Get substring from end to certain character in python [duplicate]
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This question already has an answer here:
How to get only the last part of a path in Python?
8 answers
I want to get the substring from a path from the end to a certain character, take for example the following path:
my_path = "/home/Desktop/file.txt"
My intention is to do something like:
my_path.substring(end,"/")
So I can get the name of the file that is located between the end of the string and the character "/", in this case "file.txt"
python string substring substr
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
marked as duplicate by Chris_Rands python
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Nov 16 '18 at 12:32
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
How to get only the last part of a path in Python?
8 answers
I want to get the substring from a path from the end to a certain character, take for example the following path:
my_path = "/home/Desktop/file.txt"
My intention is to do something like:
my_path.substring(end,"/")
So I can get the name of the file that is located between the end of the string and the character "/", in this case "file.txt"
python string substring substr
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
marked as duplicate by Chris_Rands python
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Nov 16 '18 at 12:32
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Have you had a look at theos.pathmodule, specifically theos.path.basenamefunction?
– Kendas
Nov 16 '18 at 12:30
Usepathlib.from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".
– erip
Nov 16 '18 at 12:33
add a comment |
This question already has an answer here:
How to get only the last part of a path in Python?
8 answers
I want to get the substring from a path from the end to a certain character, take for example the following path:
my_path = "/home/Desktop/file.txt"
My intention is to do something like:
my_path.substring(end,"/")
So I can get the name of the file that is located between the end of the string and the character "/", in this case "file.txt"
python string substring substr
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
This question already has an answer here:
How to get only the last part of a path in Python?
8 answers
I want to get the substring from a path from the end to a certain character, take for example the following path:
my_path = "/home/Desktop/file.txt"
My intention is to do something like:
my_path.substring(end,"/")
So I can get the name of the file that is located between the end of the string and the character "/", in this case "file.txt"
This question already has an answer here:
How to get only the last part of a path in Python?
8 answers
python string substring substr
python string substring substr
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
asked Nov 16 '18 at 12:27
L RodMrezL RodMrez
174
174
marked as duplicate by Chris_Rands python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.
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Nov 16 '18 at 12:32
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Chris_Rands python
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Nov 16 '18 at 12:32
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Have you had a look at theos.pathmodule, specifically theos.path.basenamefunction?
– Kendas
Nov 16 '18 at 12:30
Usepathlib.from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".
– erip
Nov 16 '18 at 12:33
add a comment |
Have you had a look at theos.pathmodule, specifically theos.path.basenamefunction?
– Kendas
Nov 16 '18 at 12:30
Usepathlib.from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".
– erip
Nov 16 '18 at 12:33
Have you had a look at the
os.path module, specifically the os.path.basename function?– Kendas
Nov 16 '18 at 12:30
Have you had a look at the
os.path module, specifically the os.path.basename function?– Kendas
Nov 16 '18 at 12:30
Use
pathlib. from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".– erip
Nov 16 '18 at 12:33
Use
pathlib. from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".– erip
Nov 16 '18 at 12:33
add a comment |
2 Answers
2
active
oldest
votes
The easiest approach, IMHO, would be to split the string:
filename = my_path.split('/')[-1]
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
add a comment |
use the os.path.basename for this
In [1]: import os
In [2]: os.path.basename('/home/Desktop/file.txt')
Out[2]: 'file.txt'
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The easiest approach, IMHO, would be to split the string:
filename = my_path.split('/')[-1]
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
add a comment |
The easiest approach, IMHO, would be to split the string:
filename = my_path.split('/')[-1]
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
add a comment |
The easiest approach, IMHO, would be to split the string:
filename = my_path.split('/')[-1]
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
The easiest approach, IMHO, would be to split the string:
filename = my_path.split('/')[-1]
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
answered Nov 16 '18 at 12:29
MureinikMureinik
187k22141206
187k22141206
add a comment |
add a comment |
use the os.path.basename for this
In [1]: import os
In [2]: os.path.basename('/home/Desktop/file.txt')
Out[2]: 'file.txt'
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
add a comment |
use the os.path.basename for this
In [1]: import os
In [2]: os.path.basename('/home/Desktop/file.txt')
Out[2]: 'file.txt'
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
add a comment |
use the os.path.basename for this
In [1]: import os
In [2]: os.path.basename('/home/Desktop/file.txt')
Out[2]: 'file.txt'
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
use the os.path.basename for this
In [1]: import os
In [2]: os.path.basename('/home/Desktop/file.txt')
Out[2]: 'file.txt'
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
answered Nov 16 '18 at 12:30
Albin PaulAlbin Paul
1,536819
1,536819
add a comment |
add a comment |
Have you had a look at the
os.pathmodule, specifically theos.path.basenamefunction?– Kendas
Nov 16 '18 at 12:30
Use
pathlib.from pathlib import Path; Path("/home/Desktop/file.txt").name == "file.txt".– erip
Nov 16 '18 at 12:33