Can I create a class from an object?












-2















for example, I use
Rectangle pinkSquare = FXMLLoader.load(Paths.get("layout", "Pink square.fxml").toUri().toURL())
created a Rectangle object. Can I make a class out of pinkSquare object, say PinkSquare and use it freely for create more objects?



I know I can use FXMLLoader to do this again, but can I create a class from pinkSquare anyway?










share|improve this question























  • instance.getClass()

    – Michael
    Nov 15 '18 at 11:53











  • What would you expect this classes functionality to be?

    – fabian
    Nov 15 '18 at 12:14











  • @Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

    – Chester
    Nov 15 '18 at 13:08











  • @fabian keep pinkSquare's state and save it as a subclass of Rectangle

    – Chester
    Nov 15 '18 at 13:10











  • @Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

    – Michael
    Nov 15 '18 at 13:11
















-2















for example, I use
Rectangle pinkSquare = FXMLLoader.load(Paths.get("layout", "Pink square.fxml").toUri().toURL())
created a Rectangle object. Can I make a class out of pinkSquare object, say PinkSquare and use it freely for create more objects?



I know I can use FXMLLoader to do this again, but can I create a class from pinkSquare anyway?










share|improve this question























  • instance.getClass()

    – Michael
    Nov 15 '18 at 11:53











  • What would you expect this classes functionality to be?

    – fabian
    Nov 15 '18 at 12:14











  • @Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

    – Chester
    Nov 15 '18 at 13:08











  • @fabian keep pinkSquare's state and save it as a subclass of Rectangle

    – Chester
    Nov 15 '18 at 13:10











  • @Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

    – Michael
    Nov 15 '18 at 13:11














-2












-2








-2








for example, I use
Rectangle pinkSquare = FXMLLoader.load(Paths.get("layout", "Pink square.fxml").toUri().toURL())
created a Rectangle object. Can I make a class out of pinkSquare object, say PinkSquare and use it freely for create more objects?



I know I can use FXMLLoader to do this again, but can I create a class from pinkSquare anyway?










share|improve this question














for example, I use
Rectangle pinkSquare = FXMLLoader.load(Paths.get("layout", "Pink square.fxml").toUri().toURL())
created a Rectangle object. Can I make a class out of pinkSquare object, say PinkSquare and use it freely for create more objects?



I know I can use FXMLLoader to do this again, but can I create a class from pinkSquare anyway?







java class object javafx






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 11:49









ChesterChester

32




32













  • instance.getClass()

    – Michael
    Nov 15 '18 at 11:53











  • What would you expect this classes functionality to be?

    – fabian
    Nov 15 '18 at 12:14











  • @Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

    – Chester
    Nov 15 '18 at 13:08











  • @fabian keep pinkSquare's state and save it as a subclass of Rectangle

    – Chester
    Nov 15 '18 at 13:10











  • @Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

    – Michael
    Nov 15 '18 at 13:11



















  • instance.getClass()

    – Michael
    Nov 15 '18 at 11:53











  • What would you expect this classes functionality to be?

    – fabian
    Nov 15 '18 at 12:14











  • @Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

    – Chester
    Nov 15 '18 at 13:08











  • @fabian keep pinkSquare's state and save it as a subclass of Rectangle

    – Chester
    Nov 15 '18 at 13:10











  • @Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

    – Michael
    Nov 15 '18 at 13:11

















instance.getClass()

– Michael
Nov 15 '18 at 11:53





instance.getClass()

– Michael
Nov 15 '18 at 11:53













What would you expect this classes functionality to be?

– fabian
Nov 15 '18 at 12:14





What would you expect this classes functionality to be?

– fabian
Nov 15 '18 at 12:14













@Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

– Chester
Nov 15 '18 at 13:08





@Michael I'm not trying to get the 'Rectangle' class, I wanna keep the state information of 'pinkSquare' and save it as a subclass of 'Rectangle'

– Chester
Nov 15 '18 at 13:08













@fabian keep pinkSquare's state and save it as a subclass of Rectangle

– Chester
Nov 15 '18 at 13:10





@fabian keep pinkSquare's state and save it as a subclass of Rectangle

– Chester
Nov 15 '18 at 13:10













@Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

– Michael
Nov 15 '18 at 13:11





@Chester You can't create classes at runtime*. You create instances of classes at runtime. (*well, technically you can, but you shouldn't)

– Michael
Nov 15 '18 at 13:11












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There's no built in way to do that but you could extend Rectangle class and create a method that returns a deep copy of it. However, that's just unnecessary work when you could just use FXMLLoader again, unless there's some significant performance gain from deep copying compared to loading the FXML, but I highly doubt that's the case.






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    1 Answer
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    1 Answer
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    active

    oldest

    votes









    0














    There's no built in way to do that but you could extend Rectangle class and create a method that returns a deep copy of it. However, that's just unnecessary work when you could just use FXMLLoader again, unless there's some significant performance gain from deep copying compared to loading the FXML, but I highly doubt that's the case.






    share|improve this answer




























      0














      There's no built in way to do that but you could extend Rectangle class and create a method that returns a deep copy of it. However, that's just unnecessary work when you could just use FXMLLoader again, unless there's some significant performance gain from deep copying compared to loading the FXML, but I highly doubt that's the case.






      share|improve this answer


























        0












        0








        0







        There's no built in way to do that but you could extend Rectangle class and create a method that returns a deep copy of it. However, that's just unnecessary work when you could just use FXMLLoader again, unless there's some significant performance gain from deep copying compared to loading the FXML, but I highly doubt that's the case.






        share|improve this answer













        There's no built in way to do that but you could extend Rectangle class and create a method that returns a deep copy of it. However, that's just unnecessary work when you could just use FXMLLoader again, unless there's some significant performance gain from deep copying compared to loading the FXML, but I highly doubt that's the case.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 11:58









        GnasGnas

        52829




        52829
































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