Compiling dict of users in Python for search results












0














I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



 user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details = {
'first' : 'error'
}
y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details = {
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
}
y = json.dumps(user_details)
return jsonify(y)


Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



EDIT:
what I really need help with is turning multiple structs like these:



    user_details = {
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
}


into one big struct like this:



        users = {
user_details1 = {
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
}
user_details2 = {
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
}
etc.
}









share|improve this question





























    0














    I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



     user = db.execute(
    'SELECT * FROM user WHERE email = ?', (emailInput,)
    ).fetchone()
    if user is None:
    user_details = {
    'first' : 'error'
    }
    y = json.dumps(user_details)
    return jsonify(y)
    if user['first'] is None:
    first = ""
    else:
    first = user['first']
    if user['email'] is None:
    email = ""
    else:
    email = user['email']
    if user['last'] is None:
    last = ""
    else:
    last = user['last']
    if user['address_line1'] is None:
    address_line1 = ""
    else:
    address_line1 = user['address_line1']
    if user['address_line2'] is None:
    address_line2 = ""
    else:
    address_line2 = user['address_line2']
    if user['username'] is None:
    username = ""
    else:
    username = user['username']
    user_details = {
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username
    }
    y = json.dumps(user_details)
    return jsonify(y)


    Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



    EDIT:
    what I really need help with is turning multiple structs like these:



        user_details = {
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username
    }


    into one big struct like this:



            users = {
    user_details1 = {
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username
    }
    user_details2 = {
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username
    }
    etc.
    }









    share|improve this question



























      0












      0








      0







      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details = {
      'first' : 'error'
      }
      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



          user_details = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }


      into one big struct like this:



              users = {
      user_details1 = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      user_details2 = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      etc.
      }









      share|improve this question















      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details = {
      'first' : 'error'
      }
      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



          user_details = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }


      into one big struct like this:



              users = {
      user_details1 = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      user_details2 = {
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username
      }
      etc.
      }






      python sql json






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      share|improve this question




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      edited Nov 13 '18 at 0:23

























      asked Nov 13 '18 at 0:01









      Japhy

      184




      184
























          2 Answers
          2






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          0














          Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






          share|improve this answer





























            0














            fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



            users = db.execute(
            'SELECT * FROM user WHERE email = ?', (emailInput,)
            ).fetchall()
            for user in users:
            if user['first'] is None:
            <etc>





            share|improve this answer





















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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






              share|improve this answer


























                0














                Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                share|improve this answer
























                  0












                  0








                  0






                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                  share|improve this answer












                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 0:08









                  rikAtee

                  4,77542956




                  4,77542956

























                      0














                      fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                      users = db.execute(
                      'SELECT * FROM user WHERE email = ?', (emailInput,)
                      ).fetchall()
                      for user in users:
                      if user['first'] is None:
                      <etc>





                      share|improve this answer


























                        0














                        fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                        users = db.execute(
                        'SELECT * FROM user WHERE email = ?', (emailInput,)
                        ).fetchall()
                        for user in users:
                        if user['first'] is None:
                        <etc>





                        share|improve this answer
























                          0












                          0








                          0






                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>





                          share|improve this answer












                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 13 '18 at 0:12









                          rd_nielsen

                          1,6152615




                          1,6152615






























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