SQL Server : except with results from both datasets
I have the following tables:
Stores:
StoreID | Name
1 | Store1
2 | Store2
3 | Store3
EmID | StoreID
1 | 1
2 | 1
3 | 1
1 | 2
3 | 2
Employee:
EmID | Employee | Important
1 | Cashier | 1
2 | Manager | 1
3 | Guard | 0
I need a query to return StoreID and EmID where Employee is important (Important = 1) and the store and employee are not connected. Basically, the result should be:
StoreID | EmId
--------+-------
2 | 2
3 | 1
3 | 2
I have tried joins, outer joins / apply-es, except, cte, temporary tables, but still haven't found the answer.
Can someone help me with the code, or at least point me in the right direction?
Any idea will be very much appreciated.
Thanks.
sql-server
add a comment |
I have the following tables:
Stores:
StoreID | Name
1 | Store1
2 | Store2
3 | Store3
EmID | StoreID
1 | 1
2 | 1
3 | 1
1 | 2
3 | 2
Employee:
EmID | Employee | Important
1 | Cashier | 1
2 | Manager | 1
3 | Guard | 0
I need a query to return StoreID and EmID where Employee is important (Important = 1) and the store and employee are not connected. Basically, the result should be:
StoreID | EmId
--------+-------
2 | 2
3 | 1
3 | 2
I have tried joins, outer joins / apply-es, except, cte, temporary tables, but still haven't found the answer.
Can someone help me with the code, or at least point me in the right direction?
Any idea will be very much appreciated.
Thanks.
sql-server
You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57
add a comment |
I have the following tables:
Stores:
StoreID | Name
1 | Store1
2 | Store2
3 | Store3
EmID | StoreID
1 | 1
2 | 1
3 | 1
1 | 2
3 | 2
Employee:
EmID | Employee | Important
1 | Cashier | 1
2 | Manager | 1
3 | Guard | 0
I need a query to return StoreID and EmID where Employee is important (Important = 1) and the store and employee are not connected. Basically, the result should be:
StoreID | EmId
--------+-------
2 | 2
3 | 1
3 | 2
I have tried joins, outer joins / apply-es, except, cte, temporary tables, but still haven't found the answer.
Can someone help me with the code, or at least point me in the right direction?
Any idea will be very much appreciated.
Thanks.
sql-server
I have the following tables:
Stores:
StoreID | Name
1 | Store1
2 | Store2
3 | Store3
EmID | StoreID
1 | 1
2 | 1
3 | 1
1 | 2
3 | 2
Employee:
EmID | Employee | Important
1 | Cashier | 1
2 | Manager | 1
3 | Guard | 0
I need a query to return StoreID and EmID where Employee is important (Important = 1) and the store and employee are not connected. Basically, the result should be:
StoreID | EmId
--------+-------
2 | 2
3 | 1
3 | 2
I have tried joins, outer joins / apply-es, except, cte, temporary tables, but still haven't found the answer.
Can someone help me with the code, or at least point me in the right direction?
Any idea will be very much appreciated.
Thanks.
sql-server
sql-server
edited Nov 14 '18 at 9:24
marc_s
575k12811101257
575k12811101257
asked Nov 14 '18 at 8:24
Roman ClaudiuRoman Claudiu
13
13
You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57
add a comment |
You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57
You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57
You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57
add a comment |
3 Answers
3
active
oldest
votes
You use a cross join
to get the set of all possible employee/store combinations, and a left join
to then remove the combinations that exist in the join table1:
declare @Stores table (StoreID int, Name char(6))
insert into @Stores (StoreID,Name) values
(1,'Store1'),
(2,'Store2'),
(3,'Store3')
declare @Employees table (EmID int, Employee varchar(8), Important bit)
insert into @Employees (EmID,Employee,Important) values
(1,'Cashier',1),
(2,'Manager',1),
(3,'Guard' ,0)
declare @Staffing table (EmID int, StoreID int)
insert into @Staffing (EmID,StoreID) values
(1,1),
(2,1),
(3,1),
(1,2),
(3,2)
select
*
from
@Stores s
cross join
@Employees e
left join
@Staffing st
on
s.StoreID = st.StoreID and
e.EmID = st.EmID
where
e.Important = 1 and
st.EmID is null
Results:
StoreID Name EmID Employee Important EmID StoreID
----------- ------ ----------- -------- --------- ----------- -----------
3 Store3 1 Cashier 1 NULL NULL
2 Store2 2 Manager 1 NULL NULL
3 Store3 2 Manager 1 NULL NULL
1The one I've named Staffing and you didn't name in the question. Note also (for future questions) that my presentation of the sample data takes up approximately as much space as yours in the question, provides the data types, and is a runnable script.
