11:04










  • if i give string it is not working pls check
    – Ramapriyan C
    Nov 11 at 11:08






  • 1




    If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
    – dnoeth
    Nov 11 at 11:27


















up vote
1
down vote













In SQL Server 2017+, you can simply do:



select v.*
from t cross apply
(select count(*) as cnt,
string_agg(rtrim(col), '* ') within group (order by ord) as ConcateColumn
from (values (1, col1), (2, col2), (3, col4), (4, col3)
) v(col, ord)
where col is not null
) v;


In earlier versions, I would probably follow the same structure that you have:



select ( (case when col1 is not null then 1 else 0 end) +
(case when col2 is not null then 1 else 0 end) +
(case when col4 is not null then 1 else 0 end) +
(case when col3 is not null then 1 else 0 end)
) as cnt





share|improve this answer




























    up vote
    0
    down vote













     select sum(
    case when col1 = '' then 0 when col1 is null then 0 else 1 end +
    case when col2 = '' then 0 when col2 is null then 0 else 1 end +
    case when col3 = '' then 0 when col3 is null then 0 else 1 end +
    case when col4 = '' then 0 when col4 is null then 0 else 1 end ) 'COUNT',
    ConcateColumn = STUFF(
    COALESCE('* ' + RTRIM(col1),'')
    +COALESCE('* ' + RTRIM(col2),'')
    +COALESCE('* ' + RTRIM(col4),'')
    +COALESCE('* ' + RTRIM(col3),'')
    , 1, 2, '') from temp1
    group by col1,col2,col3,col4





    share|improve this answer





















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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote



      accepted










      You can count the number of * in the concatenated string:



      with cte as 
      (
      select
      ConcateColumn = STUFF( COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T
      )
      select ConcateColumn,
      -- how many '*' have been removed?
      coalesce(len(ConcateColumn) - len(replace(ConcateColumn, '*', '')) + 1, 0)
      from cte
      ;


      Of course, this will return wrong numbers if your data contains *






      share|improve this answer























      • if the column is empty i need count as 0 , but im getting as 1
        – Ramapriyan C
        Nov 11 at 11:18










      • What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
        – dnoeth
        Nov 11 at 11:22










      • yes '' will return count as 1
        – Ramapriyan C
        Nov 11 at 11:23










      • check it in fiddle in last insert column
        – Ramapriyan C
        Nov 11 at 11:23






      • 1




        Well, an empty string is not the same as a NULL, of course it's counted.
        – dnoeth
        Nov 11 at 11:24















      up vote
      1
      down vote



      accepted










      You can count the number of * in the concatenated string:



      with cte as 
      (
      select
      ConcateColumn = STUFF( COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T
      )
      select ConcateColumn,
      -- how many '*' have been removed?
      coalesce(len(ConcateColumn) - len(replace(ConcateColumn, '*', '')) + 1, 0)
      from cte
      ;


      Of course, this will return wrong numbers if your data contains *






      share|improve this answer























      • if the column is empty i need count as 0 , but im getting as 1
        – Ramapriyan C
        Nov 11 at 11:18










      • What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
        – dnoeth
        Nov 11 at 11:22










      • yes '' will return count as 1
        – Ramapriyan C
        Nov 11 at 11:23










      • check it in fiddle in last insert column
        – Ramapriyan C
        Nov 11 at 11:23






      • 1




        Well, an empty string is not the same as a NULL, of course it's counted.
        – dnoeth
        Nov 11 at 11:24













      up vote
      1
      down vote



      accepted







      up vote
      1
      down vote



      accepted






      You can count the number of * in the concatenated string:



      with cte as 
      (
      select
      ConcateColumn = STUFF( COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T
      )
      select ConcateColumn,
      -- how many '*' have been removed?
      coalesce(len(ConcateColumn) - len(replace(ConcateColumn, '*', '')) + 1, 0)
      from cte
      ;


      Of course, this will return wrong numbers if your data contains *






      share|improve this answer














      You can count the number of * in the concatenated string:



      with cte as 
      (
      select
      ConcateColumn = STUFF( COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T
      )
      select ConcateColumn,
      -- how many '*' have been removed?
      coalesce(len(ConcateColumn) - len(replace(ConcateColumn, '*', '')) + 1, 0)
      from cte
      ;


