remove values from different rows until data exhaustion?











up vote
2
down vote

favorite












I have a table like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 3 | 10 |
+----+-------+------+
| 2 | 5 | 8 |
+----+-------+------+
| 3 | 4 | 7 |
+----+-------+------+


I have to delete 9 apple and 11 pears.
A result like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 0 | 0 |
+----+-------+------+
| 2 | 0 | 7 |
+----+-------+------+
| 3 | 1 | 7 |
+----+-------+------+


Is there a way to do this without having to do a lot of queries?



I did something like this.
I wonder if there is a better way.



    $eat["apple"]=9; 
$eat["pear"]=11;
$id=0; //I will increment this id during the cycle

while ($eat["apple"] > 0 && $eat["pear"] > 0) {
$get_fruit=mysql_query("SELECT id,apple,pear FROM fruits WHERE
id>'".$id."'
ORDER BY id LIMIT 1") or die (mysql_error());

if((mysql_num_rows($get_fruit))==0){
die;
} else {

$fruit = mysql_fetch_assoc($get_fruit);
$id = $fruit["id"];

foreach ($eat as $key => $value) {

if ($fruit[$key]>$eat[$key]) {
$fruit[$key]-=$eat[$key];
$eat[$key]=0;
} else {
$eat[$key]-=$fruit[$key];
$fruit[$key]=0;
}
}

$update=mysql_query("UPDATE fruits SET
apple='".$fruit["apple"]."',
pear='".$fruit["pear"]."'
WHERE id='".$id."'LIMIT 1") or die (mysql_error());
}


}










share|improve this question




















  • 1




    Your apples dont add up.
    – Mihai
    Jan 20 '14 at 14:19










  • UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
    – Mihai
    Jan 20 '14 at 14:20

















up vote
2
down vote

favorite












I have a table like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 3 | 10 |
+----+-------+------+
| 2 | 5 | 8 |
+----+-------+------+
| 3 | 4 | 7 |
+----+-------+------+


I have to delete 9 apple and 11 pears.
A result like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 0 | 0 |
+----+-------+------+
| 2 | 0 | 7 |
+----+-------+------+
| 3 | 1 | 7 |
+----+-------+------+


Is there a way to do this without having to do a lot of queries?



I did something like this.
I wonder if there is a better way.



    $eat["apple"]=9; 
$eat["pear"]=11;
$id=0; //I will increment this id during the cycle

while ($eat["apple"] > 0 && $eat["pear"] > 0) {
$get_fruit=mysql_query("SELECT id,apple,pear FROM fruits WHERE
id>'".$id."'
ORDER BY id LIMIT 1") or die (mysql_error());

if((mysql_num_rows($get_fruit))==0){
die;
} else {

$fruit = mysql_fetch_assoc($get_fruit);
$id = $fruit["id"];

foreach ($eat as $key => $value) {

if ($fruit[$key]>$eat[$key]) {
$fruit[$key]-=$eat[$key];
$eat[$key]=0;
} else {
$eat[$key]-=$fruit[$key];
$fruit[$key]=0;
}
}

$update=mysql_query("UPDATE fruits SET
apple='".$fruit["apple"]."',
pear='".$fruit["pear"]."'
WHERE id='".$id."'LIMIT 1") or die (mysql_error());
}


}










share|improve this question




















  • 1




    Your apples dont add up.
    – Mihai
    Jan 20 '14 at 14:19










  • UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
    – Mihai
    Jan 20 '14 at 14:20















up vote
2
down vote

favorite









up vote
2
down vote

favorite











I have a table like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 3 | 10 |
+----+-------+------+
| 2 | 5 | 8 |
+----+-------+------+
| 3 | 4 | 7 |
+----+-------+------+


I have to delete 9 apple and 11 pears.
A result like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 0 | 0 |
+----+-------+------+
| 2 | 0 | 7 |
+----+-------+------+
| 3 | 1 | 7 |
+----+-------+------+


Is there a way to do this without having to do a lot of queries?



I did something like this.
I wonder if there is a better way.



    $eat["apple"]=9; 
$eat["pear"]=11;
$id=0; //I will increment this id during the cycle

while ($eat["apple"] > 0 && $eat["pear"] > 0) {
$get_fruit=mysql_query("SELECT id,apple,pear FROM fruits WHERE
id>'".$id."'
ORDER BY id LIMIT 1") or die (mysql_error());

if((mysql_num_rows($get_fruit))==0){
die;
} else {

$fruit = mysql_fetch_assoc($get_fruit);
$id = $fruit["id"];

foreach ($eat as $key => $value) {

if ($fruit[$key]>$eat[$key]) {
$fruit[$key]-=$eat[$key];
$eat[$key]=0;
} else {
$eat[$key]-=$fruit[$key];
$fruit[$key]=0;
}
}

$update=mysql_query("UPDATE fruits SET
apple='".$fruit["apple"]."',
pear='".$fruit["pear"]."'
WHERE id='".$id."'LIMIT 1") or die (mysql_error());
}


}










share|improve this question















I have a table like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 3 | 10 |
+----+-------+------+
| 2 | 5 | 8 |
+----+-------+------+
| 3 | 4 | 7 |
+----+-------+------+


I have to delete 9 apple and 11 pears.
A result like this



+----+-------+------+
| id | apple | pear |
+----+-------+------+
| 1 | 0 | 0 |
+----+-------+------+
| 2 | 0 | 7 |
+----+-------+------+
| 3 | 1 | 7 |
+----+-------+------+


Is there a way to do this without having to do a lot of queries?