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
add a comment |
Please use Cross join followed by Left join and filter on IMP and StoreID null.
create table #Stores
(storeID int, Name varchar(100))
create table #ES
(empid int,storeID int)
create table #E
(eid int,employee varchar(100), imp int)
insert into #stores values(
1,'Store1'),
(2,'Store2'),
(3,'Store3')
insert into #ES values(
1,1),(2,1),(3,1),(1,2),(3,2)
insert into #E values
(1,'Cashier',1),
(2,'Manager', 1),
(3,'Guard',0)
select * from #Stores
select * from #ES
select * from #E
select #stores.storeid,#E.eid from #Stores
cross join #E
LEFT join #ES
on #ES.storeid = #Stores.storeid
and #E.eid = #ES.empid
where #E.imp = 1
and #ES.storeID is null
add a comment |
Try this query.
I assumed the table name of the "Employee" is dbo.Employee and table name of "Stores" is dbo.Stores and the intermediate table is "dbo.EmpStore"
SELECT S.StoreID, E.EmID
FROM dbo.Stores S
CROSS JOIN dbo.Employees E
LEFT JOIN dbo.EmpStore ES ON ES.EmID = E.EmID AND ES.StoreID = S.StoreID
WHERE E.Important=1 AND ES.EmID IS NULL
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You use a cross join
to get the set of all possible employee/store combinations, and a left join
to then remove the combinations that exist in the join table1:
declare @Stores table (StoreID int, Name char(6))
insert into @Stores (StoreID,Name) values
(1,'Store1'),
(2,'Store2'),
(3,'Store3')
declare @Employees table (EmID int, Employee varchar(8), Important bit)
insert into @Employees (EmID,Employee,Important) values
(1,'Cashier',1),
(2,'Manager',1),
(3,'Guard' ,0)
declare @Staffing table (EmID int, StoreID int)
insert into @Staffing (EmID,StoreID) values
(1,1),
(2,1),
(3,1),
(1,2),
(3,2)
select
*
from
@Stores s
cross join
@Employees e
left join
@Staffing st
on
s.StoreID = st.StoreID and
e.EmID = st.EmID
where
e.Important = 1 and
st.EmID is null
Results:
StoreID Name EmID Employee Important EmID StoreID
----------- ------ ----------- -------- --------- ----------- -----------
3 Store3 1 Cashier 1 NULL NULL
2 Store2 2 Manager 1 NULL NULL
3 Store3 2 Manager 1 NULL NULL
1The one I've named Staffing and you didn't name in the question. Note also (for future questions) that my presentation of the sample data takes up approximately as much space as yours in the question, provides the data types, and is a runnable script.
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
add a comment |
You use a cross join
to get the set of all possible employee/store combinations, and a left join
to then remove the combinations that exist in the join table1:
declare @Stores table (StoreID int, Name char(6))
insert into @Stores (StoreID,Name) values
(1,'Store1'),
(2,'Store2'),
(3,'Store3')
declare @Employees table (EmID int, Employee varchar(8), Important bit)
insert into @Employees (EmID,Employee,Important) values
(1,'Cashier',1),
(2,'Manager',1),
(3,'Guard' ,0)
declare @Staffing table (EmID int, StoreID int)
insert into @Staffing (EmID,StoreID) values
(1,1),
(2,1),
(3,1),
(1,2),
(3,2)
select
*
from
@Stores s
cross join
@Employees e
left join
@Staffing st
on
s.StoreID = st.StoreID and
e.EmID = st.EmID
where
e.Important = 1 and
st.EmID is null
Results:
StoreID Name EmID Employee Important EmID StoreID
----------- ------ ----------- -------- --------- ----------- -----------
3 Store3 1 Cashier 1 NULL NULL
2 Store2 2 Manager 1 NULL NULL
3 Store3 2 Manager 1 NULL NULL
1The one I've named Staffing and you didn't name in the question. Note also (for future questions) that my presentation of the sample data takes up approximately as much space as yours in the question, provides the data types, and is a runnable script.