      Of course, this will return wrong numbers if your data contains *







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 11 at 11:29

























      answered Nov 11 at 11:11









      dnoeth

      44k31838




      44k31838












      • if the column is empty i need count as 0 , but im getting as 1
        – Ramapriyan C
        Nov 11 at 11:18










      • What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
        – dnoeth
        Nov 11 at 11:22










      • yes '' will return count as 1
        – Ramapriyan C
        Nov 11 at 11:23










      • check it in fiddle in last insert column
        – Ramapriyan C
        Nov 11 at 11:23






      • 1




        Well, an empty string is not the same as a NULL, of course it's counted.
        – dnoeth
        Nov 11 at 11:24


















      • if the column is empty i need count as 0 , but im getting as 1
        – Ramapriyan C
        Nov 11 at 11:18










      • What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
        – dnoeth
        Nov 11 at 11:22










      • yes '' will return count as 1
        – Ramapriyan C
        Nov 11 at 11:23










      • check it in fiddle in last insert column
        – Ramapriyan C
        Nov 11 at 11:23






      • 1




        Well, an empty string is not the same as a NULL, of course it's counted.
        – dnoeth
        Nov 11 at 11:24
















      if the column is empty i need count as 0 , but im getting as 1
      – Ramapriyan C
      Nov 11 at 11:18




      if the column is empty i need count as 0 , but im getting as 1
      – Ramapriyan C
      Nov 11 at 11:18












      What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
      – dnoeth
      Nov 11 at 11:22




      What do you mean by empty? Empty string ''? It works with the D-Shih's dbfiddle.uk/…
      – dnoeth
      Nov 11 at 11:22












      yes '' will return count as 1
      – Ramapriyan C
      Nov 11 at 11:23




      yes '' will return count as 1
      – Ramapriyan C
      Nov 11 at 11:23












      check it in fiddle in last insert column
      – Ramapriyan C
      Nov 11 at 11:23




      check it in fiddle in last insert column
      – Ramapriyan C
      Nov 11 at 11:23




      1




      1




      Well, an empty string is not the same as a NULL, of course it's counted.
      – dnoeth
      Nov 11 at 11:24




      Well, an empty string is not the same as a NULL, of course it's counted.
      – dnoeth
      Nov 11 at 11:24












      up vote
      2
      down vote













      You can try this.



      select  (SELECT count(NULLIF(val,''))
      FROM (VALUES(col1),(col2),(col3), (col4)) v (val)) 'COUNT',
      ConcateColumn = STUFF(
      COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T


      If you want to count without NULL and '' you can try to use NULLIF function.



      sqlfiddle






      share|improve this answer



















      • 1




        count instead of sum, but you beat me to it... +1 :-)
        – Zohar Peled
        Nov 11 at 11:01












      • @ZoharPeled Yes Thanks
        – D-Shih
        Nov 11 at 11:02










      • please note that the columns may a string, just for understanding i gave it as numbers
        – Ramapriyan C
        Nov 11 at 11:04










      • if i give string it is not working pls check
        – Ramapriyan C
        Nov 11 at 11:08






      • 1




        If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
        – dnoeth
        Nov 11 at 11:27















      up vote
      2
      down vote













      You can try this.



      select  (SELECT count(NULLIF(val,''))
      FROM (VALUES(col1),(col2),(col3), (col4)) v (val)) 'COUNT',
      ConcateColumn = STUFF(
      COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T


      If you want to count without NULL and '' you can try to use NULLIF function.



      sqlfiddle






      share|improve this answer



















      • 1




        count instead of sum, but you beat me to it... +1 :-)
        – Zohar Peled
        Nov 11 at 11:01












      • @ZoharPeled Yes Thanks
        – D-Shih
        Nov 11 at 11:02










      • please note that the columns may a string, just for understanding i gave it as numbers
        – Ramapriyan C
        Nov 11 at 11:04










      • if i give string it is not working pls check
        – Ramapriyan C
        Nov 11 at 11:08






      • 1




        If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
        – dnoeth
        Nov 11 at 11:27













      up vote
      2
      down vote










      up vote
      2
      down vote









      You can try this.



      select  (SELECT count(NULLIF(val,''))
      FROM (VALUES(col1),(col2),(col3), (col4)) v (val)) 'COUNT',
      ConcateColumn = STUFF(
      COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T


      If you want to count without NULL and '' you can try to use NULLIF function.