I did something like this.
I wonder if there is a better way.



    $eat["apple"]=9; 
$eat["pear"]=11;
$id=0; //I will increment this id during the cycle

while ($eat["apple"] > 0 && $eat["pear"] > 0) {
$get_fruit=mysql_query("SELECT id,apple,pear FROM fruits WHERE
id>'".$id."'
ORDER BY id LIMIT 1") or die (mysql_error());

if((mysql_num_rows($get_fruit))==0){
die;
} else {

$fruit = mysql_fetch_assoc($get_fruit);
$id = $fruit["id"];

foreach ($eat as $key => $value) {

if ($fruit[$key]>$eat[$key]) {
$fruit[$key]-=$eat[$key];
$eat[$key]=0;
} else {
$eat[$key]-=$fruit[$key];
$fruit[$key]=0;
}
}

$update=mysql_query("UPDATE fruits SET
apple='".$fruit["apple"]."',
pear='".$fruit["pear"]."'
WHERE id='".$id."'LIMIT 1") or die (mysql_error());
}


}







php mysql rows cycle






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edited Nov 11 at 6:34









Cœur

17k9102140




17k9102140










asked Jan 20 '14 at 14:15









Micky

60118




60118








  • 1




    Your apples dont add up.
    – Mihai
    Jan 20 '14 at 14:19










  • UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
    – Mihai
    Jan 20 '14 at 14:20
















  • 1




    Your apples dont add up.
    – Mihai
    Jan 20 '14 at 14:19










  • UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
    – Mihai
    Jan 20 '14 at 14:20










1




1




Your apples dont add up.
– Mihai
Jan 20 '14 at 14:19




Your apples dont add up.
– Mihai
Jan 20 '14 at 14:19












UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
– Mihai
Jan 20 '14 at 14:20






UPDATE table SET apple=SUM(apple)-9;UPDATE table SET apple=o WHERE id!=1
– Mihai
Jan 20 '14 at 14:20














2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










CREATE TABLE t
(`id` int, `apple` int, `pear` int)
;

INSERT INTO t
(`id`, `apple`, `pear`)
VALUES
(1, 3, 10),
(2, 5, 8),
(3, 4, 7)
;

UPDATE t
INNER JOIN (
SELECT
id, apple, pear,
GREATEST(0, apple - GREATEST(0, @atr)) AS new_apples,
@atr := @atr - apple,
GREATEST(0, pear - GREATEST(0, @ptr)) AS new_pears,
@ptr := @ptr - pear
FROM t
, (SELECT @atr := 9, @ptr := 11) variable_initialization_subquery /*@atr = ApplesToRemove...*/
ORDER BY id
) sq ON t.id = sq.id
SET t.apple = sq.new_apples,
t.pear = sq.new_pears;

SELECT * FROM t;

| ID | APPLE | PEAR |
|----|-------|------|
| 1 | 0 | 0 |
| 2 | 0 | 7 |
| 3 | 3 | 7 |



  • DEMO






share|improve this answer




























    up vote
    3
    down vote













    Here's apples...



    SET @apple = 9;
    UPDATE fruits x
    JOIN
    ( SELECT id
    , apple
    , GREATEST(apple-@apple,0)n,@apple:=@apple-apple
    FROM fruits
    ORDER
    BY id
    ) y
    ON y.id = x.id
    SET x.apple = y.n;





    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      CREATE TABLE t
      (`id` int, `apple` int, `pear` int)
      ;

      INSERT INTO t
      (`id`, `apple`, `pear`)
      VALUES
      (1, 3, 10),
      (2, 5, 8),
      (3, 4, 7)
      ;

      UPDATE t
      INNER JOIN (
      SELECT
      id, apple, pear,
      GREATEST(0, apple - GREATEST(0, @atr)) AS new_apples,
      @atr := @atr - apple,
      GREATEST(0, pear - GREATEST(0, @ptr)) AS new_pears,
      @ptr := @ptr - pear
      FROM t
      , (SELECT @atr := 9, @ptr := 11) variable_initialization_subquery /*@atr = ApplesToRemove...*/
      ORDER BY id
      ) sq ON t.id = sq.id
      SET t.apple = sq.new_apples,
      t.pear = sq.new_pears;

      SELECT * FROM t;

      | ID | APPLE | PEAR |
      |----|-------|------|
      | 1 | 0 | 0 |
      | 2 | 0 | 7 |
      | 3 | 3 | 7 |



      • DEMO






      share|improve this answer

























        up vote
        3
        down vote



        accepted










        CREATE TABLE t
        (`id` int, `apple` int, `pear` int)
        ;

