Using Iterable and numeric as input in a function in python












1














I've written a mean function in python



    def mean(*args):
numbers = args
sm=0
length = len(numbers)
if length>0:
for num in numbers:
sm = sm+num
return sm/length
else:
return 'FAIL'


which is working fine with numeric values. Now I want to modify it so that it also accepts iterables in the input.



Modified function:



    def mean_new(*args):
numbers = args
sm=0
count=0
for num in numbers:
if iter(num):
data = list(num)
sm += sum(data)
count+=len(data)
else:
sm = sm+num
count+=1
return sm/count


mean_new function is not working and giving me an error 'int' object is not iterable. Could you please help me identify what I'm doing wrong in the mean_new function.
mean_new function should work with both numeric and iterable input.










share|improve this question






















  • What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
    – Willem Van Onsem
    Nov 12 at 19:32










  • thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
    – Joran Beasley
    Nov 12 at 19:32






  • 2




    as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
    – juanpa.arrivillaga
    Nov 12 at 19:34










  • It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
    – MSG
    Nov 12 at 19:34


















1














I've written a mean function in python



    def mean(*args):
numbers = args
sm=0
length = len(numbers)
if length>0:
for num in numbers:
sm = sm+num
return sm/length
else:
return 'FAIL'


which is working fine with numeric values. Now I want to modify it so that it also accepts iterables in the input.



Modified function:



    def mean_new(*args):
numbers = args
sm=0
count=0
for num in numbers:
if iter(num):
data = list(num)
sm += sum(data)
count+=len(data)
else:
sm = sm+num
count+=1
return sm/count


mean_new function is not working and giving me an error 'int' object is not iterable. Could you please help me identify what I'm doing wrong in the mean_new function.
mean_new function should work with both numeric and iterable input.










share|improve this question






















  • What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
    – Willem Van Onsem
    Nov 12 at 19:32










  • thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
    – Joran Beasley
    Nov 12 at 19:32






  • 2




    as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
    – juanpa.arrivillaga
    Nov 12 at 19:34










  • It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
    – MSG
    Nov 12 at 19:34
















1












1








1







I've written a mean function in python



    def mean(*args):
numbers = args
sm=0
length = len(numbers)
if length>0:
for num in numbers:
sm = sm+num
return sm/length
else:
return 'FAIL'


which is working fine with numeric values. Now I want to modify it so that it also accepts iterables in the input.



Modified function:



    def mean_new(*args):
numbers = args
sm=0
count=0
for num in numbers:
if iter(num):
data = list(num)
sm += sum(data)
count+=len(data)
else:
sm = sm+num
count+=1
return sm/count


mean_new function is not working and giving me an error 'int' object is not iterable. Could you please help me identify what I'm doing wrong in the mean_new function.
mean_new function should work with both numeric and iterable input.










share|improve this question













I've written a mean function in python



    def mean(*args):
numbers = args
sm=0
length = len(numbers)
if length>0:
for num in numbers:
sm = sm+num
return sm/length
else:
return 'FAIL'


which is working fine with numeric values. Now I want to modify it so that it also accepts iterables in the input.



Modified function:



    def mean_new(*args):
numbers = args
sm=0
count=0
for num in numbers:
if iter(num):
data = list(num)
sm += sum(data)
count+=len(data)
else:
sm = sm+num
count+=1
return sm/count


mean_new function is not working and giving me an error 'int' object is not iterable. Could you please help me identify what I'm doing wrong in the mean_new function.
mean_new function should work with both numeric and iterable input.







python python-3.x function mean iterable






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 at 19:30









MSG

103




103












  • What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
    – Willem Van Onsem
    Nov 12 at 19:32










  • thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
    – Joran Beasley
    Nov 12 at 19:32






  • 2




    as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
    – juanpa.arrivillaga
    Nov 12 at 19:34










  • It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
    – MSG
    Nov 12 at 19:34




















  • What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
    – Willem Van Onsem
    Nov 12 at 19:32










  • thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
    – Joran Beasley
    Nov 12 at 19:32