      sqlfiddle






      share|improve this answer














      You can try this.



      select  (SELECT count(NULLIF(val,''))
      FROM (VALUES(col1),(col2),(col3), (col4)) v (val)) 'COUNT',
      ConcateColumn = STUFF(
      COALESCE('* ' + NULLIF(RTRIM(col1),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col2),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col3),''),'')
      +COALESCE('* ' + NULLIF(RTRIM(col4),''),'')
      , 1, 2, '')
      FROM T


      If you want to count without NULL and '' you can try to use NULLIF function.



      sqlfiddle







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 11 at 11:33

























      answered Nov 11 at 11:00









      D-Shih

      24.4k61431




      24.4k61431








      • 1




        count instead of sum, but you beat me to it... +1 :-)
        – Zohar Peled
        Nov 11 at 11:01












      • @ZoharPeled Yes Thanks
        – D-Shih
        Nov 11 at 11:02










      • please note that the columns may a string, just for understanding i gave it as numbers
        – Ramapriyan C
        Nov 11 at 11:04










      • if i give string it is not working pls check
        – Ramapriyan C
        Nov 11 at 11:08






      • 1




        If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
        – dnoeth
        Nov 11 at 11:27














      • 1




        count instead of sum, but you beat me to it... +1 :-)
        – Zohar Peled
        Nov 11 at 11:01












      • @ZoharPeled Yes Thanks
        – D-Shih
        Nov 11 at 11:02










      • please note that the columns may a string, just for understanding i gave it as numbers
        – Ramapriyan C
        Nov 11 at 11:04










      • if i give string it is not working pls check
        – Ramapriyan C
        Nov 11 at 11:08






      • 1




        If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
        – dnoeth
        Nov 11 at 11:27








      1




      1




      count instead of sum, but you beat me to it... +1 :-)
      – Zohar Peled
      Nov 11 at 11:01






      count instead of sum, but you beat me to it... +1 :-)
      – Zohar Peled
      Nov 11 at 11:01














      @ZoharPeled Yes Thanks
      – D-Shih
      Nov 11 at 11:02




      @ZoharPeled Yes Thanks
      – D-Shih
      Nov 11 at 11:02












      please note that the columns may a string, just for understanding i gave it as numbers
      – Ramapriyan C
      Nov 11 at 11:04




      please note that the columns may a string, just for understanding i gave it as numbers
      – Ramapriyan C
      Nov 11 at 11:04












      if i give string it is not working pls check
      – Ramapriyan C
      Nov 11 at 11:08




      if i give string it is not working pls check
      – Ramapriyan C
      Nov 11 at 11:08




      1




      1




      If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
      – dnoeth
      Nov 11 at 11:27




      If you want empty strings treated as NULLs, you must add NULLIF, e.g. `RTRIM(NULLIF(col1),''))
      – dnoeth
      Nov 11 at 11:27










      up vote
      1
      down vote













      In SQL Server 2017+, you can simply do:



      select v.*
      from t cross apply
      (select count(*) as cnt,
      string_agg(rtrim(col), '* ') within group (order by ord) as ConcateColumn
      from (values (1, col1), (2, col2), (3, col4), (4, col3)
      ) v(col, ord)
      where col is not null
      ) v;


      In earlier versions, I would probably follow the same structure that you have:



      select ( (case when col1 is not null then 1 else 0 end) +
      (case when col2 is not null then 1 else 0 end) +
      (case when col4 is not null then 1 else 0 end) +
      (case when col3 is not null then 1 else 0 end)
      ) as cnt





      share|improve this answer

























        up vote
        1
        down vote













        In SQL Server 2017+, you can simply do:



        select v.*
        from t cross apply
        (select count(*) as cnt,
        string_agg(rtrim(col), '* ') within group (order by ord) as ConcateColumn
        from (values (1, col1), (2, col2), (3, col4), (4, col3)
        ) v(col, ord)
        where col is not null
        ) v;


        In earlier versions, I would probably follow the same structure that you have:



        select ( (case when col1 is not null then 1 else 0 end) +
        (case when col2 is not null then 1 else 0 end) +
        (case when col4 is not null then 1 else 0 end) +
        (case when col3 is not null then 1 else 0 end)
        ) as cnt





        share|improve this answer























          up vote
          1
          down vote










          up vote
          1
          down vote









          In SQL Server 2017+, you can simply do:



          select v.*
          from t cross apply
          (select count(*) as cnt,
          string_agg(rtrim(col), '* ') within group (order by ord) as ConcateColumn
          from (values (1, col1), (2, col2), (3, col4), (4, col3)
          ) v(col, ord)
          where col is not null
          ) v;