        INSERT INTO t
        (`id`, `apple`, `pear`)
        VALUES
        (1, 3, 10),
        (2, 5, 8),
        (3, 4, 7)
        ;

        UPDATE t
        INNER JOIN (
        SELECT
        id, apple, pear,
        GREATEST(0, apple - GREATEST(0, @atr)) AS new_apples,
        @atr := @atr - apple,
        GREATEST(0, pear - GREATEST(0, @ptr)) AS new_pears,
        @ptr := @ptr - pear
        FROM t
        , (SELECT @atr := 9, @ptr := 11) variable_initialization_subquery /*@atr = ApplesToRemove...*/
        ORDER BY id
        ) sq ON t.id = sq.id
        SET t.apple = sq.new_apples,
        t.pear = sq.new_pears;

        SELECT * FROM t;

        | ID | APPLE | PEAR |
        |----|-------|------|
        | 1 | 0 | 0 |
        | 2 | 0 | 7 |
        | 3 | 3 | 7 |



        • DEMO






        share|improve this answer























          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          CREATE TABLE t
          (`id` int, `apple` int, `pear` int)
          ;

          INSERT INTO t
          (`id`, `apple`, `pear`)
          VALUES
          (1, 3, 10),
          (2, 5, 8),
          (3, 4, 7)
          ;

          UPDATE t
          INNER JOIN (
          SELECT
          id, apple, pear,
          GREATEST(0, apple - GREATEST(0, @atr)) AS new_apples,
          @atr := @atr - apple,
          GREATEST(0, pear - GREATEST(0, @ptr)) AS new_pears,
          @ptr := @ptr - pear
          FROM t
          , (SELECT @atr := 9, @ptr := 11) variable_initialization_subquery /*@atr = ApplesToRemove...*/
          ORDER BY id
          ) sq ON t.id = sq.id
          SET t.apple = sq.new_apples,
          t.pear = sq.new_pears;

          SELECT * FROM t;

          | ID | APPLE | PEAR |
          |----|-------|------|
          | 1 | 0 | 0 |
          | 2 | 0 | 7 |
          | 3 | 3 | 7 |



          • DEMO






          share|improve this answer












          CREATE TABLE t
          (`id` int, `apple` int, `pear` int)
          ;

          INSERT INTO t
          (`id`, `apple`, `pear`)
          VALUES
          (1, 3, 10),
          (2, 5, 8),
          (3, 4, 7)
          ;

          UPDATE t
          INNER JOIN (
          SELECT
          id, apple, pear,
          GREATEST(0, apple - GREATEST(0, @atr)) AS new_apples,
          @atr := @atr - apple,
          GREATEST(0, pear - GREATEST(0, @ptr)) AS new_pears,
          @ptr := @ptr - pear
          FROM t
          , (SELECT @atr := 9, @ptr := 11) variable_initialization_subquery /*@atr = ApplesToRemove...*/
          ORDER BY id
          ) sq ON t.id = sq.id
          SET t.apple = sq.new_apples,
          t.pear = sq.new_pears;

          SELECT * FROM t;

          | ID | APPLE | PEAR |
          |----|-------|------|
          | 1 | 0 | 0 |
          | 2 | 0 | 7 |
          | 3 | 3 | 7 |



          • DEMO







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 20 '14 at 14:55









          fancyPants

          38.5k156378




          38.5k156378
























              up vote
              3
              down vote













              Here's apples...



              SET @apple = 9;
              UPDATE fruits x
              JOIN
              ( SELECT id
              , apple
              , GREATEST(apple-@apple,0)n,@apple:=@apple-apple
              FROM fruits
              ORDER
              BY id
              ) y
              ON y.id = x.id
              SET x.apple = y.n;





              share|improve this answer

























                up vote
                3
                down vote













                Here's apples...



                SET @apple = 9;
                UPDATE fruits x
                JOIN
                ( SELECT id
                , apple
                , GREATEST(apple-@apple,0)n,@apple:=@apple-apple
                FROM fruits
                ORDER
                BY id
                ) y
                ON y.id = x.id
                SET x.apple = y.n;





                share|improve this answer























                  up vote
                  3
                  down vote










                  up vote
                  3
                  down vote









                  Here's apples...



                  SET @apple = 9;
                  UPDATE fruits x
                  JOIN
                  ( SELECT id
                  , apple
                  , GREATEST(apple-@apple,0)n,@apple:=@apple-apple
                  FROM fruits
                  ORDER
                  BY id
                  ) y
                  ON y.id = x.id
                  SET x.apple = y.n;





                  share|improve this answer












                  Here's apples...



                  SET @apple = 9;
                  UPDATE fruits x
                  JOIN
                  ( SELECT id
                  , apple
                  , GREATEST(apple-@apple,0)n,@apple:=@apple-apple
                  FROM fruits
                  ORDER
                  BY id
                  ) y
                  ON y.id = x.id
                  SET x.apple = y.n;






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 20 '14 at 14:42









                  Strawberry

                  25.7k83149




                  25.7k83149






























                       

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