  • 2




    as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
    – juanpa.arrivillaga
    Nov 12 at 19:34










  • It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
    – MSG
    Nov 12 at 19:34


















What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
– Willem Van Onsem
Nov 12 at 19:32




What is iter(num) here doing? Exactly what do you want to realize by accepting iterables? Can you provide some sample input?
– Willem Van Onsem
Nov 12 at 19:32












thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
– Joran Beasley
Nov 12 at 19:32




thats not how you check if something is iterable ... if isinstance(obj,collection.iterable) or something like that
– Joran Beasley
Nov 12 at 19:32




2




2




as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
– juanpa.arrivillaga
Nov 12 at 19:34




as an aside, return 'FAIL' is a bad design decision. Throw an error, don't return a magic string.
– juanpa.arrivillaga
Nov 12 at 19:34












It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
– MSG
Nov 12 at 19:34






It should work with the following inputs: mean_new(1,2,3,4) mean_new([1,1,1,2]) mean_new(1, (2,), 3, [4,6]))
– MSG
Nov 12 at 19:34














1 Answer
1






active

oldest

votes


















1














To check if an object is iterable, you can indeed use iter(object), but not as a condition in an if statement, but in a try block, since iter() would raise a TypeError exception if the object is not iterable. But then, since you are throwing away the iterator returned by iter() and are instead using the list() constructor to convert the iterable into a list, you can simply put the try block around list() instead:



for num in numbers:
try:
data = list(num)
sm += sum(data)
count += len(data)
except TypeError:
sm = sm + num
count += 1





share|improve this answer

















  • 1




    It worked. Thanks.:)
    – MSG
    Nov 12 at 19:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














To check if an object is iterable, you can indeed use iter(object), but not as a condition in an if statement, but in a try block, since iter() would raise a TypeError exception if the object is not iterable. But then, since you are throwing away the iterator returned by iter() and are instead using the list() constructor to convert the iterable into a list, you can simply put the try block around list() instead:



for num in numbers:
try:
data = list(num)
sm += sum(data)
count += len(data)
except TypeError:
sm = sm + num
count += 1





share|improve this answer

















  • 1




    It worked. Thanks.:)
    – MSG
    Nov 12 at 19:53
















1














To check if an object is iterable, you can indeed use iter(object), but not as a condition in an if statement, but in a try block, since iter() would raise a TypeError exception if the object is not iterable. But then, since you are throwing away the iterator returned by iter() and are instead using the list() constructor to convert the iterable into a list, you can simply put the try block around list() instead:



for num in numbers:
try:
data = list(num)
sm += sum(data)
count += len(data)
except TypeError:
sm = sm + num
count += 1





share|improve this answer

















  • 1




    It worked. Thanks.:)
    – MSG
    Nov 12 at 19:53














1












1








1






To check if an object is iterable, you can indeed use iter(object), but not as a condition in an if statement, but in a try block, since iter() would raise a TypeError exception if the object is not iterable. But then, since you are throwing away the iterator returned by iter() and are instead using the list() constructor to convert the iterable into a list, you can simply put the try block around list() instead:



for num in numbers:
try:
data = list(num)
sm += sum(data)
count += len(data)
except TypeError:
sm = sm + num
count += 1





share|improve this answer












To check if an object is iterable, you can indeed use iter(object), but not as a condition in an if statement, but in a try block, since iter() would raise a TypeError exception if the object is not iterable. But then, since you are throwing away the iterator returned by iter() and are instead using the list() constructor to convert the iterable into a list, you can simply put the try block around list() instead:



for num in numbers:
try:
data = list(num)
sm += sum(data)
count += len(data)
except TypeError:
sm = sm + num
count += 1






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 at 19:42









blhsing

28.5k41336




28.5k41336








  • 1




    It worked. Thanks.:)
    – MSG
    Nov 12 at 19:53














  • 1




    It worked. Thanks.:)
    – MSG
    Nov 12 at 19:53








1




1




It worked. Thanks.:)
– MSG
Nov 12 at 19:53




It worked. Thanks.:)
– MSG
Nov 12 at 19:53


















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