          In earlier versions, I would probably follow the same structure that you have:



          select ( (case when col1 is not null then 1 else 0 end) +
          (case when col2 is not null then 1 else 0 end) +
          (case when col4 is not null then 1 else 0 end) +
          (case when col3 is not null then 1 else 0 end)
          ) as cnt





          share|improve this answer












          In SQL Server 2017+, you can simply do:



          select v.*
          from t cross apply
          (select count(*) as cnt,
          string_agg(rtrim(col), '* ') within group (order by ord) as ConcateColumn
          from (values (1, col1), (2, col2), (3, col4), (4, col3)
          ) v(col, ord)
          where col is not null
          ) v;


          In earlier versions, I would probably follow the same structure that you have:



          select ( (case when col1 is not null then 1 else 0 end) +
          (case when col2 is not null then 1 else 0 end) +
          (case when col4 is not null then 1 else 0 end) +
          (case when col3 is not null then 1 else 0 end)
          ) as cnt






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 11 at 11:36









          Gordon Linoff

          748k34285391




          748k34285391






















              up vote
              0
              down vote













               select sum(
              case when col1 = '' then 0 when col1 is null then 0 else 1 end +
              case when col2 = '' then 0 when col2 is null then 0 else 1 end +
              case when col3 = '' then 0 when col3 is null then 0 else 1 end +
              case when col4 = '' then 0 when col4 is null then 0 else 1 end ) 'COUNT',
              ConcateColumn = STUFF(
              COALESCE('* ' + RTRIM(col1),'')
              +COALESCE('* ' + RTRIM(col2),'')
              +COALESCE('* ' + RTRIM(col4),'')
              +COALESCE('* ' + RTRIM(col3),'')
              , 1, 2, '') from temp1
              group by col1,col2,col3,col4





              share|improve this answer

























                up vote
                0
                down vote













                 select sum(
                case when col1 = '' then 0 when col1 is null then 0 else 1 end +
                case when col2 = '' then 0 when col2 is null then 0 else 1 end +
                case when col3 = '' then 0 when col3 is null then 0 else 1 end +
                case when col4 = '' then 0 when col4 is null then 0 else 1 end ) 'COUNT',
                ConcateColumn = STUFF(
                COALESCE('* ' + RTRIM(col1),'')
                +COALESCE('* ' + RTRIM(col2),'')
                +COALESCE('* ' + RTRIM(col4),'')
                +COALESCE('* ' + RTRIM(col3),'')
                , 1, 2, '') from temp1
                group by col1,col2,col3,col4





                share|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                   select sum(
                  case when col1 = '' then 0 when col1 is null then 0 else 1 end +
                  case when col2 = '' then 0 when col2 is null then 0 else 1 end +
                  case when col3 = '' then 0 when col3 is null then 0 else 1 end +
                  case when col4 = '' then 0 when col4 is null then 0 else 1 end ) 'COUNT',
                  ConcateColumn = STUFF(
                  COALESCE('* ' + RTRIM(col1),'')
                  +COALESCE('* ' + RTRIM(col2),'')
                  +COALESCE('* ' + RTRIM(col4),'')
                  +COALESCE('* ' + RTRIM(col3),'')
                  , 1, 2, '') from temp1
                  group by col1,col2,col3,col4





                  share|improve this answer












                   select sum(
                  case when col1 = '' then 0 when col1 is null then 0 else 1 end +
                  case when col2 = '' then 0 when col2 is null then 0 else 1 end +
                  case when col3 = '' then 0 when col3 is null then 0 else 1 end +
                  case when col4 = '' then 0 when col4 is null then 0 else 1 end ) 'COUNT',
                  ConcateColumn = STUFF(
                  COALESCE('* ' + RTRIM(col1),'')
                  +COALESCE('* ' + RTRIM(col2),'')
                  +COALESCE('* ' + RTRIM(col4),'')
                  +COALESCE('* ' + RTRIM(col3),'')
                  , 1, 2, '') from temp1
                  group by col1,col2,col3,col4






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 11 at 12:28









                  Hitham Yosri

                  11




                  11






























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