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
add a comment |
You use a cross join
to get the set of all possible employee/store combinations, and a left join
to then remove the combinations that exist in the join table1:
declare @Stores table (StoreID int, Name char(6))
insert into @Stores (StoreID,Name) values
(1,'Store1'),
(2,'Store2'),
(3,'Store3')
declare @Employees table (EmID int, Employee varchar(8), Important bit)
insert into @Employees (EmID,Employee,Important) values
(1,'Cashier',1),
(2,'Manager',1),
(3,'Guard' ,0)
declare @Staffing table (EmID int, StoreID int)
insert into @Staffing (EmID,StoreID) values
(1,1),
(2,1),
(3,1),
(1,2),
(3,2)
select
*
from
@Stores s
cross join
@Employees e
left join
@Staffing st
on
s.StoreID = st.StoreID and
e.EmID = st.EmID
where
e.Important = 1 and
st.EmID is null
Results:
StoreID Name EmID Employee Important EmID StoreID
----------- ------ ----------- -------- --------- ----------- -----------
3 Store3 1 Cashier 1 NULL NULL
2 Store2 2 Manager 1 NULL NULL
3 Store3 2 Manager 1 NULL NULL
1The one I've named Staffing and you didn't name in the question. Note also (for future questions) that my presentation of the sample data takes up approximately as much space as yours in the question, provides the data types, and is a runnable script.
You use a cross join
to get the set of all possible employee/store combinations, and a left join
to then remove the combinations that exist in the join table1:
declare @Stores table (StoreID int, Name char(6))
insert into @Stores (StoreID,Name) values
(1,'Store1'),
(2,'Store2'),
(3,'Store3')
declare @Employees table (EmID int, Employee varchar(8), Important bit)
insert into @Employees (EmID,Employee,Important) values
(1,'Cashier',1),
(2,'Manager',1),
(3,'Guard' ,0)
declare @Staffing table (EmID int, StoreID int)
insert into @Staffing (EmID,StoreID) values
(1,1),
(2,1),
(3,1),
(1,2),
(3,2)
select
*
from
@Stores s
cross join
@Employees e
left join
@Staffing st
on
s.StoreID = st.StoreID and
e.EmID = st.EmID
where
e.Important = 1 and
st.EmID is null
Results:
StoreID Name EmID Employee Important EmID StoreID
----------- ------ ----------- -------- --------- ----------- -----------
3 Store3 1 Cashier 1 NULL NULL
2 Store2 2 Manager 1 NULL NULL
3 Store3 2 Manager 1 NULL NULL
1The one I've named Staffing and you didn't name in the question. Note also (for future questions) that my presentation of the sample data takes up approximately as much space as yours in the question, provides the data types, and is a runnable script.
answered Nov 14 '18 at 8:48
Damien_The_UnbelieverDamien_The_Unbeliever
194k17248335
194k17248335
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
add a comment |
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
that's exactly what i needed. i have been racking my brain for 3 days now. thanks a lot :)
– Roman Claudiu
Nov 14 '18 at 9:09
add a comment |
Please use Cross join followed by Left join and filter on IMP and StoreID null.
create table #Stores
(storeID int, Name varchar(100))
create table #ES
(empid int,storeID int)
create table #E
(eid int,employee varchar(100), imp int)
insert into #stores values(
1,'Store1'),
(2,'Store2'),
(3,'Store3')
insert into #ES values(
1,1),(2,1),(3,1),(1,2),(3,2)
insert into #E values
(1,'Cashier',1),
(2,'Manager', 1),
(3,'Guard',0)
select * from #Stores
select * from #ES
select * from #E
select #stores.storeid,#E.eid from #Stores
cross join #E
LEFT join #ES
on #ES.storeid = #Stores.storeid
and #E.eid = #ES.empid
where #E.imp = 1
and #ES.storeID is null
add a comment |
Please use Cross join followed by Left join and filter on IMP and StoreID null.
create table #Stores
(storeID int, Name varchar(100))
create table #ES
(empid int,storeID int)
create table #E
(eid int,employee varchar(100), imp int)
insert into #stores values(
1,'Store1'),
(2,'Store2'),
(3,'Store3')
insert into #ES values(
1,1),(2,1),(3,1),(1,2),(3,2)
insert into #E values
(1,'Cashier',1),
(2,'Manager', 1),
(3,'Guard',0)
select * from #Stores
select * from #ES
select * from #E
select #stores.storeid,#E.eid from #Stores
cross join #E
LEFT join #ES
on #ES.storeid = #Stores.storeid
and #E.eid = #ES.empid
where #E.imp = 1
and #ES.storeID is null
add a comment |
Please use Cross join followed by Left join and filter on IMP and StoreID null.
create table #Stores
(storeID int, Name varchar(100))
create table #ES
(empid int,storeID int)
create table #E
(eid int,employee varchar(100), imp int)
insert into #stores values(
1,'Store1'),
(2,'Store2'),
(3,'Store3')
insert into #ES values(
1,1),(2,1),(3,1),(1,2),(3,2)
insert into #E values
(1,'Cashier',1),
(2,'Manager', 1),
(3,'Guard',0)
select * from #Stores
select * from #ES
select * from #E
select #stores.storeid,#E.eid from #Stores
cross join #E
LEFT join #ES
on #ES.storeid = #Stores.storeid
and #E.eid = #ES.empid
where #E.imp = 1
and #ES.storeID is null
Please use Cross join followed by Left join and filter on IMP and StoreID null.
create table #Stores
(storeID int, Name varchar(100))
create table #ES
(empid int,storeID int)
create table #E
(eid int,employee varchar(100), imp int)
insert into #stores values(
1,'Store1'),
(2,'Store2'),
(3,'Store3')
insert into #ES values(
1,1),(2,1),(3,1),(1,2),(3,2)
insert into #E values
(1,'Cashier',1),
(2,'Manager', 1),
(3,'Guard',0)
select * from #Stores
select * from #ES
select * from #E
select #stores.storeid,#E.eid from #Stores
cross join #E
LEFT join #ES
on #ES.storeid = #Stores.storeid
and #E.eid = #ES.empid
where #E.imp = 1
and #ES.storeID is null
answered Nov 14 '18 at 8:52
WhoamIWhoamI
157119
157119
add a comment |
add a comment |
Try this query.
I assumed the table name of the "Employee" is dbo.Employee and table name of "Stores" is dbo.Stores and the intermediate table is "dbo.EmpStore"
SELECT S.StoreID, E.EmID
FROM dbo.Stores S
CROSS JOIN dbo.Employees E
LEFT JOIN dbo.EmpStore ES ON ES.EmID = E.EmID AND ES.StoreID = S.StoreID
WHERE E.Important=1 AND ES.EmID IS NULL
add a comment |
Try this query.
I assumed the table name of the "Employee" is dbo.Employee and table name of "Stores" is dbo.Stores and the intermediate table is "dbo.EmpStore"
SELECT S.StoreID, E.EmID
FROM dbo.Stores S
CROSS JOIN dbo.Employees E
LEFT JOIN dbo.EmpStore ES ON ES.EmID = E.EmID AND ES.StoreID = S.StoreID
WHERE E.Important=1 AND ES.EmID IS NULL
add a comment |
Try this query.
I assumed the table name of the "Employee" is dbo.Employee and table name of "Stores" is dbo.Stores and the intermediate table is "dbo.EmpStore"
SELECT S.StoreID, E.EmID
FROM dbo.Stores S
CROSS JOIN dbo.Employees E
LEFT JOIN dbo.EmpStore ES ON ES.EmID = E.EmID AND ES.StoreID = S.StoreID
WHERE E.Important=1 AND ES.EmID IS NULL
Try this query.
I assumed the table name of the "Employee" is dbo.Employee and table name of "Stores" is dbo.Stores and the intermediate table is "dbo.EmpStore"
SELECT S.StoreID, E.EmID
FROM dbo.Stores S
CROSS JOIN dbo.Employees E
LEFT JOIN dbo.EmpStore ES ON ES.EmID = E.EmID AND ES.StoreID = S.StoreID
WHERE E.Important=1 AND ES.EmID IS NULL
edited Nov 14 '18 at 8:56
answered Nov 14 '18 at 8:51
Thilina NakkawitaThilina Nakkawita
9211228
9211228
add a comment |
add a comment |
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You can do this by using CROSS JOIN and LEFT JOIN. Check my answer below
– Thilina Nakkawita
Nov 14 '18 at 8:57